OJ Board

Posted: **Sat Jan 18, 2003 1:33 pm**

I'm getting WA in this problem
what's wrong
is it my function checking?????

[c]

cut

[/c]

Posted: **Thu Jan 23, 2003 1:47 pm**

Read the problem carefully...

Your output "decodeable" should be "decodable", right ?

Regards,
Angga888

Posted: **Thu Jan 23, 2003 4:01 pm**

oh my god, how can I be this stupid

thx a lot angga
I get it acc now

you're a life saver

Posted: **Tue Apr 22, 2003 2:23 pm**

Help me please. I don't know what is wrong. I HATE THIS JUDGE!!!

Maybe u got some source.
[pascal]
program decoding;
var
a:array[1..9] of string[10];
i,j,k,l:byte;
b:string[10];
res:boolean;
function equ(a1,a2:string):boolean;
var i:byte;
res:boolean;
begin
res:=true;
for i:=1 to length(a2) do
res:=res and (a1=a2);
equ:=res;
end;
procedure mainloop;
var w1,w2:byte;
begin
while (k<i) and not(res) do
begin
inc(k);
j:=1;
while (j<=i) and not(res) do
begin
w1:=length(a[k]);
w2:=length(a[j]);
if (j<>k) and (w1<=w2) then
res:=res or equ(a[j],a[k]);
inc(j);
end;
end;
end;
begin
i:=0; l:=0;
while not eof(input) do
begin
readln(input,b);
if b='9' then
begin
k:=0; inc(l);
res:=false;
mainloop;
str(l,b);
if not(res) then
writeln(output,'Set '+b+' is immediately decodable')
else
writeln(output,'Set '+b+' is not immediately decodable');
i:=0;
end
else
begin
inc(i);
a:=b;
end;
end;
end.[/pascal]

Posted: **Wed May 07, 2003 12:11 pm**

Becareful the 'enter' can be appear everywhere.
I solve this problem by using function getchar, and if the character not '0' or '1', I ignore it.
The hardest of this problem is parsing input, and it always cause WA.

Consider the input can be like this:
0
1
1
0
0
010
00
0
0
9

Hope this helps.

Posted: **Sun Dec 11, 2005 9:03 am**

Hi,

could someone please give me some test inputs and outputs for problem 644? I've tried lots of tests and my algorithm seems correct but judge gave me WA. Are the constraints of the problem correct? (2-8 codes in each set with 1-10 bits) Thanks in advance!

Jeno

Posted: **Fri Dec 23, 2005 8:53 pm**

Just check the following test case...

Input:

Code: Select all

Output:

Code: Select all

Set 1 is not immediately decodable

Hope it works.

Posted: **Tue Jan 03, 2006 9:16 am**

Thanks for your test case, it helped!
Cases like 001 after 0010 weren't handled correctly, only 0010 after 001. Now I've got AC.

Jeno

Posted: **Fri Sep 12, 2008 3:38 pm**

need help...!!!

Code: Select all

#define foriz(i,n) for( i = 0 ; i < n ; i ++ ) 

bool immediately_decodable ( vecs cd )
{
 sort( cd.begin() , cd.end() );
 int i , j;
 foriz ( i , sz(cd) ) 
 {
  foriz ( j , sz(cd) )
  {
   if ( i != j && sz(cd[j]) >= sz(cd[i]) )
   {
    string x = cd[j].substr ( 0 , sz(cd[i]) );
    if ( x == cd[i] )
     return false;
   }
  }
 }
 return true;
}

int main ()
{
 int cas = 1;
 string s;
 while ( !feof(stdin) )
 {
  vecs codes;
  while ( true )
  {
   cin >> s;
   if ( s == "9" ) break;
   else codes.pb (s);
  }

  if ( immediately_decodable ( codes ) )
   printf ( "Set %d is immediately decodable\n" , cas ++ );
  else
   printf ( "Set %d is not immediately decodable\n" , cas ++ );
  codes.clear();
 }
 return 0;
}

anyone pls help me!!
thanks...

Posted: **Fri Dec 05, 2008 5:59 am**

What is the termination condition of this problem?
No, such type of terination condition.I am getting TLE because of this.Pls, inform

Posted: **Thu May 28, 2009 9:32 pm**

Hello tanvir_cse

U have to read the input upto end of file.
and when u get 9 u will print result

take input like that

while(scanf(" %s", code[num]) == 1)
{
while(1)
{
if (code[num][0] == '9') break;
scanf(" %s", code[++num]);
}
//some code here;
}

Posted: **Wed Oct 28, 2009 11:15 pm**

getting WA.can anyone please help?

Code: Select all

#include<stdio.h>
#include<string.h>
int main(){

  int a,b=0,d,e,f,x,y,z,bi[9][10],l,len[10],zz=1,aa,p,q;
  char c,m[11];
  while(gets(m)){
    
    l=strlen(m);
    len[b]=l;
    
    for(a=0;a<l;a++)
    bi[b][a]=m[a]-48;
    b++;
    if(m[0]!='9')
    continue;
    
    
    p=0;q=0;
  
    for(e=0;e<b;e++){
      for(f=e+1;f<b;f++){
       if(len[e]<len[f]){
          for(a=0;a<len[e];a++){
            if(bi[e][a]!=bi[f][a])
            break;
      
          }
        }
        if(a==len[e]){
   
        p++;
          break;
        }
      }
      if(a==len[e])
      break;
    }
    for(e=b-1;e>=0;e--){
      for(f=e-1;f>=0;f--){
       if(len[e]<len[f]){
         
          for(aa=0;aa<len[e];aa++){
            if(bi[e][aa]!=bi[f][aa])
            break;
          }
        }
        if(aa==len[e]){
    
        q++;
          break;
        }
      }
      if(aa==len[e])
      break;
    }
    if((p>0)||(q>0)){
      p=0;q=0;
      printf("Set %d is not immediately decodable\n",zz);
      zz++;
      b=0;
      continue;
    }
      
    
    if((p==0)&&(q==0)){
    printf("Set %d is immediately decodable\n",zz);
    zz++;
    b=0;
  }
  }
  return 0;
}

Posted: **Mon Feb 24, 2014 9:47 am**

fahim_xubayer wrote:getting WA.can anyone please help?

Try the following input:

Code: Select all

01
01
9

AC Output:

Code: Select all

Set 1 is not immediately decodable

Posted: **Mon Feb 24, 2014 9:48 am**

Jan wrote:Just check the following test case...

Thanks for sharing this great test case!

OJ Board

644 - Immediate Decodability

644 - Immediate Decodability

644

644 - WA

644 - Immediate Decodability ..Getting WA

644 - Immediate Decodability : TERMINATION CONDITION

Re: 644 - Immediate Decodability : TERMINATION CONDITION

Re: 644 - Immediate Decodability

Re: 644 - Immediate Decodability

Re: