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Problems input
Posted: Wed Nov 14, 2012 7:37 pm
by DiegoTrivino
If I have the following entry:
2
1
-1 0
-5 -3
2 5
0 0
1
-1 0
0 1
0 0
should read as java?? with a variable BufferedReader and readLine () method and read line by line? or just read a single line in the following format:
2 \ n \ n1 \ n-1 0 \ n-5 -3 \ n2 5 \ n0 0 \ n \ n1 \ n-1 0 \ n0 1 \ n0 0
Re: Problems input
Posted: Thu Nov 15, 2012 1:43 am
by brianfry713
Which problem number?
Re: Problems input
Posted: Sun Nov 18, 2012 4:40 pm
by DiegoTrivino
I read only one line?
2 \ n \ n1 \ n-1 0 \ n-5 -3 \ n2 5 \ n0 0 \ n \ n1 \ n-1 0 \ n0 1 \ n0 0
or should I read several lines?
2
1
-1 0
-5 -3
2 5
0 0
1
-1 0
0 1
0 0
Re: Problems input
Posted: Mon Nov 19, 2012 11:47 pm
by brianfry713
I'm not sure I understand what you're asking. On some problems it is best to parse the input line by line, on others you should read an int at a time.
Re: Problems input
Posted: Tue Dec 04, 2012 4:29 am
by DiegoTrivino
Thanks, I was able to fix the problem, but now I have a new problem with the entry:
if not tell me which is the termination condition, as I know I'll finish the entry?
Re: Problems input
Posted: Sat Dec 08, 2012 5:42 am
by brianfry713
I can't tell you how to parse the input without a problem description.
Re: Problems input
Posted: Thu Jun 27, 2013 7:11 pm
by Hikari9
if you're asking about reading such input terminated by blank lines, that will work even if the last line has NO blank line, just check if the line read is a null string.
sample code:
Code: Select all
import java.util.*;
import java.io.*;
public class Main{
public static void main( String args[] ) throws IOException{
BufferedReader br = new BufferedReader( new InputStreamReader( System.in ) );
String in;
int n = Integer.parseInt( br.readLine() );
br.readLine(); // ignore first blank line
while( n-- != 0 ){
while( ( in = br.readLine() ) != null ){ // will always work even if EOF
// do stuff here
}
}
}
}