## 10066 - The Twin Towers

All about problems in Volume 100. If there is a thread about your problem, please use it. If not, create one with its number in the subject.

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ahanys
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### 10066 - The Twin Towers

I think that i solve this probl em correctly.
I find the longest common subsequence. May be there any numbers that are longer than "long long int".

for example:
in:
2 3
1 2
2 3 4

out:
Twin Towers #1
Number of Tiles : 1

in2
1 2
1
2 3

out2:
Twin Towers #2
Number of Tiles : 0

Is there any error in my input/output.

Thank.

My program is here:

#include <stdio.h>
void nuluj(long long m,long long n, long long p[]) {
for (long i=0; i<=m; i++)
for (long j=0; j<=n; j++)
p[j]=0;
}

long long pole;
int main() {
long long z=0;
long long m,n;

long long a,b;

scanf("%lli %llin",&m,&n);
while (m!=0&&n!=0) {
z++;
for (long i=1; i<=m; i++) scanf("%lli",&a);
for (long k=1; k<=n; k++) scanf("%lli",&b[k]);
nuluj(m,n,&pole);

for (long j=1; j<=m; j++) {
if (a[j]==b) pole[j]=1;
}

for (long r=2; r<=n; r++)
for (long s=1; s<=m; s++) {
if (a[s]==b[r]) {pole[r][s]=pole[r-1][s-1]+1;}
else {
if (pole[r-1][s]>pole[r][s-1]) pole[r][s]=pole[r-1][s];
else
pole[r][s]=pole[r][s-1];
}
}

printf("Twin Towers #%llin",z);
printf("Number of Tiles : %llinn",pole[n][m]);
scanf("%lli %llin",&m,&n);
}

return 0;
}
cyfra
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Posts: 144
Joined: Thu Nov 22, 2001 2:00 am
Location: Gdynia, Poland
Hi!

I couldn't find an error in your program...

Try to make only one dimensional array..

It is quite simple...

I have also tested it a lot but I found nothing...

Maybe you will try to write this task again??

Good Luck Ps.
I have realized that after "0 0" your program is still waiting for the key...

Maybe this is the bug..
ahanys
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I get accepted. But i don't kow in what an error was. Thanks pitfall
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### 10066 Twin Towers, Problem statement wrong!

The problem states :

the Emperor ordered his architects to remove some of the tiles from the
two towers so that they have exactly the same shape and size,
and at the same time remain as high as possible.

So the towers should be as high as possible not necessirily containing
most number of tiles.

consider the input

5 5
10 10 10 10 500
500 10 10 10 10

the tallest tower is 500 high ( actually 500 x 2 ) but containg 1 tile
the tower containing most number of tile is 4 but 40 high.

so should the answer be 1 or 4 ?
the judge accepts 4.
Ustaad
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Joined: Tue Feb 05, 2002 2:00 am

### Read Question Carefully

Hi

The question says the tiles have the same heights and the input provides the radii of the tiles, not the heights !

Ustaad
pitfall
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### thanks

You are right Thanks
slavej
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### 10066 ?????? Why WA.

I'm using LCS here but it doesn't work. WHY??

[c]#include <stdio.h>

int main(void)
{
int common;
int a,b;
int i,j,m,n, counter = 0;

scanf("%d%d",&n,&m);
while((n > 0) || (m > 0))
{
++counter;

for (i = 0; i <= 100; ++i)
for (j = 0; j <= 100; ++j)
common[j] = 0;
for (i = 1; i <= n; ++i)
scanf("%d", &a);
for (i = 1; i <= m; ++i)
scanf("%d", &b);

for (i = 1; i <= n; ++i)
for (j = 1; j <= m; ++j)
if (a == b[j])
common[j] = common[i-1][j-1] + 1;
else
if (common[i-1][j] > common[j-1])
common[j] = common[i-1][j];
else
common[j] = common[j-1];

printf("Twin Towers #%d\n",counter);
printf("Number of Tiles : %d\n",common[n][m]);

scanf("%d%d",&n,&m);
if (n)
printf("\n");
}

return(0);
}
[/c]
titid_gede
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Posts: 187
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Location: Mount Papandayan, Garut
i didnt see your code is wrong, and i submitted your code and AC without changing anything.
Kalo mau kaya, buat apa sekolah?
midra
Experienced poster
Posts: 119
Joined: Fri Feb 13, 2004 7:20 am
Contact:

### 10066 (twin towers) WA!

Hi!
I get WA in this problem over and over and over...
I don't know WHY!!
here is my code:

[c]
#include <stdio.h>

int lcs(int tn1[],int tn2[],int n1,int n2){
int i,j; /*counters*/
int x,t;
int lcs=0,temp=0;
for (t=1;t<=n1;t++){
x=1;
for (i=t;i<=n1;i++)
for (j=x;j<=n2;j++)
if (tn1==tn2[j]){
temp++;x=j+1;
break;
}
if (temp>lcs) lcs=temp;

temp=0;
}
printf("%d\n\n",lcs);

}

int main()
{
int n1,n2; /*towers*/
int i; /*counter*/
int tn1; /*tiles of n1*/
int tn2; /*tiles of n2*/
int cases=1;
while(scanf("%d %d",&n1,&n2)){
if (n1==0 && n2==0)
break;
for (i=1;i<=n1;i++)
scanf("%d",&tn1);
for (i=1;i<=n2;i++)
scanf("%d",&tn2);
printf("Twin Towers #%d\nNumber of Tiles : ",cases);
cases++;
lcs(tn1,tn2,n1,n2);
}
return 0;
}[/c]

Maybe I missunderstood the problem, or maybe there is some special cases that my code doesn't pass....
if someone could help I would appreciate very much
sohel
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Posts: 856
Joined: Thu Jan 30, 2003 5:50 am
Location: New York

### lcs not right

You did not misunderstand the problem.. it is a LCS problem...

.. but your LCS function does not seem to be right. And from the look of your algorithm it seems to have a complexity of N^3.. but LCS can be implemented with N^2...

Here is the modified function which got AC.

[c]
int max(int a, int b) {
if( a < b)
return b;
return a;
}

int lcs(int tn1[],int tn2[],int n1,int n2){
int i,j; /*counters*/

int dp;

for(i=0;i<=n1;i++)
dp = 0;
for(i=0;i<=n2;i++)
dp = 0;
for(i=1;i<=n1;i++)
for(j=1;j<=n2;j++) {
if( tn1 == tn2[j] ) {
dp[j] = dp[i-1][j-1] + 1;
}
else dp[j] = max(dp[i-1][j], dp[j-1]);
}

printf("%d\n\n",dp[n1][n2]);
return 0;

}
[/c]

Hope it helps. midra
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Posts: 119
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Contact:
thank you so much Sohel!!!!   I really appreciate...
but...can you (or someone else) explain me a little more why it works fine this implementation????

thanks!!!!
Pavel Nalivaiko
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Posts: 15
Joined: Sun Mar 07, 2004 7:47 pm
Location: Moscow, Russia

### 10066 (Twin Towers) - Why WA??????

I used simple DP-based algorithm to find LCS. Everything seems to be OK, but I've got WA.

[pascal]
Type Integer = LongInt;
Const MaxN = 100;
Var A, B : Array[1..MaxN] Of Integer;
N, M : Integer;
D : Array[0..MaxN, 0..MaxN] Of Integer;

Function Load : Boolean;
Var I : Integer;
Begin
Load:=False;
Read(N, M);
If (N=0) And (M=0) Then Exit;
Load:=True;
For I:=1 To N Do Read(A);
For I:=1 To M Do Read(B);
End;

Function Max(A, B : Integer):Integer;
Begin
If A>B Then Max:=A Else Max:=B;
End;

Function Get(I, J : Integer):Integer;
Var Res : Integer;
Begin
If D[I, J]<0 Then Begin
If A=B[J] Then Res:=1+Get(I-1, J-1)
Else Res:=Max(Get(I-1, J), Get(I, J-1));
D[I, J]:=Res;
End;
Get:=D[I, J];
End;

Procedure Solve;
Var I, J : Integer;
Begin
For I:=0 To N Do
For J:=0 To M Do
D[I, J]:=-1;
For I:=0 To N Do D[I, 0]:=0;
For I:=0 To M Do D[0, I]:=0;
Get(N, M);
End;

Procedure Save(Iter : Integer);
Begin
Writeln('Twin Towers #', Iter);
Writeln('Number of Tiles = ', D[N, M]);
End;

Var Iter : Integer;
Begin
Iter:=0;
While Load Do Begin
Inc(Iter);
Solve;
Save(Iter);
Writeln;
End;
End.
[/pascal]

I know, that this algorithm could be implemented with classical DP, instead of recursive memorization, but I wan to know WHAT IS WRONG IN THIS CODE?

If anybody could help me?
little joey
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Posts: 1080
Joined: Thu Dec 19, 2002 7:37 pm
Carefully compare the output from your program with the sample output ... notice any difference? Pavel Nalivaiko
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Posts: 15
Joined: Sun Mar 07, 2004 7:47 pm
Location: Moscow, Russia
little joey wrote:Carefully compare the output from your program with the sample output ... notice any difference? OK - I fixed the excess blank line in the end of my output file, by changing the main part for this
[pascal]
Var Iter : Integer;
First : Boolean;
Begin
Iter:=0;
First:=True;
While Load Do Begin
If First Then First:=False Else Writeln;
Inc(Iter);
Solve;
Save(Iter);
End;
End.
[/pascal]

But still WA..
May be I am a bit of idiot - but I don't see any other difference..
Pavel Nalivaiko
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Posts: 15
Joined: Sun Mar 07, 2004 7:47 pm
Location: Moscow, Russia
Oh, I understand I used a pdf-version of this problem, in wich the symbol '=' is used instead of ':' 