OJ Board

What does

In case the analysed string does not determine the experiment result, a first match from the above list should be outputted.

mean?

Thank You

Hi!

It means that for this input :

19035

You should output:

-

because the negative result is before not completed experiment...

And that's all...

Good Luck

What if you have something like "12345".

Thank You

Hi!

My program returs '-' but I think that there shouldn't be such a case in the input, because it describes nothing....

and what your program gives ??

So what do we do in the default case?

Larry wrote:So what do we do in the default case?

What do you mean ??

In the input which is given in task description everything is OK...

Hi,

U're right for the '+' sign but nop the others. Read the question carefully.

[cpp]
'-' for a[strlen(a) - 2] = "35"
'*' for a[0] = '9' and a[strlen(a) - 1] = '4'
'?' for a[0-2] = "190"
[/cpp]

-novice

The problem is simple, but I cannot get AC.
I've tested. There's no illegal case in input.
Are there any tricks?

And there's my program.

[cpp]#include <fstream.h>
#include <string.h>

//ifstream fin("621.txt");
#define fin cin
#define endl '\n'

char str[1000000];

main() {
int cases, pcase;
fin >> cases;
for (pcase = 0; pcase < cases; pcase++) {
fin >> str;
if (strcmp(str, "1") == 0 || strcmp(str, "4") == 0 || strcmp(str, "78") == 0) {
cout << "+" << endl;
continue;
}
int l = strlen(str);
if (l >= 2 && str[l - 1] == '5' && str[l - 2] == '3') {
cout << "-" << endl;
continue;
}
if (str[0] == '9' && str[l - 1] == '4') {
cout << "*" << endl;
continue;
}
if (l >= 3 && str[0] == '1' && str[1] == '9' && str[2] == '0') {
cout << "?" << endl;
continue;
}
cout << endl;
}

return 0;
}[/cpp]

To get AC, there should be no EOLN after the last line of output... but I don't think it is right

Never mind...

there was a thread about this problem.
look at this ....

Regards
Dominik

what should be the output of the following input:

190135

please anyone tell me the reasult?
M H

I think "-"

Best regards
DM

Thanks for help.

I made so but why is there any think is in the qustion????????

thanks
M H

Well I think so, it's very stupid!!!!