OJ Board

#include<iostream.h>

int main()
{
double h,u,d,f;
while(cin>>h>>u>>d>>f&&h>0)
{
double ih=0;
double hc=ih+u;
double hs=hc-d;
double fa=(u*f)/100.00;
long day=1;
int a=0,b=0;
do
{
ih=hs;
u-=fa;
if(u>=0)
{
hc=ih+u;
}
else hc=ih;
hs=hc-d;
day++;

if(hs<0||hc>=h)b=1;
if(hs<0)a=1;

}while(b!=1);
if(a==0)
cout<<"success on day "<<day<<"\n";
else
cout<<"failure on day "<<day<<"\n";
}
return 0;
}

Pls specify the number of this problem

Good Luck

Thanks for reply.
The number of this problem is 573.

try these inputs:
10 3 4 14
1 9 4 46

first will fail on the first day (not second), second will fail too, because it only reaches the top, but doesn't "exceed the height of the well".

sorry the previous second sample was a mistake. it's successful on the first day.
here is the input for just missing to exceed the height of the well:
9 8 1 75

Yes it got accepted.
Thanks for your reply.

I can't why i have done the wrong. I think my algorithm is ok. Can anybody help me with any typical data.Here is my code:
#include <stdio.h>
#include <stdlib.h>

getData(char *str);
void calculate(int height, int climb, int slide, int fatigue);
int pos;

main(){
char buff[101];
int height, climb, slide, fatigue;

while(1){
pos = 0;
gets(buff);
height = getData(buff);
if (!height)
break;
climb = getData(buff);
slide = getData(buff);
fatigue = getData(buff);
calculate(height,climb,slide,fatigue);

}
return 0;
}

getData(char *str){

int i,j;
char valstr[4];
int value;

for (j = 0,i = pos;((str[i] != ' ') && (str[i] != '\0')) ;i++,j++){
valstr[j] = str[i];
}
valstr[j] = 0;
pos = i + 1;
value = atoi(valstr);
return value;

}
void calculate(int height, int climb, int slide, int fatigue){
int day = 1;
float total = 0.0;
float dayclimb, decline;

decline = (float)(climb)*fatigue/(float)100;
dayclimb = (float)climb;
while(1){
dayclimb = (float)(climb) - (day - 1)*decline;
total += dayclimb;
if (total > (float)(height)){
printf("success on day %d\n",day);
break;
}
else
total -= (float)(slide);
if (total < 0.0){
printf("failure on day %d\n",day);
break;
}
day++;
}
}
/* @END_OF_SOURCE_CODE */

Have you searched the Volume V for a thread about this problem? There should be one about it and the content can answer your question.

Please searched the forum before posting question.

Woubld you please explain what do you mean by searching thread about this problem? As a new programmer it is unknown to me.

Anybody can tell me where my mistake is? This problem REALLY REALLY drives my crazy !!!!!!!!!!!

Here's my code

[c]#include<stdio.h>
int i;
int s,h,u,f,d;
void main(){
while(1){
scanf("%i %i %i %i",&h,&u,&d,&f);
if(h==0){break;}
h*=100;u*=100;d*=100;
for(i=1,s=0,f*=(u/100);;i++){
s+=u;
if(s>h)break;
s-=d;
if(s<0)break;
u-=f;
}
if(s>0) printf("success on day %i\n",i);
else printf("failure on day %i\n",i);
}
}[/c]

Thanks

Although the problem says that all input will be integer, but the intermediate values can be floating point.
Since all of your data types are intger, your program will never store any intermediate floating point value.

Try considering all input as floating point value.

In the problem description there is:

If the fatigue factor drops the snail's climbing distance below zero, the snail does not climb at all that day.

So you should change:
[c] u-=f; [/c]
to:
[c]
u -= f;
if (u < 0) u = 0;
[/c]

Thanks to both of you.
I got AC now!!
God bless you

shamin, szymcio2001, keep posting!.

Yahoo,
You said:

dayclimb = (float)(climb) - (day - 1)*decline;
total += dayclimb;

What if (day-1)*decline<0? It says the snail never climbs a negative distance. So if(dayclimb<0) dayclimb=0;should solve it.
I haven't checked your code thoroughly, but 2 more traps:
1. The snail has to exceed the height of the well, not equal it.
2. The height of the snail has to be less than, not equal to 0.

And searching the thread means clicking the search button next to the faq button on the top of this page. But you knew that probably, seeing you have so many posts.