12578 - 10:6:2

[Nut_Boltu]

i m getting WA!!!.
plz Help.

#include<cstdio>
#include<cmath>
int main()
{
int T,L;
double redArea,greenArea;
scanf("%d",&T);
while(T--)
{
scanf("%d",&L);
int r=L/5;
int W = L*6/10;
redArea=acos(-1)*pow(r,2);
greenArea=L*W-redArea;
printf("%.2lf %.2lf\n",redArea,greenArea);
}

return 0;
}

[brianfry713]

Think about what your code is doing when L is not a multiple of 5.

[Nut_Boltu]

thanks.... ACC.

[alimbubt]

Input:

Code: Select all

10
33
10
20
30
40
50
60
70
80
97

Output:

Code: Select all

136.85 516.55
12.57 47.43
50.27 189.73
113.10 426.90
201.06 758.94
314.16 1185.84
452.39 1707.61
615.75 2324.25
804.25 3035.75
1182.37 4463.03

[gr81]

really stuck at stupid problem....my code is at http://ideone.com/9fSszm
please help.

[lbv]

really stuck at stupid problem....my code is at http://ideone.com/9fSszm
please help.

Use double variables, instead of floats. Check for example:

Input

Code: Select all

2
1000
775

Output

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125663.71 474336.29
75476.76 284898.24

[gr81]

thanks, never thought it will screw me like this.

[a.a.tanim]

i m getting WA!!!.
plz Help.



#include<stdio.h>
#include<math.h>
#define PI acos(-1)
int main()
{
double a,r;
unsigned n,i,l;
scanf("%u",&n);
for(i=1;i<=n;i++)
{
scanf("%u",&l);
r=PI*(l/5)*(l/5);
a=(6*(l*l))/10;
printf("%.2lf\t%.2lf\n",r,a-r);
}
return 0;
}

[brianfry713]

Think about what your code is doing when L is not a multiple of 5.

[mpmohi]

I just can't see the problem of this code ....can you

Code: Select all

Got the solution 

[brianfry713]

#include <math.h>
try using M_PI instead of your pi constant

[Shahidul.CSE]

Why WA?

Code: Select all

Removed after Accepted

[lighted]

Your code is accepted code.
Problems with copy/paste?

[Shahidul.CSE]

Thank you. Accepted!

[sabbir25112]

What's the problem with my code.?? why it's not accepted.
anyone can help plz.

Code: Select all

#include<stdio.h>
#include<math.h>
#define PI acos(-1)
int main()
{
    int test,i;
    float l,w,r;
    while(scanf("%d",&test)==1)
    {
        for(i=1;i<=test;i++)
        {
            scanf("%f",&l);
            w = 0.6*l;
            r = l/5;
            printf("%.2f %.2f\n",PI*r*r,(l*w)-(PI*r*r));
        }
        }
    return 0;
}