10248 - The Integer All-time Champ

[ante]

Hi !
is this correct string length for these three inputs

1 99 ===> length is 99
30 80 ===> length is 76
1 50 ===> length is 66

[Ustaad]

Hi

My "Accepted" solution gives a 65-length solution for the case 1 50.

1 50
11012013014019494847394629452844383736273526251834241733231622150

I think the other inputs give correct solutions.

Hope this helps !:)

Ustaad

[Google]

I think this is a truly special problem.
Can anybody give some hints about it?
I really have no idea about how to solve it, should I use greedy method or search?
Or is there any special algorithm for it?

[Adrian Kuegel]

You can solve it with a kind of greedy. It has something to do with the number of digits you can append at the beginning of a string to build a new unused number.

[Fred]

I have tryed solving this problem with a simple algortithm.

- I verify if the number is already on the lis
- if not, i add it using the minimum number of algarisms possible.

It was wrong...
The mistake is not relationed to multiple inputs.

With 1 99 as argument, it generates the following string:

998897796695594493392291190878685848382818076757473727170656463626160545352515043424140323130212010

It has 99 algarisms.

I don

[Emilio]

Hello there!

I have tried this problem and have got a lot of WAs. I have maked 5 different codes, the main strategy is search a number didn't use even in the list of numbers, this number is linked with other digits to make new numbers haven't used even, and then all these pieces are linked, I only search to make numbers of two digits, when all the two digits number are maked then I add the 1 digit numbers lacked. This is a brief explanation, I have maked some different codes as already said. In other approachs I add digits to one unique piece, over this I build the whole list of digits and I add at the begining and at the end. I have tried these methods in a lot of different ways, and with different ways to search and to start (with some number each time), and get the same results.
My method is a bit of greedy like.
Could anyone give me some good hint, method or some input/output?

Thanks in advance!

[Emilio]

Finally I got AC.
A small mistake in my code .
Thanks to http://public.carnet.hr/~icanadi/acmcheck/index.php I found easily my mistake!

[lord_burgos]

INPUT

Code: Select all

11 11
11 12
21 31

My AC Output

Code: Select all

11
112
22123024252627282931

[brianfry713]

Something is wrong with the input, this code returns RE

Code: Select all

#include <stdio.h>

int main(void) {
  int m, n;
  while(scanf("%d%d", &m, &n)==2)
    if(m<=0||m>n||n>=100) return 1;
  return 0;
}

Anyone who can get AC, how do you handle input parsing? What about the cases where m<=0, m>n, or n>=100?

[yleewei]

Yep @brianfry713, your code is still judged RE when I try to submit it too.

[brianfry713]

I made a few more submissions, and I believe there is a case where m<0 and a case where m>n. There is not a case where n>=100.
I haven't been able to get AC.

[brianfry713]

The judge's I/O has been fixed.