10106 - Product

[uDebug]

Replying to this thread so I can follow it. Thanks.

[Rika71]

why WA??? please help.thanks in advance

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Removed after AC

[uDebug]

why WA??? please help.thanks in advance

So, couple things

(1) Use code tags to make your code more readable.
(2) Change

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while(scanf("%s%s",&s1,&s2)==2)

to

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while(scanf("%s%s",s1,s2) != EOF)

(3) Change

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int main(void)

to

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int main()

(4) Move

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char s1[1000],s2[1000],s3[40000][40000],s4[100000];

inside main.
(5) Try running your code on the sample input. It's generally a good idea to do so before submitting your program. Your code seg faults.

[brianfry713]

v1n1t,

See:
http://www.cplusplus.com/reference/cstdio/scanf/
I prefer using:
while(scanf("%s%s", s1, s2) == 2)
instead of:
while(scanf("%s%s", s1, s2) != EOF)
Try this input to see the difference:

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1 2 3

Your third point is equivalent and just a matter of style.

Large arrays should be declared globally, static, or dynamic so they go on the heap instead of the stack. Rika71, why does s3 need to be that large?

[uDebug]

See:
http://www.cplusplus.com/reference/cstdio/scanf/
I prefer using:
while(scanf("%s%s", s1, s2) == 2)
instead of:
while(scanf("%s%s", s1, s2) != EOF)

Gotcha. Thanks for sharing. I didn't know this.

Try this input to see the difference:

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1 2 3

Will do.

Your third point is equivalent and just a matter of style.

Again, thank you for teaching me.

Large arrays should be declared globally, static, or dynamic so they go on the heap instead of the stack.

Agreed.

But for some reason, I couldn't get Rika71's code to compile unless I moved those arrays onto the stack. Could you compile and run as they posted it on the forum? If so, what did you do?

Thanks again for all the pointers.

[brianfry713]

On my machine, Rika71's code compiles and runs on the sample input correctly as he or she wrote it. What was your compile error v1n1t? Were you not able to allocate enough memory for s3? However if I move those large arrays inside of main then I get a seg fault on execution.

Try input:

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1063805700
972401858

Output should be:

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1034446639230990600

[uDebug]

See:
http://www.cplusplus.com/reference/cstdio/scanf/

I did look at this but found no mention of what the "2" (specifically) is for. Is this related to the line?

On success, the function returns the number of items of the argument list successfully filled.

So, if we were reading in 3 inputs, for example, we'd replace the "2" by "3"?

I prefer using:
while(scanf("%s%s", s1, s2) == 2)
instead of:
while(scanf("%s%s", s1, s2) != EOF)
Try this input to see the difference:

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1 2 3

OK. I got around to doing this. Here's what I wrote as a test

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#include<bits/stdc++.h>

using namespace std;

#define SIZE 1000

int main() {
	
	char s1[SIZE], s2[SIZE];

	while(scanf("%s%s", s1, s2) != EOF) {
		printf("s1: %s and s2: %s\n", s1, s2);
	}

	return 0;
}

When I ran this code on the input you provided, it output

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s1: 1 and s2: 2
s1: 3 and s2: 2

I have no idea why.

However, the same code with the while loop line replaced per your preference, it output

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s1: 1 and s2: 2

which is what I'd expected the first piece of code to do. So now, I'm confused.

On my machine, Rika71's code compiles and runs on the sample input correctly as he or she wrote it.

Oh great. Thanks for sharing.

What was your compile error v1n1t? Were you not able to allocate enough memory for s3?

So, the code compiles and builds fine. But when I run it on the following (sample) input

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12
12
2
222222222222222222222222

I get the following mysterious message

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Killed

And nothing more at all. Not sure what's going on.

[brianfry713]

Yes, see the return value of scanf:
On success, the function returns the number of items of the argument list successfully filled. This count can match the expected number of items or be less (even zero) due to a matching failure, a reading error, or the reach of the end-of-file.
If a reading error happens or the end-of-file is reached while reading, the proper indicator is set (feof or ferror). And, if either happens before any data could be successfully read, EOF is returned.

If you're reading two strings at a time using scanf and the input has an even number of strings, then testing for a return value of two or not EOF will have the same result. However in the case of an odd number of strings, the last call to scanf will return 1 and the second string is unchanged.


Your machine is probably Killing that code because of the memory it's trying to allocate:
char s3[40000][40000] alone is 1,600,000,000 bytes.

[Rika71]

On my machine, Rika71's code compiles and runs on the sample input correctly as he or she wrote it. What was your compile error v1n1t? Were you not able to allocate enough memory for s3? However if I move those large arrays inside of main then I get a seg fault on execution.

A profusion of thanks to brianfry713.
I just fixed my code for your sample & got AC.
[by the way I am he ]