OJ Board

[cpp]
This is my C++ answer for 113.
I got WA. However, I don't understand why. I thought it perfectly solves the problem. Can anyone help me?
#include <iostream>
#include <cmath>

using namespace std;

int main()
{
double n, k, p;

while (cin >> n >> p)
{

k = pow(p,(1/n));
cout << k << endl;
}
return 0;
} [/cpp]

Hi, I corrected the following line and got AC.

[cpp]cout << k << endl;[/cpp]

Most probably the default number digit after decimal is 6, so in UVA compiler your ans. for
2
16
would be
4.000000 and not 4.

Change it to the following line.
[cpp]printf("%.0lf\n",k); [/cpp]

Thanks for your reply.
I corrected the line and sent it. However, I got following compiler errors.
Also, when I run it on VC, I get no error but the output is funny. I mean, this doesn't solve the problem.
So if you have any thought on that, I appreciate it.
02143378_24.c: In function `int main ()':
02143378_24.c:14: `printf' undeclared (first use this function)
02143378_24.c:14: (Each undeclared identifier is reported only once for
each function it appears in.)

the library iostream used by the judge's compiler doesn't support the printf function, so you have to include another library ( stdio.h )

I hope it helped you

Thanks everyone. It worked.
But like how did you know that their compiler interpret it down to 6 decimal points and stuff like that?
Just out of curiosity.

I guess experience would be the greatest teacher in that case.

help me~~ plz~~

[cpp]
#include <iostream.h>
#include <math.h>
int main(void)
{
double p,n;
while(cin>>n>>p) {
cout<<pow(p,(double)1/n)<<endl;
}
return 0;
}[/cpp]

1<=p<10^101

I think that double not support so big numbers.

No, double is enough. I have a similar solution, but with two more lines at the begining of the main function:
[cpp] cout.setf(ios::fixed);
cout.precision(0); [/cpp]
I don't remember why I put them there, but there must have been a reason

Krzysztof Duleba wrote:No, double is enough. I have a similar solution, but with two more lines at the begining of the main function:
[cpp] cout.setf(ios::fixed);
cout.precision(0); [/cpp]
I don't remember why I put them there, but there must have been a reason

I fix the code
[cpp] cout<<(long)pow(p,(double)1/n)<<endl [/cpp]
and some answers will be decrease like 1234->1233
so i think the answers' form i calculate are wrong......

So you finally got accepted?

Oh!!yes....~~thank you~~

i am trying to use the double data type but if i input a number having more than say 20 digits and then just print it ( no processing ) , i am not getting the same number that i had entered. after 20 digits the precision is lost.
could anyone pls suggest why it is so?

p.s. i have even tried long double

Your code is too much complex i think- the problem is not so much complex.

I got WA with double but AC with Long Double.

I used natural log instead of base 10.

k = exp(log(p)/n) is enough to solve it.

best of luck

I used double and got AC.

I think, the judge's data has no such case where precision will be lost.