OJ Board

Thanks for the suggestion though knew it already. It is obvious that if a funciton is overloaded for some types and I am passing a value of other type, then I should type cast. But, I did not ask what I should do when I get this message.

I see that math functions of judge's compiler are overloaded ( when I use <cmath> ). Should they be ? As C math functions are inherited as they were, they should not have been overloaded as they were not. I do not also see any specification by TC++PL stroustrup. Then why are they overloaded ?

So, exactly what I want to know is why they overload them. Is there any standard indication for it, which I could not find yet. What I know is C++ math libraries should be kept as it is in C.
No, fun is meant.

They were not overloaded because it's not possible in C. Three verions were present, but with different names. So float-sqrt was declared as sqrtf, long double-sqrt was declared as sqrtl and user had to choose the best version.
cmath receclares sqrt as:
[cpp] inline float
sqrt(float __x)
{ return __builtin_sqrtf(__x); }

inline long double
sqrt(long double __x)
{ return __builtin_sqrtl(__x); }[/cpp]
to make use of overloading mechanism.