OJ Board

but my ac programm output as follows...
as i remember the problem says that the sequence contain all the succesive difference 1 to n-1...
if n=1..then it should contain alll the differnece 1 to 0(1-1)..is'nt it!!!
so if n=1,the it will be jolly if the input is as follows.. but for the input 1 2 the differece will not match with 1 to 0 ..so not jolly is it ok...

GOOD LUCK
Rocky

the system always give me WA , i dont know why.
any ideas...



/*
PROGRAMMING CHALLENGES
The Programming Contest Training Manual
IBM
2.8 Problems
2.8.1 Jolly Jumpers
*/

#include <iostream>
#include <cstdlib>
#include <vector>
#include <list>
#include <cmath>
using namespace std;

int main()
{
vector<int> nums;
list<int> res;
int seq, num,result;
int num1,num2;

cin >> seq;
if(seq <= 0 || seq > 3000)
exit(0);

nums.reserve(seq);

//To store the input in nums
for(int i = 0 ;i < seq;i++)
{
cin >> num;
nums.push_back(num);
}

//to get the difference and store it in (res) vectore variable
vector<int>::iterator iter;
for(iter = nums.begin();iter != nums.end();iter++)
{
num1 = *iter;
iter++;
if(iter == nums.end())
break;

num2 = *iter;
iter--;
result = num1 - num2;
res.push_back(abs(result));//store the absolute value of result
}

res.sort();
res.unique();


for(int i = res.size();i > 0;i--)
{
--seq;
if(res.back() == seq)
{
res.pop_back();
}
else
{
cout << "Not jolly" << endl;
exit(1);
}
}
cout << "jolly" << endl;

return 0;
}

One mistake I see is that the "j" in your "jolly" is lowercase but should be uppercase.
Learn to always test your solution against the example I/O before submitting

Edit: Also, change the exit(1) to exit(0), your program is supposed to terminate normally under all conditions.

Thanks misof
I really appreciate it.

but still WA

hi rocky

in the problem there is a comments....

so how
may u expalin please?






" i like logic "

The answer is 'Joly' for 1 2. Rocky, read the description again.

Jan wrote:The answer is 'Joly' for 1 2.

The answer for 1 2 is actually Jolly.

I don't understand Why Judge giving me WA.
Help me please

Try this case..
My output is..

Thanx,
I have got AC.....

[quote="chunyi81"]My AC program has a slightly different output than the one above.

My AC program outputs:
[code]
Jolly
Not jolly
Not jolly
Jolly
Jolly
Not jolly
Jolly
Jolly
Jolly
Not jolly
Not jolly
Jolly
Jolly
Not jolly
Jolly
Not jolly
Jolly
[/code]

As for which one is correct, it all comes down to the following input:
[code]
1 2
[/code]

Since there is only one integer, shouldn't the correct output be "Jolly"?[/quote][quote]

why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?[/quote]

why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?[/quote]

Waddle wrote:why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?

What makes you think [10 1 2 3 4 5 6 7 8 9 10] is Jolly?

[quote="sohel"][quote="Waddle"]why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?[/quote]

What makes you think [10 1 2 3 4 5 6 7 8 9 10] is Jolly?[/quote]
10-9=1
9-8=1
8-7=1
7-6=1
6-5=1
5-4=1
4-3=1
3-2=1
2-1=1
1 <= All of them <= n-1 = 9

You have slightly misunderstood the problem.
Rereading the problem statement might help!

The differences between adjacent numbers must cover all the numbers from 1 to n-1.

For the above case, only 1 is covered!! What about 2 3 4 ... 8 9 ??