11015 - 05-2 Rendezvous

[mute]

Hello tuman(sedin tor code ta thik moto kheal kori nai),
After calling "fw(adj,a)" when you are finding the min you must make the Diagonal part '0' of your "adj"

add
for(i=1; i<=a; i++) adj = 0;
after calling fw(adj,a);

[tuman]

Thanx guys ,
it was a silly mistake, i forgot to assign 0 diagonally.
macko this problem does not need multiple edges. From the problem statement it was unclear that whether it consists multiple edges or not.
I got accepted without multiple edge and also with multiple edges.


//(Nafi ...censor.... tui ei simple jinish ta dekhte ato time lagali !!! LOL)

[Hector_Hsu]

I tried to solve this problem with Dijkstra's Algorithm N times.
(I know there is a better way.... but I just try it...)

But WA so many times, can anyone send me some critical test cases?

I've read the previous posts already.

btw,

Will the following output appears?

Code: Select all

3 1
Hector
John
Ray
2 3 1

---> It causes no one can arrive Hecotr's home!

[DP]

my program produce the following output for your input:

Code: Select all

Case #1 : John

bye

[Hector_Hsu]

My prog outputs the same..

any other inputs~? plz >"<

[SRX]

My prog outputs the same..

any other inputs~? plz >"<

hi , I read my program again and I found one thing .

does your execution maintain dis(i,i)=0 ?

[Hector_Hsu]

hi , I read my program again and I found one thing .

does your execution maintain dis(i,i)=0 ?

Yes , I used a matrix to store the graph and set all graph[j] = 0
So if there is no input about house I to house J , the distance between them will be zero.(not connected)

---------------------------------------------------------------------------------

My main function Excuse me for using dynamic memory....)

Code: Select all

int main(void)
{
    int N,M,I,J,K,**graph,*dist,*d,min,ans,cas=0;
    char **name;
    while(cin>>N>>M)
    {
        cas++;
        if(!N)
            break;
        graph = new int*[N];
        for(int i=0;i<N;i++)
            graph[i] = new int[N];
        for(int i=0;i<N;i++)
            for(int j=0;j<N;j++)
                graph[i][j] = 0;
        dist = new int[N];
        for(int i=0;i<N;i++)
            dist[i] = 0;
        name = new char*[N];
        for(int i=0;i<N;i++)
        {
            name[i] = new char[11];
            cin>>name[i];
        }
        for(int i=0;i<M;i++)
        {
            cin>>I>>J>>K;
            graph[I-1][J-1] = graph[J-1][I-1] = K;
        }
        for(int i=0;i<N;i++)
        {
            d = min_dist(N,graph,i);
            for(int j=0;j<N;j++)
                dist[j] += d[j];
        }
        min = dist[0];
        ans = 0;
        for(int i=1;i<N;i++)
        {
            if(dist[i]<min)
            {
                ans = i;
                min = dist[i];
            }
        }
        cout<<"Case #"<<cas<<" : "<<name[ans]<<endl;
        for(int i=0;i<N;i++)
        {
            delete graph[i];
            delete name[i];
        }
        delete graph;
        delete name;
    }
    return 0;
}

The function called is

Code: Select all

int* min_dist(int N,int** graph,int k)

which is a Dijkstra's Algorithm,
return an array , which gives the length of shortest paths from house k.


Is there any bug in the main function?

Or ...

I should check my Dijkstra's ......

[DP]

can you explain this code segment---->

Code: Select all

        for(int i=0;i<N;i++)
        {
            d = min_dist(N,graph,i);
            for(int j=0;j<N;j++)
                dist[j] += d[j];
        } 

[Hector_Hsu]

DP:

Take a example, assume there are 5 nodes.

A,B,C,D,E

The program will run five times , k = A to E

for k = A:

Begin with node A , use Dijkstra's to travel the graph
then I get the shortest paths to B,C,D,E
that 4 value will be added to the dist

after k = E done.

=>

dist will store the total distance to house i.

compare all dist and find the min one to output.

[Hector_Hsu]

And finally I get Accepted.

The bug is that when I implement my Dijkstra's algorithm,

I use "heap" to be a min-priority queue.

And I forget to maintain the min-priority property everytime I make some action to the heap......

It's just a silly mistake....but I think it is easily to be ignored....^^"

[mhayter1]

Could someone give me some test cases for this problem. Apparently I don't understand the problem. I'm also a newbie when it comes to algos.
I out which algo to use, which is a big success, but I not getting AC.

Here's my code:

Code: Select all

/*
ID:mhayter1
PROG:ride
LANG:C++
*/
#include <iostream>
#include <fstream>
#include <vector>
#include <cctype>
#include <cstdio>
#include <iomanip>
#include <string>
#include <algorithm>
#include <sstream>
using namespace std;

/*
ifstream fin(".in");
ofstream fout(".out");
*/

const int INFINITY=1010;

int main()
{
    int distance[30][30];
    int n,m;
    string array[30];
    for(int cases=1;cin>>n>>m;cases++)
    {
        if(n==0 && m==0)
            break;
        for(int i=0;i<25;i++)
        {
            for(int j=0;j<25;j++)
            {
                distance[i][j]=INFINITY;
            }
        }
        for(int i=0;i<n;i++)
        {
            cin>>array[i+1];
        }
        int u,v,w;
        for(int i=0;i<m;i++)
        {
            cin>>u>>v>>w;
            distance[u][v]=distance[v][u]=w;
        }
        for(int k=1;k<=n;k++)
        {
            for(int i=1;i<=n;i++)
            {
                for(int j=1;j<=n;j++)
                {
                    if(distance[i][k]+distance[k][j]<distance[i][j])
                    {
                        distance[i][j]=distance[i][k]+distance[k][j];
                    }
                }
            }
        }
        int minsum=23*INFINITY;
        int cursum=0;
        int where=0;
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=n;j++)
            {
                cursum+=distance[i][j];
            }
            if(cursum<minsum)
            {
                minsum=cursum;
                where=i;
            }
            cursum=0;
        }
        cout<<"Case #"<<cases<<" : "<<array[where]<<endl;
    }
    int y;
    cin>>y;
    return 0;
}

Thanks!!

[mhayter1]

Could someone please give me test cases or something. Please

[deception01]

i'm not sure why you'd use dijkstra's when floyd's seems so much more appropriate and easier

[Spykaj]

Floyd is enough.

[WingletE]

I use Dijkstra and got WA.
Could someone give me some test cases or check my Dijkstra for me please?
Thanks in advance.

Code: Select all

int dijkstra(const int dis[22][22], const int& m, const int& start_p)
{
    int dis_min[m];          //  minimun distance
    bool not_vis[m];         //  haven't visited
    
    fill(dis_min, dis_min+m, DIS_MAX);
    fill(not_vis, not_vis+m, true);
    dis_min[start_p] = 0;
    
    for(int j = 0; j < m; j++)
    {
        int ptr = -1, min = DIS_MAX;
        
        for(int i = 0; i < m; i++)
            if((not_vis[i] == true)&&(min > dis_min[i]))
                min = dis_min[i], ptr = i;
        
        if(ptr == -1)
            break;
        
        for(int i = 0; i < m; i++)
            if(dis_min[ptr] + dis[ptr][i] < dis_min[i])
                dis_min[i] = dis_min[ptr] + dis[ptr][i];
        
        not_vis[ptr] = false;
    }
    
    int sum = 0;
    
    for(int i = 0; i < m; i++)
        sum += dis_min[i];
    
    return sum;              //  the shortest path start from start_p
}

I set DIS_MAX to 50000, would the value affects the result?