498 - Polly the Polynomial

[sohag144]

I checked all i/o that i got from previous topic.
But i m getting WA.Can anyone help?

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code deleted after got ac

[the LA-Z-BOy]

char word[MAX][10];

seems too small here... get something like

char word[MAX][20];

Also you would get Presentation Error on this, because you are printing extra space at end of each line.
Greetings.

[sohag144]

Thank you again.
You help me a lot.got AC.

[ALEXANDRIA_2]

I can't understand why I keep gettin WA all the time...
can anyone tell me what's wrong with my code...

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#include<stdlib.h>
#include<string.h>
#include<stdio.h>


long int A[100];
long int B[100];
int in;

int tes(char line[],int w){
	long int i,len,isneg=1,f=0,sum=0,T;
	in=0;
	len=strlen(line);
	for(i=0;i<len;i++)
	{
		if(line[i]=='-') isneg=0;
		else
		if(line[i]!=' ')
		{
			  f=1;
			  T=line[i]-'0';
			  sum*=10;
			  sum+=T;
		}
		else
		{
			if(f)
			{
			if(!isneg) sum*=-1;
			if(!w)A[in]=sum;
			else B[in]=sum;
			sum=0;
			in++;
			isneg=1;
			f=0;
			}
		}
	}

	if(!isneg) sum*=-1;
	if(!w)A[in]=sum;
	else B[in]=sum;
	in++;

return in;
}


long int sum(long int angka,long int pang){
	int i;
	if(!pang) return 1;
	for(i=1;i<pang;i++)
	{
		angka*=angka;
	}
	return angka;
}

void main(){
	char line[128];
	int m,n;
	long int T=0,X,Angka,k,pang,i,t=0,ctr=0;
	while(gets(line))
	{
		if(ctr) printf("\n");
		else ctr=1;
		t=0;
		m=tes(line,0);
		gets(line);
		n=tes(line,1);

	for(k=0;k<n;k++)
	{
		Angka=B[k];
		pang=m-1;
		for(i=0;i<m;i++)
		{
			X=sum(Angka,pang);
			X*=A[i];
			T+=X;
			pang--;
		}
		if(!t) {printf("%ld",T);t=1;}
		else printf(" %ld",T);
		T=0;
	}
	T=in=0;
	memset(A,0,sizeof(A));
	memset(B,0,sizeof(B));
	
	}
}

I've passed all the input given in this thread..
and the output is correct....
Thanks...

[S.M.ferdous]

Hello to all

I have solved 498 problem but my problem in getting input.

I am not understanding how to accept an even number of lines of text.
Another puzzling matter is that I can't correctly implement the breaking condition.

I need some help.plz help me.

[loghiyan]

Try this way. It might do the trick ( haven't seen the problem statement :-p) :

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      char line1[200],line2[200];
      int n;
      char *c,*d;
 while (gets(line1) && gets(line2)){
      c=strtok(line1," \n");
      while (c){
            n=atoi(c);
            cout<<n<<endl;
            c=strtok(NULL," \n");
      }
            d=strtok(line2," \n");
            while (d){
            n=atoi(d);
            cout<<n<<endl;
            d=strtok(NULL," \n");
      }
 }

Hope that helps.

[Freyr]

Yeah, does anyone have any tricky test data for this? I've made loads of different possible problems, and my program solves them all, but still gets WA.

*shrugs*

[Freyr]

Nevermind, it was a presentation error, but it came up as wrong answer.

For anyone else who may need test data...

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-1 1 -11 1 -1
1 -1 11 -11
45 0 23 0 21
500 2333 3213 1

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-11 -15 -14631 -17315
2812505750021 1333126955170913 4795737875394753 89

Double works.

Edit: Removed certain test cases as they don't appear in the judge's input file.

[Freeman]

I don't know if it's because of cin.getline
My Sample Output is correct.

This is my code (a bit long):

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#include<iostream>
#include<cmath>
#include<string>
using namespace std;
int main()
{
    int i,k,len,ct,now;
    int a[10000],b[10000],neg,xd=0;  
    char z[10000],zx[10000];
    double sum,total;
    
    while( cin.getline(z,10000) )
    {
        ct=0; total=0;  neg=0;  now=0;
        len = strlen(z);
        
        for (i=len-1;i>=0;i--)
        {
            if (z[i]>=48 && z[i]<=57)
            {
                total += int ( (z[i]-48)*pow(10.0,ct) );
                ct++;
            }
            else if (z[i]=='-')
                total *= -1;
            if (z[i]==' ' || i==0)
            {
                a[now] = int(total);
                xd++;  // control of XD
                ct=0;
                total=0;
                neg=0;
                now++;
            }
            
        } //for 
        // cout << a[0] << " " << a[1] << " " << a[2] << endl; 
        int test=0; 
        now=0; total=0; neg=1; ct=0; sum=0;// neg 1 = +  -1= - 
        
            cin.getline(zx,10000);
        
            len = strlen(zx);
            for (k=len-1;k>=0;k--)
            {
                
            if (zx[k]=='-')
                total *= -1;
            else if (zx[k]>=48 && zx[k]<=57)
            {
                total += (zx[k]-48)*pow(10.0,ct);
                // cout << "total=" << total << endl;
                ct++;
            }
            
            if (zx[k]==' ' || k==0)
            {
                for(i=0;i<xd;i++)
                {
                    sum += a[i]*pow( total,i );
                    // cout << "sum=" << sum << endl;
                }
                b[test]=sum;
                
                sum=0;
                total=0;
                now++;
                ct=0;
                test++;
                
                if (zx[k]==10)
                    break;
            }
            
            } // for
            for (i=test-1;i>=0;i--)
            {
                cout << b[i];
                if (i!=0)
                    cout << " ";
            }
            cout << endl;
            
    } //while

    return 0;
}

Can someone tell me what's wrong with it? Thks.

[Jan]

Dont open a new thread if one already exists. Use existing thread.

[vkubushyn]

Hey, my code for this problem seems impeccable to me, and it's solved all the examples on this forum correctly, and yet I still get WA. Can anyone tell me what's wrong with my code? I tried printing a space after each line, not printing an ending blank line, and other possible PE problems... Thanks.

Code: Select all

#include <iostream>
#include <math.h>
#include <vector>
#include <string>
#include <iomanip>
#include <sstream>
using namespace std;

int main() {
	cout << fixed << setprecision(0);
	vector<double> coeff;
	string s;
	stringstream* sin;
	double n, count, sum;
	getline(cin, s);
	while(!cin.eof()) {
		sin = new stringstream(s);
		while(*sin >> n)
			coeff.push_back(n);
		
		getline(cin, s);
		if(!cin.eof()) {
			sin = new stringstream(s);
			*sin >> n;
			while((*sin).good()) {
				sum = 0; count = 0;
				for(int i = coeff.size()-1; i >= 0; i--) {
					sum += coeff[i]*pow(n, count);
					count++;
				}
				cout << sum << " ";
				*sin >> n;
			}
			coeff.clear();
			getline(cin, s);
			cout << endl;
		}
	}
	return 0;
}

[jjtse]

Does anyone know if there's a limit on 'n' and 'm'?

[Samiul]

1000 will be enough for both n and m.

[thomas1016]

part of my code
I finally got AC

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istringstream iss;

istringstream works !!!!
thanks a lot

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#include<iostream>
#include<sstream>
#include<string>

using namespace std;
int pol(int,string);

void polf(string,string);

int main(){
    int j,sum;
    string po,k;
    
    while(1){
            
             
             if (!getline(cin,po)) break;
        
             
              if (!getline(cin,k)) break; 
             polf(k,po);
             }
    //system("pause");
    return 0;
    }

[maruf]

For each pair of lines, your program should evaluate the polynomial for all the values of x

what is meant by "evaluating" here??plz help........