10424 - Love Calculator

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galois_godel
New poster
Posts: 17
Joined: Wed Jul 17, 2002 5:00 pm

10424 - Love Calculator

I think it's a easy problem and I got AC when I submit first. But after REJUDGEMENT. The judge tell me that my code is wrong?
Can u tell me why? thank u?
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
using namespace std;
int chartonum(char *c)
{
int len=strlen(c);
int i;
int result=0;
for(i=0;i<len;i++)
{
if(c>='a' && c<='z')
result+=c-'a'+1;
if(c>='A' && c<='Z')
result+=c-'A'+1;
}
while(result>=10)
{
int temp=0;
while(result)
{
temp+=result%10;
result=result/10;
}
result=temp;
}
return result;
}

int main()
{
char a[30],b[30];
while(cin.getline(a,25))
{
double r;
//cin.getline(a,25);
cin.getline(b,25);
scanf("%s",b);
int numa=chartonum(a);
int numb=chartonum(b);
if(numa==numb)
r=1.0;
else if(numa>numb)
r=double(numb)/(double)(numa);
else
r=double(numa)/(double)(numb);
r=r*100.0;
cout.setf(ios::fixed);
cout.precision(2);
cout<<r<<" %"<<endl;
}

return 0;
}

galois_godel
New poster
Posts: 17
Joined: Wed Jul 17, 2002 5:00 pm

I think it's a easy problem and I got AC when I submit first. But after REJUDGEMENT. The judge tell me that my code is wrong?
Can u tell me why? thank u?
#include<iostream>
#include<cstdio>
#include<cstdlib>
#include<cstring>
using namespace std;
int chartonum(char *c)
{
int len=strlen(c);
int i;
int result=0;
for(i=0;i<len;i++)
{
if(c>='a' && c<='z')
result+=c-'a'+1;
if(c>='A' && c<='Z')
result+=c-'A'+1;
}
while(result>=10)
{
int temp=0;
while(result)
{
temp+=result%10;
result=result/10;
}
result=temp;
}
return result;
}

int main()
{
char a[30],b[30];
while(cin.getline(a,25))
{
double r;
//cin.getline(a,25);
cin.getline(b,25);
scanf("%s",b);
int numa=chartonum(a);
int numb=chartonum(b);
if(numa==numb)
r=1.0;
else if(numa>numb)
r=double(numb)/(double)(numa);
else
r=double(numa)/(double)(numb);
r=r*100.0;
cout.setf(ios::fixed);
cout.precision(2);
cout<<r<<" %"<<endl;
}

return 0;
}

Bistromath
New poster
Posts: 16
Joined: Fri Oct 11, 2002 11:03 pm
Location: France
Hi,

This problem seems easy but i think i have excatly the same problem as u.
Is there any special case to consider, or is it a precision problem
Any tip or I/O data appreciated
Thanks

turuthok
Experienced poster
Posts: 193
Joined: Thu Sep 19, 2002 6:39 am
Location: Indonesia
Contact:
galois_godel, I tried to grab your code and ran it ... It looks like something is wrong when you're reading the input (words) ...

I tried with simple input file containing:
saima
shanto

71.43 %

However, just added two more words:
saima
shanto
Pakistan
India

14.29 % ==> Looks like the love-ration between saima and Pakistan!
0.00 %

Oh yes, and one more thing that we need to be very careful, the input-description doesn't mention that each word will be in a line by itself.

-turuthok-

Bistromath
New poster
Posts: 16
Joined: Fri Oct 11, 2002 11:03 pm
Location: France
turuthok wrote:
Oh yes, and one more thing that we need to be very careful, the input-description doesn't mention that each word will be in a line by itself.

-turuthok-
I though about that case but problem description also says that a word can contain white spaces.
how do you consider such a line :
a a b b ?

"a a" and "b b" or
"a","a" and "b","b" ?

turuthok
Experienced poster
Posts: 193
Joined: Thu Sep 19, 2002 6:39 am
Location: Indonesia
Contact:
Bistromath, you are correct ... please ignore my last paragraph there ... I checked my AC code again ... it also reads one word per line ...

-turuthok-

turuthok
Experienced poster
Posts: 193
Joined: Thu Sep 19, 2002 6:39 am
Location: Indonesia
Contact:
galois_godel, try to remove or comment out your 'scanf' ... it might work.

-turuthok-

liusu
New poster
Posts: 22
Joined: Thu Aug 01, 2002 10:26 am

i also meet the same proble..my code is :
[pascal]
var
table:array[0..128] of integer;
in1,in2:string;
sum1,sum2:integer;

procedure init();

var
i,x:integer;

begin
for i:=0 to 128 do
table:=0;

x:=64;
for i:=1 to 26 do
table[x+i]:=i;
x:=96;

for i:=1 to 26 do
table[x+i]:=i;
end;

function len(i:integer):integer;
var
len,tem:integer;
begin
len:=1;
tem:=i;
while(tem>9) do
begin
inc(len);
tem:=tem div 10;
end;
len:=len;
end;

function getsum(s:String):integer;
var
i,tem,l:integer;

begin
tem:=0;
i:=1;
l:=length(s);

for i:=1 to l do
tem:=tem+table[ord(s)];
getsum:=tem;
end;

function getresult(i:integer):integer;
var
tem,x,j:integer;
begin
tem:=i;
x:=0;

while(tem>9) do
begin
if(tem>9) then
begin
for j:=0 to len(tem) do
begin
x:=x+tem mod 10;
tem:=tem div 10;
end;
tem:=x;
x:=0;
end;
end;
getresult:=tem;
end;

begin
init();
WHILE(NOT EOF) DO
begin
sum1:=getsum(in1);
sum1:=getresult(sum1);
sum2:=getsum(in2);
sum2:=getresult(sum2);
if(sum1>sum2) then
writeln(sum2/sum1*100:0:2,' %')
else writeln(sum1/sum2*100:0:2,' %');
end;

end.

Code: Select all

`````` plseae help me...thank you very much!
``````

Sajid
Learning poster
Posts: 94
Joined: Sat Oct 05, 2002 5:34 pm
Location: CS - AIUB, Dhaka, Bangladesh.
Contact:

Check

It's so easy problem. Check your code ... debug it.
it's also easy to find out inputs and outputs for this problem. so, find some others inputs and calculate the output urself 1st.. then check with ur program...

Best of LUCK...
Sajid Online: www.sajidonline.com

Angel
New poster
Posts: 8
Joined: Wed Nov 20, 2002 3:49 pm

10424 WA HEEEEEEEELLLPPPPP plzzzzzzzz

I cant find any wrong in this....... :o

#include<stdio.h>
#include<string.h>

void main()
{
int i,j,sum1=0,sum2=0;
double digit1=0.0,digit2=0.0,per;
char name1[30],name2[30];

while(gets(name1) && gets(name2))
{

for(i=0;i<strlen(name1);i++)
{
if(name1[i]>='A'&&name1[i]<='Z')
sum1+=name1[i]-'A'+1;
if(name1[i]>='a'&&name1[i]<='z')
sum1+=name1[i]-'a'+1;

}
for(i=0;i<strlen(name2);i++)
{

if(name2[i]>='A'&&name2[i]<='Z')
sum2+=name2[i]-'A'+1;
if(name2[i]>='a'&&name2[i]<='z')
sum2+=name2[i]-'a'+1;
}

if(sum1==0)digit1=0.0;
if(sum2==0)digit2=0.0;
while(sum1>0)
{
digit1+=float(sum1%10);
if(digit1>9){sum1=int(digit1);digit1=0;}
else sum1=sum1/10;

}
while(sum2>0)
{
digit2+=float(sum2%10);
if(digit2>9){sum2=int(digit2);digit2=0;}
else sum2=sum2/10;

}
if(digit1>=digit2)
{
per=(digit2/digit1)*100;
printf("%.2f %%\n",per);
}
else if(digit2>=digit1)
{
per=(digit1/digit2)*100;
printf("%.2f %%\n",per);
}

digit1=0.0;digit2=0.0;sum1=0;sum2=0;
//memset(name1,0,sizeof(name1)-1);
//memset(name2,0,sizeof(name2)-1);
}
}

Angel
New poster
Posts: 8
Joined: Wed Nov 20, 2002 3:49 pm

test

test

SilVer DirectXer
New poster
Posts: 39
Joined: Wed Jan 22, 2003 11:02 am

10424.... the poor love calculator.

[cpp]
#include <stdio.h>
#include <string.h>
struct shit{
char name[26];
int n_value;
int len_name;
};
int die1,die2;
shit n1,n2;
int i;
double ans;
void main(void)
{
while (1)
{
ans=0;
gets(n1.name);
if (feof(stdin))
break;
gets(n2.name);
if (feof(stdin))
break;
n1.len_name =strlen(n1.name );
n2.len_name =strlen(n2.name );
for (i=0;i<n1.len_name ;i++)
if (n1.name>=65 && n1.name <=90)
n1.name +=32;
for (i=0;i<n2.len_name ;i++)
if (n2.name>=65 && n2.name <=90)
n2.name +=32;
die1=0;
for (i=0;i<n1.len_name ;i++)
{
if ((n1.name >=65 && n1.name <=90)||(n1.name>=97 && n1.name<=122))
{
die1=1;
break;
}
}
die2=0;
for (i=0;i<n2.len_name ;i++)
{
if ((n2.name [i]>=65 && n2.name[i] <=90)||(n2.name[i]>=97 && n2.name[i]<=122))
{
die2=1;
break;
}
}
n1.n_value =0;
for (i=0;i<n1.len_name ;i++)
{
if (n1.name[i]>=97 && n1.name[i]<=122)
n1.n_value +=n1.name[i]-96;
}
n2.n_value =0;
for (i=0;i<n2.len_name ;i++)
{
if (n2.name[i]>=97 && n2.name[i]<=122)
n2.n_value +=n2.name[i]-96;
}

for (i=0;i<=5;i++)
{
if (n1.n_value >=10 && n1.n_value <=99)
{
n1.n_value =n1.n_value/10+n1.n_value % 10;
}
if (n1.n_value >=100 && n1.n_value <=600)
{
n1.n_value =n1.n_value /100+((n1.n_value /10) % 10)+n1.n_value % 100;
}

if (n2.n_value >=10 && n2.n_value <=99)
{
n2.n_value =n2.n_value/10+n2.n_value % 10;
}
if (n2.n_value >=100 && n2.n_value <=600)
{
n2.n_value =n2.n_value /100+((n2.n_value /10) % 10)+n2.n_value % 100;
}

}
if (n1.n_value >n2.n_value )
ans=n2.n_value /(double)n1.n_value;
else
ans=n1.n_value /(double)n2.n_value;

ans*=100;

if (die1==0 || die2==0)
printf("0.00 ");
else
printf("%0.2f ",ans);
printf("%%\n");
}
}

[/cpp]

if the ratio of the result is more than 1, say x, i take 1/x...
if user only input rubbish charactar in one of the name...
the result will be 0.00 %....

am i right?

any other rules that i havent consider?

i got a WA..
pls help me to take a look.

Learning poster
Posts: 57
Joined: Sun Sep 29, 2002 12:00 pm
Location: in front of the monitor :-)
Contact:
hello.

the problem-statement states that only the alphabetic characters have values. so if you get any other character, then ASCII code for that character should NOT be added.

if you haven't got AC yet, hope this helps.

Calvin
New poster
Posts: 5
Joined: Sat Mar 08, 2003 12:50 pm
What a complicated program and so long for such a problem!! You should start again and think in a simple way..

For ratio, the problem is for 2 numbers A and B to calculate (A/B)*100 si A is smaller than B and (B/A)*100 if B smaller than A...[/java]

Syed Mubashshir Husain
New poster
Posts: 9
Joined: Wed Apr 02, 2003 10:28 am
The code is so complicated. Think it so easily.
The ratio

if(a > b) b / a;
else a / b;