488 - Triangle Wave

[helloneo]

Now look at my output.... I thik thats good.... but still WA

Actually your code prints output this way..

\n
2\n
\n
3\n
2\n
1\n
22\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
22\n
1\n
\n
3\n
2\n
1\n
22\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
22\n
1\n

[Obaida]

I think I can't read you.... still WA....
look at my code...... what should be edited...

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Removed

[AcmNightivy]

I change in using stdio..but still WA..Help!!Thanks!!

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#include <stdio.h>

int main ()
{
	int i, j, k;
	int caseNum;
	int a, f;
	char num[10][10] = {"", "1", "22", "333", "4444", "55555", "666666", "7777777", "88888888", "999999999"};

	scanf ("%d", &caseNum);

	for (i = 0; i < caseNum; i++)
	{
		scanf ("%d%d", &a, &f);

		for (j = 0; j < f; j++)
		{
			for (k = 1; k <= a; k++)
			{
				printf ("%s\n", num[k]);
			}
			k = k - 2;
			for (; k >= 1; k--)
			{
				printf ("%s\n", num[k]);
			}

			//if (i != caseNum - 1)
			printf ("\n");
		}	
	}
	return 0;
}

[Obaida]

Some one please could tell me from my above code... that where is the extra \n in my program.... I couldn't find it.... But still I had to belive because I am getting WA in this problem......

[CSEDU_1323]

hi,
Obaida, helloneo trace out ur error u print a extra new line in d front

use if(l>= 1 &&l<n)
instead if(l>= 0 &&l<n)
will do ur work

&&

u don't need 2 take test case more than once

HOPE THIS HELPS

[Obaida]

Thank You very much.....! I got Accepted..... But in the instruction of the program it is mentoned that we had to print a blank line after test case....
But afterall thank you.... very much....

[pwilt]

I seem to be getting the answer correct (tried to follow the formatting in the other posts to the letter) but I'm still getting WA from the judge. Can anybody point out something that I've missed?

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#include <iostream>
#include <string>

using namespace std;

int main(){
    int tc;
    cin >> tc;
    string nums[9] = {"1","22","333","4444","55555","666666","7777777","88888888","999999999"};
    
    short amp, freq, j;
    
    for (int i = 1; i <= tc; i++){
        cin >> amp;
        cin >> freq;
        
        for (short k = 1; k <= freq; k++){
            for (j = 0; j < amp; j++){
                cout << nums[j] << endl;
            }
            for (j -= 2; j >= 0; j--){
                cout << nums[j] << endl;
            }
            if (k < freq){
                cout << endl;
            }
        }
        if (i < tc){
            cout << endl;
        }
    }
}

[pwilt]

Bump?

[t_sergiu]

I am getting a TLE on this problem as well. I would think it wouldn't take any time at all to run this. Can anybody offer some suggestions?

[Jan]

No idea. Are you sure you are taking input correctly? You can check your solution by sending a solution which just takes the input.

[t_sergiu]

Fixed. I was using cin and cout. Switched it to use printf and scanf, and did it in 1/10 of a second.

[Obaida]

But this is Actually WA...!
Not PE...
In "int main()" type you should use "return 0;"
But you didn't do it.

[hahahaken]

My code got time limit exceeded.
How to reduce the time? Coz I don't know the maximum number of input.

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Removed after AC

[Obaida]

If you use array then you can solve the problem by pre-initialization, it can be like:

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int use[10]={0,1,22,333,4444,55555,666666,7777777,88888888,999999999};
then just print the current value of use[i] and make the wave. It will be more faster and efficient.

else you can do it without any use of array then it can be a little slow.

>>may this help you.

[hahahaken]

If you use array then you can solve the problem by pre-initialization, it can be like:

Code: Select all

int use[10]={0,1,22,333,4444,55555,666666,7777777,88888888,999999999};
then just print the current value of use[i] and make the wave. It will be more faster and efficient.

else you can do it without any use of array then it can be a little slow.

>>may this help you.

Still TLE
Here's the updated version:

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Removed after AC