445 - Marvelous Mazes

[Stanley Sentoso]

oh, i miss something. i change my variabel data type from char to unsigned char, but i still got Presentation Error (PE).

[rossi kamal]

sorry i ve found that silly mistake.....but i want to mention that

my ac code gives the following result
make it clear plz..

input:
1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T!

11X21b1X!
4X1b1X!


outout:
T TTTTT
T T TT
T T TT
T T T
TTT T
T T T
TTTTT*T


XX X

XXXX X

[Fuad Hassan EWU]

AC

[sapnil]

To Fuad Hassan EWU

your output is like this:

Code: Select all

T TTTTT
T  T TT
T T  TT
T   T T
TTT   T
T   T T
TTTTT*T
 
XX   X
XXXX X<

but it must be

Code: Select all

T TTTTT
T  T TT
T T  TT
T   T T
TTT   T
T   T T
TTTTT*T
 
XX   X
XXXX X
<

'<' indecate cursor.

Hope its help

Thanks
Keep posting
Sapnil

[Fuad Hassan EWU]

yes sapnil. it works. thanks...

[mahedee]

I tried this problem for several time but still getting WA. Could you please help me?

Code: Select all

#include<stdio.h>
#include<string.h>

int main()
{
	char str[500];
	int i,j,val=0;
	int len,flag =0;
	while(gets(str)!=NULL)
	{
		//printf("\n");
		len = strlen(str);
		if(len==0)
		{
			printf("\n");
			continue;
		}
		for(i = 0;i<len;i++)
		{
			if(str[i]>=48&&str[i]<=57)
			{
				val = val + (str[i]-48);
			}

			else
			{
				j = 0;
				do
				{
					if(str[i]=='b')
						printf(" ");
					else if(str[i] == '!'||str[i] == '\n')
						printf("\n");
					else
						printf("%c",str[i]);
					
					j++;
				}while(j<val);
				val = 0;
			}
		}
		printf("\n\n");		

	}
	return 0;
}

[sohel]

Do not create a new thread for a problem if one already exists!

[aliahmed]

AC - Thanks

[abid_iut]

why I am getting WA
pls someone check
here is my code:

Code: Select all

#include<stdio.h>
#include<string.h>

int main()
{
	char str[200];
	int i,j,n,flag=0;
	while(gets(str)!=NULL){
		if(flag==0)flag=1;
		else putchar('\n');
		if(str[0]=='\n')
			printf("\n");
		else {
			n=0;
			for(i=0;str[i]!=0;i++)
				if(str[i]=='!')
					putchar('\n');
				else 
					if(str[i]>='1' && str[i]<='9')
						n+=str[i]-48;
					else {
						for(j=0;j<n;j++){
							if(str[i]=='b')printf(" ");
							else
							printf("%c",str[i]);
						}
						n=0;
					}
			}
		
	}
	return 0;
}

pls help

[Articuno]

What are you trying to do with this? :

Code: Select all

if(str[0]=='\n')
         printf("\n");

You are using gets() and I think it is not possible for a string to have a '\n' character while you are using gets().
And for this case:

Code: Select all

101a

Your code fails.The output should be

Code: Select all

aa

I think this problem requires to read input character by character. Then you will be able to check for '\n' character.
There is one more thing. Think about this case:

Code: Select all

1a<There may be a '\n'>

if it is the last test case and there is a newline after "1a" your program will fail to print that newline. Do you get my point?
Wish you good luck.

[abid_iut]

Thanks Articuno
U r a great guide for me
Thanks for help

[linux]

Try these inputs

input:

Code: Select all

    1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T!

    11X21b1X!
    4X1b1X!

    3X3b3X1b1X5b1X1b1X2b1X3b1X2b1X1b4X1b4X1b1X3b3X
    1b1X4b1X1b1X1b1X2b1X2b1X1b2X1b1X3b2X1b1X1b1X2b1X1b1X2b1X1b3X2b1X
    1b1X4b3X2b1X1b1X1b1X2b1X1b2X3b1X1b2X1b1X2b1X1b1X2b1X1b1X1b1X3b1X
    3X3b1X5b1X1b1X3b1X2b1X3b1X2b1X1b4X1b4X1b3X1b3X


    3O3b3O1b1O5b1O1b1O2b1O3b1O2b1O1b4O1b4O1b1O3b3O
    1b1O4b1O1b1O1b1O2b1O2b1O1b2O1b1O3b2O1b1O1b1O2b1O1b1O2b1O1b3O2b1O
    1b1O4b3O2b1O1b1O1b1O2b1O1b2O3b1O1b2O1b1O2b1O1b1O2b1O1b1O1b1O3b1O
    3O3b1O5b1O1b1O3b1O2b1O3b1O2b1O1b4O1b4O1b3O1b3O

output:

Code: Select all

    T TTTTT
    T  T TT
    T T  TT
    T   T T
    TTT   T
    T   T T
    TTTTT*T


    XX   X

    XXXX X


    XXX   XXX X     X X  X   X  X XXXX XXXX X   XXX
    X    X X X  X  X XX X   XX X X  X X  X XXX  X
    X    XXX  X X X  X XX   X XX X  X X  X X X   X
    XXX   X     X X   X  X   X  X XXXX XXXX XXX XXX


    OOO   OOO O     O O  O   O  O OOOO OOOO O   OOO
    O    O O O  O  O OO O   OO O O  O O  O OOO  O
    O    OOO  O O O  O OO   O OO O  O O  O O O   O
    OOO   O     O O   O  O   O  O OOOO OOOO OOO OOO

[aliahmed]

I test your input
I think my output is correct
then why wa again?

[linux]

Code: Select all

if(str[i]=='\0')
break;
if(str[i]>=48 && str[i]<=56)
{
sum=sum+str[i]-48;
continue;
}

What about the digit 9? Why are ignoring it? It's not any less important to get AC. Other parts of the code seems okay.

[shorojini]

i am getting wrong answer in this problem.
i am giving my code here.if there is not any prob in code then there must
be some prob in my input output system.please can anyone give me any solution and
some some sample input output.pls pls pls mark me my prob.pls pls pls.

Code: Select all

#include<iostream>
#include<string>
using namespace std;
int main()
{
string s;
while(getline(cin,s))
{
int l=s.length();

int k=0;
for(int i=0;i<l;i++){

if(s>=48 && s<=57)
k=k+s-48;

else if(s=='!')
cout<<"\n";

else{
if(s=='b') {
for(int i=0;i<k;i++)
cout<<" "; }
else{
for(int j=0;j<k;j++)
cout<<s; }
k=0;
}

if(i==l-1)
cout<<"\n";

}




}
return 0;
}