11205 - The broken pedometer

[mmonish]

I am getting WA in this problem.
Can anyone give me some critical test case.

[mmonish]

Now i got AC. But my program takes 1.633 sec.
I checked all possible configaration.
Anyone please tell me how can i improve the time.

[Jan]

You can use bitwise operations to solve it. My brute force code(with bitwise calculations) took 0.312 seconds.

[hi!man!]

sorry, I don't understand what this problem means.

In this case, LEDs 5 and 6 can be suppressed without losing information, so the solution is 5.

What does this mean??I looked this problem twice but still can't understand it

[mmonish]

In this prob u have to find minimum number of active led's necessary to identify each symbol's means no repetive pattern.

In the first sample used 7 led's to represent a symbol. But if we turn off led 5 && 6 then it is still have no repetive pattern. So we need 5 active led's && thus the minimum.

Hope it helps.

[hi!man!]

Thank you for your quick reply.
I finally understand this problem!!

Now I am thinking how to solve it...

[sjn]

Can anyone give some critical test cases?

[mmonish]

try this case

Code: Select all

5
2
2
1 0
1 1
4
5
1 1 1 1
0 1 1 0
1 0 0 1
1 1 0 0
0 0 0 1
1
2
1
0
1
1
0
4
4
1 1 0 0
0 0 1 0
1 0 0 0
0 1 0 0

output

Code: Select all

1
3
1
1
2

[/code]

[sjn]

thank you for your test cases!

I really misunderstood the problem

[mmonish]

yes.
That's the exact reason.

[sjn]

yes.
That's the exact reason.

Thank you for your post, I should read the problem and your previous post carefully next time

[mmonish]

Sily mistake in my typing. The result should be 1.

now i edit my post. Thanks for ur reply.

[darkos32]

i've tried all test cases,but i still got WA...can anyone give me another critical testcases ?


thanks..

[hamedv]

is it a valid input

Code: Select all

1
2
2
11
11

[mmonish]

I think there is no cases like that.

Try this cases
Input

Code: Select all

3
3
1
1 0 1
5
2
1 1 1 1 1
1 1 1 1 0
3
8
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1

Output

Code: Select all

1
1
3