494 - Kindergarten Counting Game

[xintactox]

I changed the line

cur_word.clear();

by

cur_word = ''";

It compiled and worked fine in my pc under g++ and cygwin, but i'm still getting CE... any suggestions?!

Thanks!

[Jan]

You used 2..

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cur_word.clear();

I believe you removed only one of them. Remove both of them. I m sure that you will not get CE.

Hope it helps.

[xintactox]

Hi!

I posted the following code, but I'm still getting CE...
I changed the lines you told me but.. it's not getting accepted... what else an be wrong?

Thank you

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#include <string>
#include <iostream>
#include <ctype.h>
//#include <iomanip>

using namespace std;

int main()
{
   string linha, cur_word;
   int count, char_count;   
   while(getline(cin, linha))
   {
      count = 0;
      char_count = 0;
      cur_word = "";         
      while(char_count < linha.size())
      {
         while(isalpha(linha[char_count]) && char_count < linha.size())
         {            
            cur_word += linha[char_count];
            char_count++;
         }         
         for(int i = 0; i < cur_word.size(); i++)
            if(isalpha(cur_word[i]))
            {               
               count++;
               break;
            }
         cur_world = "";   
         char_count++;
      }
      cout<<count<<endl;      
   }
   return 0;
}

[chunyi81]

Very careless typo in your code.

You declared the following variables in your code:

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   string linha, cur_word; 

but further down in your code I see this:

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cur_world = "";

[xintactox]

You we're right....

I was too stupid, im sorry for bothering u all!

Ang I Got AC! Thanks!

[abhi]

this is my code i get WA .i think it should work ......where am i wrong??

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 CODE DELETED             

[Schutzstaffel]

At first glance your program doesn't give the correct output if the line starts with a character that's is not in A-Z and a-z like ponctuation and whitespace.
For example:

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..  This is a valid input!

You program would output 6 wich is wrong.

Also you program didn't output the correct values for the example given because of this condition:

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while (str[i]!='\0')

gets function fills the array only until the last character in str position, the rest of the array has garbage for so saying so you should have while (i < strlen(str)) instead.

Good luck, you're near the correct answer

[chunyi81]

Did you even test your code with the sample input. Your code gives wrong answer with the sample input.

Change this:

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while(!isalpha(str[i])) i++;

to this:

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while(str[i] != '\0' && !isalpha(str[i])) i++;

This will make your code pass the sample input but your code will still give WA if the sample input contains one word like this:

Input:
a

Correct Output:
1

But your code gives:
0

[abhi]

well i made the changes which Schutzstaffel suggested and got AC anyways . but still the time is 0.002 s. i dont know y it is so slow ????

[Jan]

I have not read your code. Try submitting 2 or 3 times. I think you will get it Accepted in 0.000 seconds. Otherwise try to avoid printf. Then your runtime will decrease.

[abhi]

well anyways ..... i checked on the web and according to C standards gets must terminate the string with a '\0' character. so if i use

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while(str[i]!='\0')

then it should have worked properly i think ????

[mamun]

well anyways ..... i checked on the web and according to C standards gets must terminate the string with a '\0' character. so if i use

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while(str[i]!='\0')

then it should have worked properly i think ????

It should, depending on the value of i (I didn't get a chance to read your code ).

[chunyi81]

You had two while loops in your original code. The first one did this:

while(str != '\0')

This is fine of course.

It is the inner while loop that can cause problems:

while(!isalpha(str)) i++;

If str is '\0' in this loop your code will still increment i, since the null character is not an alphabet character according to the isalpha function.

[fixit]

var a:array [0..100] of char;count,i:integer;
function ileslow(s:string):integer;
var k:integer;var slowo_start:boolean;counter:longint;
begin
slowo_start:=false;
counter:=0;
for k:=1 to length(s) do
if (s[k] in ['a'..'z']) or (s[k] in ['A'..'Z']) then
begin
if not slowo_start then
begin
inc(counter); slowo_start:=true;
end;
end else
slowo_start:=false;


ileslow:=counter;

end;

begin
count:=0;
while true do
begin
readln(a[count]);inc(count);
if (a[count-1][length(a[count-1])]=#26) or (a[count-1][1]=#26) then break;
end;
for i:=0 to count-1 do
writeln(ileslow(a));
end.

I don't understand what is wrong

[farzane]

Hi dear fixit

First:you didn't say what kind of problem you had with your code.After submition what kind of error you recived.

Your algorithm for this problem is true for sure.I submitted a solution for this problem by this algoritm and I recived an ACCEPTED reply.
Here is my code in c++:
-----------------------------------------------
#include<iostream.h>

int counter(char str[]){
int count=0;
bool inword=false;
int i=0;
for(;str;i++)
if((str>='a' && str<='z')||(str>='A' && str<='Z')){
if(inword==false){
inword=true;
count++;
}

}
else inword=false;
return count;
}



void main(){
char str[100000];
while(cin.getline(str,100000))
cout<<counter(str)<<endl;
}

-------------------------------------------------------------------------
Try to correct your own code.
I saw some mistakes in your code:

1)You recived all of inputs and saved them and then solved each of them.
while you can read and solve them one by one why you did so?

2)I think the size of array a(100) is too small.

3)You define array a so: a:array [0..100] of char;
but you use it in a different model: a[count-1][length(a[count-1])]
(I mean the number of brakets[])


All of the above are my opinions and maybe they are wrong,but I hope I was helpful.

And at the end I excuse if I couldn't express myself good.English isn't my
tongue languge and I'm not good at it.

with the best regards