10424 - Love Calculator

[longted]

can you tell me my answer is right but upload uva web is wrong.
where is my wrong
ths

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my code is below
// uva_10424.cpp 
//


#include <iostream>
#include <string.h>
#include<iomanip>
#include<stdio.h>
#define MAX_SIZE 512
using namespace std;
int caluated_str_value(char *str)
{
/*
A=65
Z=90
a=97
z=122
0=48
9=57*/
	int sum=0;
	char str_array[MAX_SIZE]={NULL};
	strcpy(str_array,str);
	do
	{	sum=0;
		for(int i=0;i<strlen(str_array);i++)
		{
			int char_value=str_array[i];
			
			if(char_value>=48 &&char_value<=57)
			{
				sum=sum+int(str_array[i]-48);			
			}
			if(char_value>=65 &&char_value<=90)
			{
				sum=sum+int(str_array[i]-64);			
			}
			if(char_value>=97 &&char_value<=122)
			{
				sum=sum+int(str_array[i]-96);			
			}
		}
		char sum_array[MAX_SIZE]={NULL};
		sprintf(sum_array,"%d",sum);
		strcpy(str_array,sum_array);
		
	}while(strlen(str_array)!=1);
		return sum;

}

int  main()
{
	char a_str[MAX_SIZE]={NULL},b_str[MAX_SIZE]={NULL};
	float a_val=0,b_val=0;
	while(cin>>a_str>>b_str)
	{
		for(int i=0;i<=1;i++)
		{
			if(i==0)
			 a_val=caluated_str_value(a_str);
			 else
			 b_val=caluated_str_value(b_str);
		
		}
		if(a_val>b_val)
		{
			float ans=b_val/a_val*100;
			cout<<fixed<<setprecision(2)<<ans<<" %"<<endl;
		}
		else
		{
			float ans=a_val/b_val*100;
			cout<<fixed<<setprecision(2)<<ans<<" %"<<endl;
		
		}
	
	

	
	}

	return 0;
}

[lighted]

Your code gets Compile Error. Change line

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int _tmain(int argc, _TCHAR* argv[])

You must use int main(), so change to

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int main()

Remove line

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#include "stdafx.h"

Change reading to

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while(gets(a_str)  &&  gets(b_str))

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It is difficult to read your code. Use code tags. Like this.

[longted]

can you tell me why i use while(gets(a_str) && gets(b_str) is accept but use while(cin>>a_str>>b _str) is wrong answer

[lighted]

If you want to use cin. Try this way.

Code: Select all

 while(cin.get(a_str,MAX_SIZE),cin.ignore(),cin.get(b_str,MAX_SIZE),cin.ignore())

[longted]

ths,i want to understand to use different between cin and gets

[lighted]

At the end of each line there is newline character '\n'.
gets reads line until newline, then newline character is extracted from standart input stream.

As i understand when you use just cin it reads string from input stream but newline character is not extracted from input stream, it is leaved there.
cin.ignore() extracts or removes newline character from input stream.

So to handle newline characters correct you must use gets or cin + cin.ignore together.
There can be other ways to do this. I showed you 2 ways.

[Nood]

I got TLE, don't know why!

Here's my code

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Removed After AC

[Xenon Kfr]

why compilation error?

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#include<stdio.h>
int digit(int);
int main()
{
    int na,nb,sum1,sum,i,j,value;
    float r;
    char a[25],b[25];
    while(gets(a))
    {
        gets(b);
        sum=0;
        for(i=0;a[i];i++)
        {
            if(a[i]>64 && a[i]<91)
            {
                value=a[i]-64;
            }
            else if(a[i]>96 && a[i]<123)
            {
                value=a[i]-96;
            }
            sum=sum+value;
        }
        na=digit(sum);
        sum1=0;
        for(i=0;b[i];i++)
        {
            if(b[i]>64 && b[i]<91)
            {
                value=b[i]-64;
            }
            else if(b[i]>96 && b[i]<123)
            {
                value=b[i]-96;
            }
            sum1=sum1+value;
        }
        nb=digit(sum1);
        if(na<nb)
            r=(float)na/(float)nb*100.00;
        else
            r=(float)nb/(float)na*100.00;
        printf("%.2f\n",r);
    }
    return 0;
}
int digit(int x)
{
    int n,i,sum,d;
    while(1)
    {
        for(i=1;;i*=10)
        {
            if((x/i>0) && (x/i<10))
                break;
        }
        n=i;sum=0;
        for(i=n;i>0;i=i/10)
        {
            d=x/i;
            sum=sum+d;
            x=x-i*d;
        }
        if(sum<10 && sum>0)
            return sum;
        x=sum;
    }
    return sum;
}

[lighted]

It gives WA, not CE. Check it again

[Xenon Kfr]

i did check it again.its CE.and why its wrong?

[lighted]

Copy/paste code from post above, not from your pc. It gives WA with ANSI C 4.8.2, C++ 4.8.2, C++11 4.8.2. You can get CE only if you send it with JAVA or PASCAL.

Look at your outputs carefully. They don't match. You missed "%" symbol. Don't forget to remove your codes after getting acccepted.

[Xenon Kfr]

its WA .why?

Code: Select all

#include<stdio.h>
int digit(int);
int main()
{
    int na,nb,sum1,sum,i,j,value;
    float r;
    char a[25],b[25];
    while(gets(a))
    {
        gets(b);
        sum=0;
        for(i=0;a[i];i++)
        {
            if(a[i]>64 && a[i]<91)
            {
                value=a[i]-64;
            }
            else if(a[i]>96 && a[i]<123)
            {
                value=a[i]-96;
            }
            sum=sum+value;
        }
        na=digit(sum);
        sum1=0;
        for(i=0;b[i];i++)
        {
            if(b[i]>64 && b[i]<91)
            {
                value=b[i]-64;
            }
            else if(b[i]>96 && b[i]<123)
            {
                value=b[i]-96;
            }
            sum1=sum1+value;
        }
        nb=digit(sum1);
        if(na<nb)
            r=(float)na/(float)nb*100.00;
        else
            r=(float)nb/(float)na*100.00;
        printf("%.2f %%\n",r);
    }
    return 0;
}
int digit(int x)
{
    int n,i,sum,d;
    while(1)
    {
        for(i=1;;i*=10)
        {
            if((x/i>0) && (x/i<10))
                break;
        }
        n=i;sum=0;
        for(i=n;i>0;i=i/10)
        {
            d=x/i;
            sum=sum+d;
            x=x-i*d;
        }
        if(sum<10 && sum>0)
            return sum;
        x=sum;
    }
    return sum;
}

[lighted]

Input

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Xenon Kfr
Love Calculator

Acc Output

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87.50 %

Also check input here. http://www.udebug.com/UVa/10424

Your input will be two names. Each name holds not more than 25 characters

So you should make a and b of length 26. One char for '/0'.

[Xenon Kfr]

thanx a lot

[MD.AMINUL ISLAM]

Why getting WA ????

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#include<stdio.h>
#include<string.h>
#include<ctype.h>
int digitsum(int n);
int main()
{
    char s1[40],s2[40];
    int i,j,g,sum=0,sum2=0,a,b,l;
    double p,c,d;
    //freopen("1.txt", "r", stdin);
    while(gets(s1))
    {
        gets(s2);
        sum=0,sum2=0,p=0.0,c=0.0,d=0.0;
        //l=strlen(s1);
        for(i=0;i<strlen(s1);i++)
        {
            if(isalpha(s1[i]))
            {
                if(islower(s1[i]))
                    sum+=s1[i]+1-'a';
                else sum+=s1[i]+1-'A';
            }
        }
      // printf("%d\n%d\n",sum,l);
        a=digitsum(sum);
        /*while(a>9)
        {
           a=digitsum(a);
        }*/
        //printf("%d\n",a);
        for(j=0;j<strlen(s2);j++)
        {
            if(isalpha(s2[j]))
            {
                if(islower(s2[j]))
                    sum2+=s2[j]+1-'a';
                else sum2+=s2[j]+1-'A';
            }
        }
        //printf("%d\n",sum2);

        b=digitsum(sum2);
       /* while(b>9)
        {
            b=digitsum(b);
        }*/
       //printf("%d\n", b);
        c=a,d=b;
        p=(d*100.0)/c;
        if(p<100.0)
        printf("%.2lf %%\n",p);
        else printf("100.00 %%\n");
    }
    return 0;
}
int digitsum(int n)
{
   int s=0;
   if(n==0) return 0;
   else
   {
       if((s=n%10+digitsum(n/10))>9)
            return digitsum((s=n%10+digitsum(n/10)));
       else
        return (s=n%10+digitsum(n/10));
   }
   return s;
}
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