272 - TEX Quotes

[brianfry713]

Don't print a space at the end of a line.

[NAbdulla]

Whats wrong with my code

Code: Select all

#include <stdio.h>
#include <string.h>
int main()
{
    int i, j, k, l1, f;
    char in[10000], out[10000];
    while(gets(in) != EOF){
        l1 = strlen(in);
        f = 0;
        for(i = 0, j = 0; i < l1; i++){
            if(in[i] == '"' && f == 0){
                out[j] = '`';
                j++;
                out[j] = '`';
                j++;
                f = 1;
            }
            else if(in[i] == '"' && f == 1){
                out[j] = 39;
                j++;
                out[j] = 39;
                j++;
                f = 0;
            }
            else{
                out[j] = in[i];
                j++;
            }
        }
        out[j] == '\0';
        printf("%s\n", out);
    }
    return 0;
}

[brianfry713]

gets will not return EOF (-1). You could instead use NULL (0):
while(gets(in) != NULL) {

[NAbdulla]

Thanks, but there was another wrong, that was for each line I was putting f = 0.

[sarowar_csecu]

What's wrong! Getting WA. Please help.

Code: Select all

Removed after AC
 

[brianfry713]

Remove the first line: /*
Always print a newline char at the end of the last line.

[sarowar_csecu]

Accepted. Thanks

[RocknJon]

Hello, I sent my code like 6 times but I keep gettin Wrong Answer, please help me. Btw is C++

Code: Select all

#include <stdio.h>
#include <string.h>
//#define MAX 10000000

int main()
{
	char Original[1000000]="";
	int par=0;
	while(gets(Original))
	{
		int l=strlen(Original);
		for (int i = 0; i < l; i++)
		{
			if(Original[i]=='"')
			{
				par++;
				if(par%2==0)
				{
					printf("%c%c",39,39);
				}
				else
				{
					printf("%c%c",96,96);
				}

			}
			else
			{
				printf("%c",Original[i]);
			}
		}
	}
	return 0;
}

[lighted]

Print newline after each line processing.

[lazyplatoon]

I'm getting wrong answer... Can you please tell me what's the problem??

Code: Select all

//Removed after AC

[lighted]

Don't set count to 0 in loop. It should be set to 0 once, before loop. Change line to

Code: Select all

if (str[i] == '"') {

[lazyplatoon]

Don't set count to 0 in loop. It should be set to 0 once, before loop. Change line to

Code: Select all

if (str[i] == '"') {

Thanks man... Silly mistake...

[FahimShahriar]

Code: Select all

#include <stdio.h>
#include <string.h>
int main()
{
    int i,j=0,f;
    char a[1000],b[1000];
    gets(a);
    f=0;
    for (i=0;a[i]!='\0';i++)
    {
        if (a[i]=='"'&& f==0)
        {
            b[j]='`';
            j++;
            b[j]='`';
            j++;
            f=1;
        }
        else if (a[i]=='"' && f==1)
        {   b[j]=39;
            j++;
            b[j]=39;
            j++;
            f=0;
        }
        else
            {
                b[j]=a[i];
                j++;
            }
    }
    b[j]='\0';
    printf("%s",b);
    return 0;
}

[brianfry713]

Doesn't match the sample I/O, your code is only printing the first line.

[BaronRED]

Hi guys, I've tried what I think is the naive approach but I can't figure out why it takes so much to execute (I got TLE) and how to improve it, can somebody help me? I've seen so many complicated programs for this problem while mine is very simple, what I'm ignoring?
Instead of reading the whole input, process it and print it out, my program proceed char by char; what I can think of is that start reading from stdin and start printing on stdout might take some time instead of read all and print all, but dunno...
Thanks in advance!

Code: Select all

#include <stdio.h>

int main (){
	bool quotes = 0; //true = the first (``) - false = the second ('')
	char c;
	do {
		scanf ("%c", &c);
		if (c != '"'){
			printf("%c", c);
		} else {
			quotes = !quotes;
			printf ((quotes)? "``" : "''");
		}
	} while (c != EOF);
	return 0;
}