10451 - Ancient Village Sports

[deena sultana]

Sohel,
So kind of u.
THANK U SO MUCH. I get AC now .
take care n keep well, ok?

[ankit.arora]

My code gives WA...... Please help

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#include<iostream>
#include<cmath>
using namespace std;

int main()
{
         double n,ang,area,r,r2,rim,areaspec,areaoffi,d1;
         unsigned long long ar;
         int count=0;
         
         while(cin>>n>>area)
         {
                if(n<3)
                break;
                           
                count++;
               
                ang=((2*acos(0.0))/n);
                r=sqrt((area/(n*cos(ang)*sin(ang))));
               
                r2=r*cos(ang);
               
                areaspec=((2*acos(0.0)*r*r)-area);
                areaoffi=(area-(2*acos(0.0)*r2*r2));
               
                ar=(unsigned long long)(areaspec*100000);
                d1=(areaspec*100000)-ar;
                if(d1>0.5 ||(d1==0.5 && (unsigned long long)ar%2!=0))
                ar++;
                cout<<(double)ar/100000<<" ";
               
                ar=(unsigned long long)(areaoffi*100000);
                d1=(areaoffi*100000)-ar;
                if(d1>0.5 ||(d1==0.5 && (unsigned long long)ar%2!=0))
                ar++;
                cout<<(double)ar/100000<<"\n";
               
               
         }
} 

[Jan]

Forgot to print caseno?

[abhineet.bansal]

Someone please look at my code and tell me why i get WA....
i have tried a lot....

Code: Select all

// Ancient Village Sports 10451

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    int ncase=0;
    int n;
    while(cin>>n)
    {
        ncase++;
        long double area;
        if(n<3) break;
        cin>>area;
        long double r = sqrt((2.0*area/(long double)n)/sin(4.0*acos(0.0)/(long double)n));
        long double ri = r*cos(2.0*acos(0.0)/(long double)n);
        r = (2.0*acos(0.0)*r*r) - area;
        ri = area - (2.0*acos(0.0)*ri*ri);
        r = 100000.0*r;
        unsigned long long t = (unsigned long long)r;
        if(((r-(long double)t)>0.5)||((r-(long double)t)==0.5 && t%2!=0))
          t++;
        r = (long double)t/100000.0;
        ri = 100000.0*ri;
        t = (unsigned long long)ri;
        if(((ri-(long double)t)>0.5)||((ri-(long double)t)==0.5 && t%2!=0))
            t++;
        ri = (long double)t/100000.0;
        cout<<"Case "<<ncase<<": "<<r<<" "<<ri<<endl;
    }
    return 0;
}

Thanx a lot...

[Hikari9]

This is a precision-error prone problem. I had to tweak a lot in my code to get Accepted.
Well, after a lot of WAs, I found out the precision of the judge for this problem.

1. Read and compute values as doubles
2. Print answer as a float
3. Don't use epsilons

There are many formulas for this problem, all of which work. However, you may get trapped in the precision error so heed this advice.

Just change

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printf( "Case %d: %.5lf %.5lf\n", ++CASES, a, b );

into

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printf( "Case %d: %.5f %.5f\n", ++CASES, a, b );

or maybe explicitly cast your answer as float

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cout.precision(5);
cout << fixed;
cout << "Case " << ++CASES << ": " << (float)a << " " << (float)b << endl;

Hope this helps

[AbyssalGreed]

please help me with my code.
I don't know why i'm always getting a WA..
please help


import java.util.*;
import java.math.*;
import java.io.*;
import java.text.*;

class Main
{
public static void main(String args[])throws Exception
{
Code Remove after getting AC in uva
}
}

[lighted]

Don't read from file. Read from standart input

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Scanner sc = new Scanner(System.in);

Be careful with integer division. You must convert long to double. Change lines

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double Spectator = (2*PI*c)/(b*(Math.sin(Math.toRadians((double)360/b))));
double Official = (c*PI)/(b*(Math.tan(Math.toRadians((double)180/b))));

Or

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double Spectator = (2*PI*c)/(b*(Math.sin(Math.toRadians(360.0/b))));
double Official = (c*PI)/(b*(Math.tan(Math.toRadians(180.0/b))));

Don't forget to remove your code after getting accepted.

[AbyssalGreed]

thanks for helping