10849 - Move the bishop

[Prianka]

Many many thanks to Maruf.
But it is just a stupid joke nothing else.
If there is no newline so why the judges gave this condition-------

he input begins with a single integer, C, indicating the number of test cases following, each of them as described below. This line is followed by a blank line, and there is also a blank line between two consecutive test cases.

Any way thanks again to help me a lot.
Thanks.

[abid_iut]

what is the problem in this code
I think it goes with the algorithm given in previous threads.
here is the code:

Code: Select all

#include<stdio.h>

int main()
{
	long x1,y1,x2,y2,n,num,N;
	scanf("%ld",&n);
	for(int it=0;it<n;it++){
		scanf("%ld",&num);
		scanf("%ld",&N);
		for(int i=0;i<num;i++){
			scanf("%ld %ld %ld %ld",&x1,&y1,&x2,&y2);
			if(x1 == x2 == y1 == y2){printf("0\n");continue;}
			else if(x1==y1 && x2==y2){printf("1\n");continue;}
			if((((x1+y1)%2==0) && ((x2+y2)%2==0)) || (((x1+y1)%2==1) && ((x2+y2)%2==1))){
				if(x1+y1 == x2+y2)printf("1\n");
				else printf("2\n");
			}
			else printf("no move\n");
		}
	}
	return 0;
}

pls help

[helloneo]

Try this case..

Code: Select all

1

1
4
1 2 2 3

My output is

Code: Select all

1

[uDebug]

Here's some input / output that I found useful during testing / debugging.

Input:

Code: Select all

2

3
100000000
3 6 3 6
100000000 100000000 1 1
56724 9862 8746 190234

20
8
5 5 3 8
5 5 8 3
5 5 7 7
5 5 4 4
6 6 2 7
6 6 7 2
6 6 1 1
6 6 4 4
2 7 2 2
2 7 3 3
2 7 8 1
2 7 1 8
5 8 2 2
5 8 7 7
5 8 3 2
5 8 8 1
6 1 1 6
5 5 8 8
3 4 1 2
7 6 8 4

AC Output:

Code: Select all

0
1
2
no move
no move
1
1
no move
no move
1
1
no move
no move
1
1
no move
no move
2
2
1
1
1
no move

[axelblaze]

I have no idea why I'm getting WA...
Please help. thanks in advance..!

Code: Select all

removed after ac

[waheed]

i get WA with this code help plz

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;


public class Main {
public static void main (String [] args) throws NumberFormatException, IOException{
BufferedReader buffer = new BufferedReader(new InputStreamReader(System.in));
int n = Integer.parseInt(buffer.readLine());
buffer.readLine();
int s ;
int t ;
int u ;
int v ;
for(int i = 0;i<n;i++){
int x = Integer.parseInt(buffer.readLine());
int y = Integer.parseInt(buffer.readLine());
for(int j = 0;j<x;j++){
StringTokenizer f =new StringTokenizer(buffer.readLine());
int a = Integer.parseInt(f.nextToken());
int b = Integer.parseInt(f.nextToken());
int c = Integer.parseInt(f.nextToken());
int d = Integer.parseInt(f.nextToken());
s = a+b;
t = c+d;
u = a-b;
v = c-d ;
if((s%2==0 && t%2!=0)||(s%2!=0 && t%2==0) )
System.out.println("no move");
else
if(s!=t && u!=v)
System.out.println(2);
else
System.out.println(1);

}
buffer.readLine();

}

}

}

[uDebug]

I have no idea why I'm getting WA...
Please help. thanks in advance..!

Try running the test case on the post above yours and do a diff of the output files. (Hint: You're printing extra newlines.)

[lighted]

If there is a thread about your problem, please use it.
Don't open new thread. Use search first by problem number (10849 for this problem)
http://acm.uva.es/board/search.php?keyw ... 45b4825c8d

For this problem there is existing thread
http://acm.uva.es/board/viewtopic.php?f ... 45b4825c8d
You can check your program for input/output tests posted here.

Also you must post for this problem in the Volume CVIII.

[waheed]

done

[uDebug]

i fed up with this problem ,i have no idea why i get WA HELP PLZZZZ

Use code tags to make your code more readable.

Also, try moving the "buffer.readLine();" inside the for loop like so

Code: Select all

public class Main {
	public static void main(String[] args) throws NumberFormatException,
			IOException {
		BufferedReader buffer = new BufferedReader(new InputStreamReader(
				System.in));
		long n = Long.parseLong(buffer.readLine());
		long s;
		long t;
		long u;
		long v;
		for (int i = 0; i < n; i++) {
			// Moved readline inside for loop
			buffer.readLine();
			long x = Long.parseLong(buffer.readLine());
			long y = Long.parseLong(buffer.readLine());
			...

[lighted]

Are you fed up with getting Accepted?
I got accepted by sending your java solution.
What is your problem? Check it once again.

[waheed]

ops i don't what happenend it is a miracle i run it thousand times and didn't work now it works any way thaaaaaaaaaaaaaaaaaaanks

[lighted]

It will be good if you remove your code after getting accepted

[uDebug]

It will be good if you remove your code after getting accepted

You said it! A significant percentage of people post code when asking for help and then leave it on there once they've figured out the solution. The forum is full of nearly AC (or even AC) code like that. Requesting people to remove their code hardly every works. But perhaps it's worth trying.

[lighted]

I hope it will help to those people who will solve problems on uva for a long time.