## 10929 - You can say 11

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Faithkeeper_Rangwan
New poster
Posts: 12
Joined: Sun Jul 07, 2013 7:32 pm

### Re: 10929 - You can say 11

Code: Select all

``````import java.util.*;
import java.math.*;
class Main
{
public static void main(String[] args)
{
BigInteger a,b;
Scanner sc = new Scanner(System.in);
a = sc.nextBigInteger();
while(!a.equals(BigInteger.ZERO))
{
b =a.mod(BigInteger.valueOf(11));
if(b.equals(BigInteger.ZERO)) System.out.println(a+" is a multiple of 11.");
else System.out.println(a+" is not a multiple of 11.");
a = sc.nextBigInteger();
}
}
}
``````
Also got WA with this one, don't know how to fix this brianfry713
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Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 10929 - You can say 11

input:

Code: Select all

``````01
0
``````
output should be

Code: Select all

``01 is not a multiple of 11.``
Check input and AC output for thousands of problems on uDebug!

Faithkeeper_Rangwan
New poster
Posts: 12
Joined: Sun Jul 07, 2013 7:32 pm

### Re: 10929 - You can say 11

brianfry713 wrote:input:

Code: Select all

``````01
0
``````
output should be

Code: Select all

``01 is not a multiple of 11.``
AC'd

Thanks.

woaraka92
New poster
Posts: 9
Joined: Sun Oct 20, 2013 6:50 pm

### UVA 10929

#include<stdio.h>
#include<string.h>

int main(){
char a;
int i,sum;
while(1){
scanf("%s",a);
if(strcmp(a,"0")==0)
break;

sum=0;
for(i=0;a!='\0';i++){
sum=sum*10+a-48;
if(sum<11){
i++;
sum=sum*10+a-48;
}

if(sum>10)
sum=sum%11;
}

if(sum==0)
printf("%s is a multiple of 11.\n",a);
else
printf("%s is not a multiple of 11.\n",a);

}
return 0;
}

woaraka92
New poster
Posts: 9
Joined: Sun Oct 20, 2013 6:50 pm

### Re: UVA 10929

whats the problem in this code?

brianfry713
Guru
Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: UVA 10929

110 is a multiple of 11.
Check input and AC output for thousands of problems on uDebug!

woaraka92
New poster
Posts: 9
Joined: Sun Oct 20, 2013 6:50 pm

### Re: UVA 10929

Thanks brianfry713..

jddantes
Learning poster
Posts: 73
Joined: Sat Mar 08, 2014 8:55 am

### Re: 10929 - You can say 11

What's wrong with mine?
Also by positive number do they mean positive integers?

Code: Select all

``````#include <stdio.h>
#include <string.h>
int main()
{
char number;
while(fgets(number, 1005, stdin)!=NULL)
{
number[strlen(number)-1] = 0;

if(number == '0' && number == 0)
{
return 0;
}

int sum = 0;
int i = 0;
for(i=0; number[i];i++)
{

if(i%2 == 0)
{
sum+=number[i] - '0';
}
else
{
sum-=number[i] - '0';
}

//printf("%d %d\n",sum, number[i] - '0');
}

if (sum % 11 == 0)
{
printf("%s is a multiple of 11.\n",number);
}
else
{
printf("%s is not a multiple of 11.\n",number);
}
}

return 0;
}
``````

brianfry713
Guru
Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 10929 - You can say 11

That is AC code.
Yes they mean positive integers.
Check input and AC output for thousands of problems on uDebug!

jddantes
Learning poster
Posts: 73
Joined: Sat Mar 08, 2014 8:55 am

### Re: 10929 - You can say 11

Why is mine WA?

Code: Select all

``````#include <stdio.h>
#include <string.h>
int main()
{
char number;
while(fgets(number, 1005, stdin)!=NULL)
{
number[strlen(number)-1] = 0;

if(number == '0' && number == 0)
{
return 0;
}

int sum = 0;
int i = 0;
for(i=0; number[i];i++)
{

if(i%2 == 0)
{
sum+=number[i] - '0';
}
else
{
sum-=number[i] - '0';
}

//printf("%d %d\n",sum, number[i] - '0');
}

if (sum % 11 == 0)
{
printf("%s is a multiple of 11.\n",number);
}
else
{
printf("%s is not a multiple of 11.\n",number);
}
}

return 0;
}
``````

brianfry713
Guru
Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 10929 - You can say 11

That is AC code.
Check input and AC output for thousands of problems on uDebug!

uDebug
A great helper
Posts: 475
Joined: Tue Jul 24, 2012 4:23 pm

### Re: 10929 - You can say 11

So, for this problem, it turns out that there are two outputs that are both accepted.

For, the following input

Code: Select all

``````            112233
00000000030800
2937
323455693
5038297
00000112234
00112
0
``````
AC Output #1:

Code: Select all

``````112233 is a multiple of 11.
00000000030800 is a multiple of 11.
2937 is a multiple of 11.
323455693 is a multiple of 11.
5038297 is a multiple of 11.
00000112234 is not a multiple of 11.
00112 is not a multiple of 11.``````
AC Output #2:

Code: Select all

``````            112233               is a multiple of 11.
00000000030800 is a multiple of 11.
2937                            is a multiple of 11.
323455693                  is not a multiple of 11.
5038297           is a multiple of 11.
00000112234      is not a multiple of 11.
00112             is not a multiple of 11.
``````
Check input and AC output for over 7,500 problems on uDebug!

brianfry713
Guru
Posts: 5947
Joined: Thu Sep 01, 2011 9:09 am
Location: San Jose, CA, USA

### Re: 10929 - You can say 11

There probably aren't spaces in the judge's input.
Check input and AC output for thousands of problems on uDebug!

uDebug
A great helper
Posts: 475
Joined: Tue Jul 24, 2012 4:23 pm

### Re: 10929 - You can say 11

brianfry713 wrote:There probably aren't spaces in the judge's input.
That makes sense. Thanks.
Check input and AC output for over 7,500 problems on uDebug!

jddantes
Learning poster
Posts: 73
Joined: Sat Mar 08, 2014 8:55 am

### Re: 10929 - You can say 11

Why is mine not accepted?

Code: Select all

``````#include <stdio.h>
#include <string.h>
int main()
{
char number;
while(fgets(number, 1005, stdin)!=NULL)
{
number[strlen(number)-1] = 0;

if(number == '0' && number == 0)
{
return 0;
}

int sum = 0;
int i = 0;
for(i=0; number[i];i++)
{

if(i%2 == 0)
{
sum+=number[i] - '0';
}
else
{
sum-=number[i] - '0';
}

//printf("%d %d\n",sum, number[i] - '0');
}

if (sum % 11 == 0)
{
printf("%s is a multiple of 11.\n",number);
}
else
{
printf("%s is not a multiple of 11.\n",number);
}
}

return 0;
}

``````