272 - TEX Quotes

[Ghaverves]

Can anyone help with my code?
It's such a simple question and I keep getting wrong answer.
It is really frustrating.

Code: Select all

removed after AC

[sohel]

I think you are printing an additional character when you reach the end of file.
Try putting the input in a file and read if from there. You should be able to see the error.

[Ghaverves]

Thanks
you caught the error

[MotherTiger]

I got Runtime Error so many times, but don't know why!
Can anyone tell me what goes wrong please?
Thanks alot!

Code: Select all

#include <stdio.h>

int main()
{
	int counter = 0, flag = 0;
	char text[5000] = {0}, x;
	while((x = getchar()) != EOF)
	{
		if(x == '\"')
		{
			if(flag == 0)
			{
				text[counter] = '`';
				counter++;
				text[counter] = '`';
				flag = 1;
			}
			else
			{
				text[counter] = '\'';
				counter++;
				text[counter] = '\'';
				flag = 0;
			}
		}
		else
		{
			text[counter] = x;
		}
		counter++;
	}
	printf("%s", text);
	return 0;
}

[fernandohbc]

I've just compiled and runned your code and turns out that it works fine in my box.
I even compared your output against my AC'd code's output and they are identical.
Have you searched for any additional input/output to test your code with?

[MotherTiger]

I've just compiled and runned your code and turns out that it works fine in my box.
I even compared your output against my AC'd code's output and they are identical.
Have you searched for any additional input/output to test your code with?

Thanks for your reply!
Yes, i've tried some additional input/output and the code works fine.
That's wierd!

[sadia_atique]

I have no idea why my code gets WA,please,can anyone kindly help me??

Code: Select all

#include<stdio.h>
int main()
{
    char ch;
    int i=0;
    while(ch=getc(stdin)!=EOF)
    {
         if((int)ch==34)
         {
                        if (i==0)
                        {
                                 printf("``");
                                 i=1;
                        }
                        else if(i==1)
                        {
                             printf("''");
                             i=0;
                        }
         }
         else printf("%c",ch);
    }
    return 0;
}

[sohel]

The operators = and != have got the same precedence, however they are right associative.

That means ch = getc(stdin) != EOF is treated as ch = ( getc(stdin) != EOF ) and thus ch will always be assigned with a boolean (0/1) value.
You can get around this problem by enclosing the first two terms with parenthesis, something like ( ch = getc(stdin) ) != EOF

Hope it helps.

[sadia_atique]

Thanks a lot,it worked
How stupid mistake it was!!

[kia.masster]

Hi guys! What is the wrong of this code?

Code: Select all

#include <iostream>
#include <cstring>
#include <string>

using namespace std;

string s;

void Shift(int i){
	s += s[s.length() - 1];
	for (int j = s.length() - 2; j > i; j--)
		s[j + 1] = s[j];
}

int main(){
	while (getline(cin, s))
	{
		if (s.length() > 0)
		{
			int j = 0;
			int b = s.length();
			int z = 0;
			int ord = 39;
			for (int i = 0; i < b; i++)
			{
				int a = s[i + z];
				if (a == 34)
				{
					j++;
					if (j % 2 == 1)
					{
						s[i + z] = '`';
						Shift(i + z);
						s[i + z + 1] = '`';
						z++;
					}
					else
					{
						s[i + z] = ord;
						Shift(i + z);
						s[i + z + 1] = ord;
						z++;
					}
				}
			}
			cout << s << endl;
		}
	}
}

[brianfry713]

kia.masster I can see you already figured out that you weren't closing the quotes correctly across multiple lines.

[islamzee]

PLEASE HELP! getting crazy with WA all day long for this! i know there might be a shorter n easier way, bt what's specifically wrong with my code??

char str[1000000];

#include<stdio.h>
#include<string.h>

int main()
{
int i,j,count=0;

while(gets(str))
{
//count=0;

for(i=0;str;i++)
{
if(str!='"') printf("%c",str);

else
{
count=0;
j=i+1;
count++;

while(str[j])
{
if(str[j]=='"')
{
count++;
break;
}
j++;
}

if(count%2==0)
{
printf("``");
for(j=i+1;str[j]!='"';j++) printf("%c",str[j]);
printf("''");

i=j;
count=0;
}

else
{
if(str[i+1]==NULL) printf("''");
else printf("``");
}
}
}
printf("\n");

for(i=0;i<2000;i++) str=NULL;
}

return 0;
}

[islamzee]

one another thing...if input is [this"]
then would the last " be replaced by `` or ' ' ??

[brianfry713]

Run your code and do a diff against the sample I/O. It doesn't match line 2.

[maruf.2hin]

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getting wrong answer....... for both code

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Accepted...............

and also for this.....

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 Accepteed...................