494 - Kindergarten Counting Game

[problem]

hi everybody at last i solve this problem.i only change char t[30000].

[miko'mized]

Code: Select all

#include <iostream>

using namespace std;

char buff;
int words;
bool is;

int main()  {
    while(!cin.eof())   {
        buff = cin.get();
        while(buff!='\n' && buff!=EOF)   {
            if( ( buff >= 'a' && buff <= 'z') || (buff >= 'A' && buff <= 'Z') )    {
                if(!is)  {
                    is = true;
                    words++;
                }
            }
            else is = false;
            buff = cin.get();
        }
        cout << words << endl;
        words = 0;
        is = false;
    }
    return 0;
}

im sure that works, but dont know why it gets WA.

[UFP2161]

The last line of the input will look something like:

word1 word2(\n)
(EOF)

Currently, your program will still parse the EOF, and thus output an extraneous "0".

Another possible problem is that you don't initialize the "words" variable to anything. In theory, it could be just some junk variable, though C++ normally sets everything to 0 for you, it's always better to initialize your own variables and not let the compiler do it.

[miko'mized]

thx. i considered that but i thought that input looks like this:

word word word('\n')
word word(EOF)

now i've got AC. thx again.

[ahmed hasan]

For using getlint(cin, ) it does not run properly in VC++
I used mingw.
I define a word as a consecutive sequence of charecter if its each charecter is a letter (upper/lower). Thats what i can do in computer.
I think the problem is there how I define words.
How can I know that a consecutive sequence of cheraters is an word?

Code: Select all

#include<iostream>
#include<string>
#include<cstring>

using std::string;
using std::cout;
using std::endl;
using std::cin;
using std::getline;

string ip;
int p1,p2;
int count;

void word_check(string word)
{
    char lc=word[word.length()-1];      //lc=last character.
    if(word.length()!=1)
    if(lc=='.'||lc=='?'||lc=='!')
        word.erase(word.length()-1,1);  //I just ignore the last character if its length is >1
    
    int f=1;
    for(int c1=0;c1<word.length();c1++)
    if( !((word[c1]>='A'&&word[c1]<='Z') || (word[c1]>='a'&&word[c1]<='z')) )
    {f=0;break;}                   //I defined word which has all its character between A->z or a->z
    if(f)count++;
}



int main()
{
    while(getline(cin,ip))
    {
        count=0;
        p1=p2=0;
        while(1)
        {
            while(p1<ip.length()&&ip[p1]==' ')p1++;p2=p1;
            if(p1>=ip.length())break;
            while(p2<ip.length()&&ip[p2]!=' ')p2++;
            word_check(ip.substr(p1,p2-p1));
            p1=p2;
        }
        cout<<count<<endl;
    }
    return 0;
}

[murkho]

I have considered tab also. But yet it gets WA. Please help me finding out the reason for WA>>>

Code: Select all

					/*BEGIN_OF_THE_SOURCE_CODE*/

#include<stdio.h>
#include<string.h>
#include<ctype.h>
#define N 10000


int main()
{
char str[N];
int i,len,word = 0,j;
while(gets(str) != NULL)
	{
	 word = 0;
	 len = strlen(str);

	 for(i = 0;i<len;i++)
		{
		 if( isalpha(str[i]) )
			{
			 for(j = i+1;j<len;j++)
				{
				 if(str[j] == ' '  || str[j] =='\t')
					{
					 word++;
					 break;
					}
			 
				}
			 if(j == len )
				 word++;
			 i = j;
		 
		 
			}
	 
	 
		}


	printf("%d\n",word);


	}



return 0;
}

				/*END_OF_THE_SOURCE_CODE*/

[mf]

Your code fails tests like these:

Code: Select all

abc@def
000a1b2c3d010
ch33se

The output should be:

Code: Select all

2
4
2

[refa]

Dear ACM members,

Could you please take a look at my code and tell me what's wrong because I am getting WA all the time and I read all the posts about it on the forum and it works properly with the example inputs. Thank you

Code: Select all

#include <iostream>
#include <string>
#include <cctype>

using namespace std;

int main()
{
  string line1="";
  long long int duzina=0;
  long long int count = 0;
  while(getline(cin, line1))
  {
    duzina= 0;
    count = 0;

    line1= " " + line1 + " ";
     for(long long int i=0; i<line1.length(); i++)
     {
      if(ispunct(line1[i])!=0 || isspace(line1[i])!=0 || isdigit(line1[i])!=0 || isblank(line1[i])!=0 || iscntrl(line1[i])!=0)
      {
       string word = "";
       word = line1.substr(duzina, i-duzina);
       if(isalpha(word[0]))
       {
           count++;
        }

       duzina=i+1;
      }
     }
    cout << count <<endl;
  };
  return 0;
};

I hope somebody will be able to help me out. Thx

Best regards,
Refik

[jaracz]

consider this algo

read string
if(isalpha(string[0]))count++;

and than in some loop until the one before last element of string(excluding '\0')

if( (isspace(string) && isalpha(string[i+1])) || (!isspace(string) && !isalpha(string)) && isalpha(string[i+1]) ) count++;

and you dont have to use long long( i used just int )
Hope it helps!

[Salman]

need some Test case

Code: Select all

/*
Name: kindergarden countiog  
Number: 494
Type :  adhoc
Process : ON
Author :Salman Zaman
Email : zamansalman@gmail.com
Date : 21/08/05 23:27




*/



#include<stdio.h>
//#include<string.h>



//#include<conio.h>



int main(){

       char ch;
       int flag,count;
       
  //     freopen("494.txt","r",stdin);
        
        flag=0;
        count=0;
        while(scanf("%c",&ch)!=EOF){
             

              if((ch>='A' && ch<='Z' )||(ch>='a' && ch<='z')){
                     flag++;   
              }    
              
              else if(ch=='\n'){
                      if(flag>0){
                          count++;
                      }    
                      printf("%d\n",count); 
                    flag=0;
                    count=0;
              }          
              else if(ch==' '){
                  if(flag>0){
                      count++;
                  }    
                  flag=0;
              }    
              
                 
                                                    
                           
   }    
     
   //getch();
   return 0;
}

[helloneo]

Code: Select all

abcd-efg

try this..
my output is 2

[thirddawn]

It's ok with sample input...however it can't work when I submit
---
#include <stdio.h>

int main() {
int space=0;
char a;
while (scanf("%c",&a)==1){
if (a==' '){
scanf("%c",&a);
if (a!='.')
space = space + 1;
}
if (a=='\n'){
printf ("%d\n",space+1);
space = 0;
}
}
return 0;
}

[Timo]

Try This Case :

input :
7 is a prime number.
hello world.
timo12345timo

output :
4
2
2

A ``word'' is defined as a consecutive sequence of letters (upper and/or lower case). Only letters -> 'a'-'z' and 'A'-'Z'.

I hope you will get AC.

[xintactox]

Hi everybody!
I don't know why it's getting CE, it compiles normally with g++ at cygwin...

Please take a look!

Thanks, my code follows

Code: Select all

#include <string>
#include <iostream>
#include <cctype>
//#include <iomanip>

using namespace std;

int main()
{
	string linha, cur_word;
	int count, char_count;	
	while(getline(cin, linha))
	{
		count = 0;
		char_count = 0;
		cur_word.clear();				
		while(char_count < linha.size())
		{
			while(linha[char_count] != ' ' && char_count < linha.size())
			{				
				cur_word += linha[char_count];
				char_count++;
			}			
			for(int i = 0; i < cur_word.size(); i++)
				if(isalpha(cur_word[i]))
				{					
					count++;
					break;
				}
			cur_word.clear();	
			char_count++;
		}
		cout<<count<<endl;		
	}
	return 0;
}

[Jan]

Remove the following function...

Code: Select all

cur_word.clear(); 

Hope it works.