602 - What Day Is It?

[Jalal]

9/3/1752 is an invalid date.
9/4/1752 is an invalid date.
9/5/1752 is an invalid date.
9/12/1752 is an invalid date.
Hope can help

dont take any input less 1 as a valid input

[Jalal]

I have send the exe to ur mail add.
cheak ur outputs
it cant be possible to write 0 month , or 0 day or 0 year

[angga888]

Thanx, Jalal I've received your exe file. Now, I'm gonna check my program.

angga888

[angga888]

Ok finally, I got Accepted on 602 problem . After I got your exe file, I just tried to test many inputs to your exe and compare the output to my program. Finally, I found that I've made miscalculation in deciding whether a year is a leap year or not before and after 1952.
By the way, thank you very much for your help.

Regards
Angga

[angga888]

Ok finally, I got Accepted on 602 problem . After I got your exe file, I just tried to test many inputs to your exe and compare the output to my program. Finally, I found that I've made miscalculation in deciding whether a year is a leap year or not before and after 1752.
By the way, thank you very much for your help.

Regards
Angga

[deddy one]

sorry to interrupt here
but I think "2 28 0"
is invalid date because the input are positive integers right??

I passed all the test case above, well, except for the first two
,even when I remove my date check condition, but the answer
from the first two cases up there doesn't match with mine

I've send the problem to the judge but I still don't know the
result yet due to the judge error right now.

[deddy one]

ok, I got AC
apparently "2 28 0" is not on the judge's test case

[TWEmp]

Output:

Code: Select all

January 1, 0 is a Thursday
January 1, 1 is a Saturday
March 1, 401 is a Friday
March 1, 801 is a Monday
February 29, 1000 is a Thursday
March 1, 1000 is a Friday
9/3/1752 is an invalid date.
9/13/1752 is an invalid date.

Do the days September 3rd 1752 until September 13th 1752 ever exist in the USA calendar?

These days aren't exist in US calendar.

Sorry for interupption, but doesn't year 0 not exist?

(I get Wrong answer in 602 either)

[raysa]

I think you may assume that there's no year 0 in the Judge's input,
since the year is always in positive numbers...
Well, I hope the following will help:

• 1/ AFTER September 13th 1752, there is cyclical pattern of date,
  that is: any year that is a multiple of 400 would have its
  first day fall on Saturday <"Math Magic", Scott Flansburg,
  1993>.
  Thus: January 1, 2000 is a Saturday
  January 1, 2400 is a Saturday
  January 1, 8400 is a Saturday
  So, every 400 years the same date is repeated:
  January 7, 1999 is a Thursday
  January 7, 5999 is a Thursday
  2/ Pay more attention to 28/29 Feb & 1 Mar, 31 Dec & 1 Jan when
  examining your code. Are those days related directly?

And, deddy one:

*********** Message was cut ***********

[due to a serious misunderstanding,
I apologize to my very friend, Deddy One,
for any words and insultings...
To everyone who's d-load or read this message
previously, forget all my sayings, coz
it's purely a failure of mine, and I regret it.]

Best regards,


raysa

[pywong]

what's wrong there? i can't see the bug

Code: Select all

#include<stdio.h>
#include<stdlib.h>


int main(void)
{
int day,month,year,yearsbetween,weekday,daysbetween;
int flag=1;

while(flag){
scanf("%d %d %d",&month,&day,&year);

if(!month && !day && !year)
flag=0;

else if(year <= 0 || day > 31 || day <= 0 || month > 12 || month <= 0)
printf("%d/%d/%d is an invalid date.\n",month,day,year);

else if(month == 4 || month == 6 || month == 9 || month == 11)
if (day >= 31)
printf("%d/%d/%d is an invalid date.\n",month,day,year);

else if(((year > 1752 && month == 2 && (year % 4 != 0 || (year % 400 != 0 && year % 100 == 0))) 
|| (year <= 1752 && year%4!=0 && month == 2)) && day > 28)
printf("%d/%d/%d is an invalid date.\n",month,day,year);

else if((year > 1752 && month==2 && ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) 
|| (year <= 1752 && year%4 == 0 && month == 2))&& day > 29)
printf("%d/%d/%d is an invalid date.\n",month,day,year);

else{
daysbetween = 0;
yearsbetween = year-1;

if(year > 1752 || (year ==1752 && month > 9 ) || (year == 1752 && month == 9 && day >= 14))
daysbetween = yearsbetween * 365 + yearsbetween / 4 - (yearsbetween / 100 - yearsbetween / 400);

else 
daysbetween = yearsbetween * 365 + yearsbetween / 4;

if(month <= 2)
daysbetween += (month-1)*31+day-1;

else if((year>1752 && ((year%4 == 0 && year%100!=0) || year%400==0))
|| year <=1752 && (year%4 == 0)){
if(month<=7){
if((month-1)%2==0)
daysbetween += (month-1)*30+(month-3)/2+day-1;
else
daysbetween += (month-1)*30+month/2-1+day-1;
}
else
daysbetween += 212+(month-8)*30+(month-7)/2+day;
}
else if((year>1752 && (year%4 != 0 || (year%100 == 0 && year%400 != 0)))
   || (year%4 != 0 && year<=1752)) {
if(month<=7){
if((month-1)%2==0)
daysbetween += (month-1)*30+(month-3)/2+day-2;
else
daysbetween += (month-1)*30+month/2-2+day-1;
}
else
daysbetween += 212+(month-8)*30+(month-7)/2+day-1;
}



switch(month){
case 1:
printf("January %d, %d is a ",day,year);
break;
case 2:
printf("February %d, %d is a ",day,year);
break;
case 3:
printf("March %d, %d is a ",day,year);
break;
case 4:
printf("April %d, %d is a ",day,year);
break;
case 5:
printf("May %d, %d is a ",day,year);
break;
case 6:
printf("June %d, %d is a ",day,year);
break; 
case 7:
printf("July %d, %d is a ",day,year);
break;
case 8:
printf("August %d, %d is a ",day,year);
break; 
case 9:
printf("September %d, %d is a ",day,year);
break;
case 10:
printf("October %d, %d is a ",day,year);
break; 
case 11:
printf("November %d, %d is a ",day,year);
break;
case 12:
printf("December %d, %d is a ",day,year);
break;
}


weekday=0;
if(year > 1752 || (year ==1752 && month > 9 ) || (year == 1752 && month == 9 && day >= 14))
weekday = daysbetween%7;

else 
weekday = (daysbetween + 5) % 7;

switch(weekday){
case 1:
printf("Tuesday\n");
break;
case 2:
printf("Wednesday\n");
break;
case 3:
printf("Thursday\n");
break;
case 4:
printf("Friday\n");
break;
case 5:
printf("Saturday\n");
break;
case 6:
printf("Sunday\n");
break;

case 0:
printf("Monday\n");
break;
}

}
}
return 0;
}

[deddy one]

--CUT--

[raysa]

*********** Message was cut ***********

[Dominik Michniewski]

I have one small question to raysa and deddy one :

Could you our private discussion posts exchange with private messages ? It's not place for this ....

Best regards
Dominik Michniewski

[beeplove]

Hello guys,

How did you get the reference of weekday?
I didn't see any reference of the name of weekday in the problem.
To get the name of the day, we should have a weekday name for a certain date.
Do we have it in problem 602?



best regards,
beeplove

[deddy one]

start with 1 1 1 being as Saturday.
that's my reference when solving this problem.

beware of the day after september 2 1752.