Here is my thought:
Code: Select all
infinity 1
Phi(x) = Sigma -------
k = 1 k(k+x).
infinity 1 - x
Let Phi1(x) = Phi(x) - Phi(1) = Sigma -------------.
k = 1 k(k+x)(k+1)
Let Phi2(x) = Phi1(x) / (1 - x)
and
Phi3(x) = Phi2(x) - Phi2(2).
precision error.