11185 - Ternary

[helloneo]

Try this case..

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3
-1

My output..

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10

[noor_aub]

I know My Algorithm is right, Then Why wrong answer

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Thanks Sohel. I forget the basic rules of Checking Input range.
Code Remove After A/C

[sohel]

What does your program output if the input is 0?
Hint: When you get WA in a problem, try to check the extreme cases first( In this case 0 and 1000000000)

[shaon_cse_cu08]

Can Someone Help me to determine what is wrong with my code... I have tested several case...

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Code Removed After AC....

I didn't think of the out put 0 when the case is 0...

[desperate12]

Why I have got WA I can't understand ... ...


#include <cstdio>
#include <iostream>
#include <cstdlib>
#include <cstring>

using namespace std;

int main()
{
long long a;
int ternary[200],i,j;
while(cin>>a)
{
if(a<0)
{
return 0;
}


if(a==0)
{
cout<<'0'<<endl;
}


else
{
for(i=0;a>0;i++)
{
ternary=a%3;
a=a/3;
}
for(j=i-1;j>=0;j--)
{
cout<<ternary[j];
}
}
cout<<endl;

}
return 0;
}

[brianfry713]

You're printing an extra newline for N=0.

[ratul.i]

Can anyone please tell me why I get runtime error for this code:

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#include<stdio.h>

void reverse(char *num, int count)
{
    while(count>=0)
    {
        printf("%c",num[count]);
        count--;
    }
}

int main()
{
    long int a;

    while(1)
    {
        scanf("%ld",&a);

        if(a<0)
            break;
        else if(a==0)
            printf("0\n");
        else
        {
            char *c; int i=0;
            while(a>=1)
            {
                long int x = a%3;
                c[i]=x+'0';
                a /= 3;
                i++;
            }
            reverse(c, i-1);
            printf("\n");
        }
    }

    return 0;
}

[brianfry713]

instead of

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char *c;

try

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char c[MAXSIZE];

[ratul.i]

Thnx, Thnx a lot brianfry713 ... Accepted

[Nahian37]

#include<stdio.h>
int main()
{
long n,i,j,a[50];
while(1)
{
scanf("%ld",&n);
if(n<=0) break;

for(i=0;n>0;i++)
{
a=n%3;
n=n/3;
}
for(j=i-1;j>=0;j--)
{
printf("%ld",a[j]);
}
printf("\n");
}
return 0;
}
whats the problem with this code?

[brianfry713]

For input:

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0
-1

AC output:

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0

[shuvrothpol1]

I've accepted this problem after 3 times compiler error.But i can't find out the problem why the code is compiled error. For this I ignore the string.h function and do the task manually and got accepted . But still now I am in fix why I can't use strrev() function ? my previous code given below:

#include <stdio.h>
#include <string.h>

int main ()

{
char str [50];
int n,i;
scanf ("%d",&n);

while (n>=0){

i=0;
if (n==0){
str=0;
str[i++]+=48;
}

while (n!=0){
str=n%3;
str[i++]+=48;
n/=3;
}
str='\0';

printf ("%s\n",strrev(str));
scanf ("%d",&n);

}
return 0;
}

[brianfry713]

strrev isn't supported in the judge's compiler.

[shuvrothpol1]

Tnx sir.....

[raihan_sust5]

any one please give some critical test case so i can test my code.....i am having a wrong answer..