401 - Palindromes

[Salehwar]

Oh well, I guess I'll never be able to solve it

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Removed after AC	

I added the new function MirroredChar2 to check if the character is a valid character since I haven't checked that, but still WA!

Thank you.

[ALEXANDRIA_2]

Hi Salehwar...
don't give up...
u only need to fix ur output statement

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cout<<str<<" -- is a regular plaindrome.\n"<<endl;

to

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cout<<str<<" -- is a regular palindrome.\n"<<endl;

and don't forget to remove ur code after get AC..

[Salehwar]

Oh my god!!!!! I feel so stupid! that was the mistake! I got AC

Thank you alot, and god bless you

[pushpit.saxena]

my code is::

#include<string>
#include <algorithm>
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;

bool CheckPalin(string x)
{
string y;
y.assign(x,0,x.size());
reverse(y.begin(),y.end());
if(y==x)
return true;
else
return false;
}
bool getMirror(string x,string character , string reverse1)
{
string y="";
char ch;
for(int i=0;i<x.size();i++)
if((ch=reverse1[character.find(x,0)])!=' ')
y+=ch;
else
return false;
reverse(y.begin(),y.end());
if(x==y)
return true;
return false;
}



int main()
{

int i;
string input;
fflush(stdin);
string character="ABCDEFGHIJKLMNOPQRSTUVWXYZ123456789";
string reverse1="A 3 HIL JM O 2TUVWXY51SE Z 8 ";
while(cin>>input)
{
bool m=getMirror(input,character,reverse1);
bool p=CheckPalin(input);
if(m && p)
cout<<input<<" -- is a mirrored palindrome.\n\n";
else if(m && !p)
cout<<input<<" -- is a mirroed string.\n\n";
else if(!m && p)
cout<<input<<" -- is a regular palindrome.\n\n";
else if(!m && !p)
cout<<input<<" -- is not a palindrome.\n\n";


fflush(stdin);
input.erase(input.begin(),input.end());
}

return 0;
}



can anyone find out where i m wrong....

[helloneo]

Try to search first.. and don't open a new thread if there is one already.

[pushpit.saxena]

my code is::

#include<string>
#include <algorithm>
#include <iostream>
#include <cstdio>
#include <cstdlib>
using namespace std;

bool CheckPalin(string x)
{
string y;
y.assign(x,0,x.size());
reverse(y.begin(),y.end());
if(y==x)
return true;
else
return false;
}
bool getMirror(string x,string character , string reverse1)
{
string y="";
char ch;
for(int i=0;i<x.size();i++)
if((ch=reverse1[character.find(x,0)])!=' ')
y+=ch;
else
return false;
reverse(y.begin(),y.end());
if(x==y)
return true;
return false;
}



int main()
{

int i;
string input;
fflush(stdin);
string character="ABCDEFGHIJKLMNOPQRSTUVWXYZ123456789";
string reverse1="A 3 HIL JM O 2TUVWXY51SE Z 8 ";
while(cin>>input)
{
bool m=getMirror(input,character,reverse1);
bool p=CheckPalin(input);
if(m && p)
cout<<input<<" -- is a mirrored palindrome.\n\n";
else if(m && !p)
cout<<input<<" -- is a mirroed string.\n\n";
else if(!m && p)
cout<<input<<" -- is a regular palindrome.\n\n";
else if(!m && !p)
cout<<input<<" -- is not a palindrome.\n\n";


fflush(stdin);
input.erase(input.begin(),input.end());
}

return 0;
}

please help me out....
I m getting WA...

[pushpit.saxena]

my code is in the above post......
plzzzzzz help me out I m getting WA!!

[ishtiaq ahmed]

Can anybody inform me where is my error? Waiting for your reply. Here is my code...

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the code is removed after ac.
Thanks to JAN bhia.

[Jan]

Try the cases.

Input:

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H22H
EVE
MJJM
J
YJ33JY

Output:

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H22H -- is a regular palindrome.

EVE -- is a regular palindrome.

MJJM -- is a regular palindrome.

J -- is a regular palindrome.

YJ33JY -- is a regular palindrome.

Hope these help.

[jesun]

I have tried all test cases given in the forum and got the desired results.
But I still get WA .Can anyone do the favor to take a look at my code &
figure out the bug?thanks in advance.

my code:

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REMOVED AFTER AC.

[Edited by : Jan] Use code tags.

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[Jan]

Try the cases.

Input:

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ISSEJML11JML322I
SV2OSV2
8SZSJYYL2528

Output:

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ISSEJML11JML322I -- is a mirrored string.

SV2OSV2 -- is a mirrored string.

8SZSJYYL2528 -- is a mirrored string.

Hope these help.

[jesun]

THANKS JAN bhai for your i/p set.It's really helpful!!I have missed {'s','2'} matching set.that's why I was getting WA.Thanks again for your help to get AC.
AND oh yes! I shall try to remember to use code tags if necessary.

[Mohiuddin]

i m getting w a. i can't understand what's the mistake? Plzz help..

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#include<stdio.h>
#include<string.h>
int main (void)
{
	int i,j,k,p,q;

	char ch[21];

	char ch1[21]={'A','E','H','I','J','L','M','O','S','T','U','V','W','X','Y','Z','1','2','3','5','8'};

	char ch2[21]={'A','3','H','I','L','J','M','O','2','T','U','V','W','X','Y','5','1','S','E','Z','8'};

	while(scanf("%s",ch)!=EOF)
	{
		p=0;

		q=0;

		for (i=0,j=strlen(ch)-1;i<=j/2;i++,j--)
		{
			if (ch[i]!=ch[j])
			{
				p=1;
				break;

			}
		}

		for (i=0,j=strlen(ch)-1;i<=j/2;i++,j--)
		{
			for(k=0;k<21;k++)
			{
				if (ch[i]==ch1[k])
				{
					break;

				}
			}
			
			if(k==21||ch[j]!=ch2[k])
			{
				q=1;
				break;
			}
		}

		if (p&&q)
		{
			printf ("%s -- is not a palindrome\n\n",ch);

		}
		else if(p==0&&q)
		{
			printf ("%s -- is a regular palindrome\n\n",ch);
		}
		else if (p&&q==0)
		{
			printf ("%s -- is a mirrored string\n\n",ch);
		}
		else if(p==0&&q==0)
		{
			printf ("%s -- is a mirrored palindrome\n\n",ch);
		}

	}
	return 0;
}

[Jan]

Your code doesn't even pass the samples. (Check carefully, a single 'full stop' can be dangerous)

[KaDeG]

Hello,
I tried solving Palindromes(401) problem. But keep getting Wrong Answer
although I searched the forums for test cases and in all of them my code worked correct.
Here is my code:

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#include <stdio.h>
#include <string.h>

/* check if a given string is palindrome */
int isPalindrome(char *s)
{
    int i, j;
    for (i = 0, j = strlen(s) - 1; i <= j; ++i, --j)     {
        if (s[i] != s[j])
            return 0;
    }
    return 1;
}

/* check if a given string is mirrored */
int isMirror(char *s)
{
    int i, j, c, k;
    char *nonReversed = "BCDFGKNPQR04679"; /* not valid characters.(unreversable characters) */

    /* reversed characters with their reverse */
    char mirror[21][2] = {{'A', 'A'}, {'E', '3'}, {'H', 'H'}, {'I', 'I'}, {'J', 'L'}, {'L', 'J'},
                            {'M', 'M'}, {'O', 'O'}, {'S', '2'}, {'T', 'T'}, {'U', 'U'}, {'V', 'V'},
                                {'W', 'W'}, {'X', 'X'}, {'Y', 'Y'}, {'Z', '5'}, {'1', '1'},
                                    {'2', 'S'}, {'3', 'E'}, {'5', 'Z'}, {'8', '8'}};


    /* if given string has a character that cannot be reversed 
     * the string is sure not mirrored */
    for (i = 0; s[i] != '\0'; ++i)      {
        c = s[i];
        for (j = 0; nonReversed[j] != '\0'; ++j)        {
            if (c == nonReversed[j])    {
                return 0;
            }
        }
    }

    for (i = 0, j = strlen(s) - 1; i <= j; ++i, --j)    {

        for (k = 0; k < 21; ++k)        {
            if (mirror[k][0] == s[i])   {
                if (s[j] != mirror[k][1])       {
                    return 0;
                }
                break;
            }
        }
    }
    return 1;
}

int main()
{
    char name[30];
    while (scanf("%s", name) != EOF)    {
        if (isPalindrome(name)) {
            if (isMirror(name)) {
                printf("%s -- is mirrored palindrome.\n");
            }
            else        {
                printf("%s -- is regular palindrome.\n");
            }
        }
        else    {
            if (isMirror(name)) {
                printf("%s -- is a mirrored string.\n");
            }
            else        {
                printf("%s -- is not a palindrome.\n");
            }
        }
        printf("\n");
    }
    return 0;
}

Any test-cases or code problems would be very help full.
Thanks,
KaDeG