11349 - Symmetric Matrix

[rio]

Actually, I'm having problems with understanding the problem description,
should i cut the matrix vertically or horizontally to make the comparison to check whether it's symmetric or not ????
sorry but I'm little confused here

and thanx in advance

No, you don't have to.
If the matrix is like:

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a b c d
e f g h
i j k l
m n o p

then you have to check;

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All the values are non-negative and a==p && b==o && c==n && ..

-----
Rio

[Obaida]

Removed

[Chirag Chheda]

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Code Acc!!!

[emotional blind]

Hi Chirag Chheda,
I think you should remove this line

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system("pause");

And another thing, you should initialize f=false.

[Chirag Chheda]

Thank you sir for replying.
I made the changes suggested by you. But still i am getting WA.
And as far as system("pause") is concerned the judge dont give WA for that as in all my submissions
i send the code without removing it.

Waiting for your reply

[emotional blind]

Look at the definition -

Definition: Symmetric matrix is such a matrix that all elements of it are non-negative and symmetric with relation to the center of this matrix. Any other matrix is considered to be non-symmetric.

Please ensure all the things of this definition.

[Chirag Chheda]

Thank you sir..
finally i managed to get an ACC

[Obaida]

But can someone explain why i am RTE.

>>my code is posted above.

[Chirag Chheda]

Can u tell me y r u printing this line???

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printf("N = ");

I think that's shud be in the input part and not the output part.

change it to:-

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scanf("%c%c",&c,&c);

declare 'c' to be of char data type

[Obaida]

Thank you very much. I always make such stupid mistake .
I never thought i should be inputed and getting RTE.

Again thank you for quick reply.

[A. M. Santos R.]

I think the problem statement is unclear:

Elements of this matrix are Mij: {0 < i < n, 0 < j < n}.

It should be Mij: {1 <= i <= n, 1 <= j <= n}.

[sharath]

#include <stdio.h>

int main ()
{
int num_test, k, n, i, j, flag;
long long a[110][110];
char junk;

scanf ("%d", &num_test);
k = 0;

NEXT_CASE:
while (k++ < num_test)
{
fflush (stdin);
scanf ("%c %c %d", &junk, &junk, &n);
flag = 0;
for (i = 0;i < n; i ++)
{
for (j = 0;j < n;j ++)
{
scanf("%lld", &a[j]);
if (a[j] < 0)
{
printf ("Test #%d: Non-symmetric.\n", k);
flag = 1;
}
}
}

if (flag)
{
continue;
}

for (i = 0;i < n/2; i ++)
{
for (j = 0;j < n;j ++)
{
if (a[j] != a[n - i - 1][n - j - 1])
{
printf ("Test #%d: Non-symmetric.\n", k);
goto NEXT_CASE;
}
}
}

for (j = 0;j < n/2; j ++)
{
for (i = 0;i < n;i ++)
{
if (a[j] != a[n - i - 1][n - j - 1])
{
printf ("Test #%d: Non-symmetric.\n", k);
goto NEXT_CASE;
}
}
}
printf ("Test #%d: Symmetric.\n", k);
}
return 0;
}

Can someone please let me know what is wrong in the above code...I am getting RTE

[kbr_iut]

U need to read the input carefully.
suppose input is like

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1
N = 3

first, u r taking 1 with

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scanf ("%d", &num_test);

that is okay.
then u r using

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scanf ("%c %c %d", &junk, &junk, &n);

Can u tell what will be the valu of junk and n here?
junk='\n'
junk='N'
n=garbage........

u can use this

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scanf("\nN = %d",&n);

or

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scanf(" N = %d",&n);

[sharath]

@kbr_iut :
I have used fflush(stdin) before the statement scanf ("%c %c %d", &junk, &junk, &n); So the new line character would be flushed and n will have the value 3 for the input you have mentioned. Am I correct?

[kbr_iut]

I just copied ur code and run for sample input of this problem and ur code gives

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Test #1: Symmetric.
Test #2: Symmetric.

and try to use code tag to post codes.