11349 - Symmetric Matrix

[Hojjat jafary]

the problem statement is not clear to me because i don't know what should i do when n the dimension of the matrix is even like 4.

[emotional blind]

there is also a center of the matrix when n is even.

[shakil]

What it mean????
symmetric with relation to the center of this matrix.

[Hojjat jafary]

which of these matrix are Symmetric?

1 6 7 1
7 2 3 1
1 3 2 7
1 5 4 1

or

1 4 5 1
7 2 3 1
1 3 2 7
1 5 4 1

[emotional blind]

Second one, I think that should be enough information now..

[Hojjat jafary]

thanks for your replay i got ac.

[armansuleimenov]

What is wrong with this code, I got WA?

Code: Select all

thanx, luishhh and sclo! got AC

Please give sample input with the correct output that make my program fail.

[luishhh]

use long longs

[armansuleimenov]

Oh, I see: [-2^32 ... 2^32] doesn't fit signed 32-bit integer ([-2^32...2^31-1]), I overlooked that. However I still get WA.

I changed this

Code: Select all

int m[110][110]; 

to this

Code: Select all

long long m[110][110]; 

That is the only I change I need to do to use 64-bit integers.

[sclo]

Oh, I see: [-2^32 ... 2^32] doesn't fit signed 32-bit integer ([-2^32...2^31-1]), I overlooked that. However I still get WA.

I changed this

Code: Select all

int m[110][110]; 

to this

Code: Select all

long long m[110][110]; 

That is the only I change I need to do to use 64-bit integers.

Just remove the word break from your code and you'll get AC.
As a rule, avoid use of the keyword break when reading input. (The only exception is to detect terminal character or delimiters)

PS. Please remove your code.

[damarro]

Hello. I get WA with my code and i don't know why. Can you help me?

Code: Select all

#include <iostream>

using namespace std;

int main() {
	long long M[110][110];
	int T;
	cin >> T;
	for(int cas = 1; cas <= T; cas++) {
		char a, b;
		int N;
		cin >> a >> b >> N;
		
		if(N <= 0)
			continue;
		
		for(int i = 0; i < N; i++)
			for(int j = 0; j < N; j++)
				cin >> M[i][j];
		
		bool sim = true;
		for(int i = 0; i < N; i++) {
			for(int j = 0; j < N; j++) {
				if(M[i][j] != M[N-1-i][N-1-j])
					sim = false;
			}
		}
		
		cout << "Test #" << cas << ": ";
		if(sim)
			cout << "Symmetric." << endl;
		else
			cout << "Non-symmetric." << endl;
	}
}

Thanks.

[Lomir]

Read the problem statement once again.

[mukit]

Someone please cheque my code ?
It's getting wrong answer

#include<iostream>
#include<cstdio>
using namespace std;
#define MAX 102
long long m[MAX][MAX];
int di;
int res=89;
int res2=90;
int func(int di)
{
int x=1;
int y=1;
int i,j;
{
/*for(i=1;i<=di;i++)
{
for(j=1;j<=di;j++)
{
cin>>m[j];
}
}*/
x=1;
y=di;
for(i=1,j=di;i<=di/2,j>=di/2;i++,j--)
{
if(m[x]==m[y][j])res=1;
else res=0;
}
return res;
}
}
int func2(int di)
{
int x=1;
int y=1;
int i,j;
{
/*for(i=1;i<=di;i++)
{
for(j=1;j<=di;j++)
{
cin>>m[j];
}
}*/
x=1;
y=di;
for(i=1,j=di;i<=di,j>0;i++,j--)
{
if(m[x]==m[j][y])res2=1;
else res2=0;
}
return res2;
}
}
int main()
{
int test;
int xm;
int ctr=1;
int i,j;
char c,c1;
cin>>test;
for(xm=0;xm<test;xm++)
{
cin>>c>>c1>>di;
for(i=1;i<=di;i++)
{
for(j=1;j<=di;j++)
{
cin>>m[j];
}
}
if(di%2==0)di/=2;
else di=(di/2)+1;
func(di);
func2(di);
if(res==1 && res2==1) cout<<"Test #"<<ctr<<": Symmetric."<<endl;
else cout<<"Test #"<<ctr<<": Non-symmetric."<<endl;
ctr++;
}
}

[rio]

Your code doesn't even pass the sample input..
Try to pass the sample input first.

And when you post your code, use code tag. It will be easier to see.
-----
Rio

[amr saqr]

Actually, I'm having problems with understanding the problem description,
should i cut the matrix vertically or horizontally to make the comparison to check whether it's symmetric or not ????
sorry but I'm little confused here

and thanx in advance