392 - Polynomial Showdown

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shamim
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Post by shamim » Sun Jun 13, 2004 6:57 am

It would be better if you mentioned the name or/and number of the problem. :P
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afzaalakhtar
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Polynomial Showdown plz help me

Post by afzaalakhtar » Sun Jun 13, 2004 1:57 pm

I've tried each and every input my code give me the correct result
but acm gives WA why?????

if anybody can help me...... my source code is below

// Programmed by Afzaal Akhtar
// Polynomial ShowDown ACM Problem 392
#include<iostream>
#include<sstream>

using namespace std;


const int MAX = 8;
int p[MAX];

string writepoly()

{
stringstream s;
int power;
bool started;

started = false;

for(power = MAX; power>=0;power--){
if (p[power] != 0){
if (started) {
if (p[power] < 0) {
s<<" - ";
p[power] = -p[power];
}
else
s<<" + ";
}
else{
started = true;
if (p[power] < 0){
s<<"-";
p[power] = -p[power];
}
}
if ((p[power] != 1) || (power == 0))
s<<p[power];
if (power>0)
s<<"x";
if (power>1)
s<<"^"<<power;
}
}
if(!started)
s<<"0";

s<<"\n";

return s.str();
}


int main()
{

while(!cin.eof()){
for(int i=MAX;i>=0;i--)
cin>>p;

cout<<writepoly();
}
return 0;
}
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samueljj
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Post by samueljj » Sun Jun 13, 2004 7:32 pm

midra.... probably the instead of -x in line 2 it will be - x..... i think so...

tahsin..
novice programmer
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midra
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Post by midra » Sun Jun 13, 2004 11:08 pm

thanks a lot!!
I fix this little things, but I am still WA!!
I really got stuck with this!
Here is my code: (I know it's a very ineficient program, but I am a newcomer in this field so I don't know any other way to do it)

[c]
#include <stdio.h>
#include <math.h>
int main()
{
int c[13]; /*Coeficients*/
int i; /*counter*/
int n; /*Numero para saber si ya hizo el 1er coef.*/

empieza:
while(scanf("%d%d%d%d%d%d%d%d%d",&c[9],&c[8],&c[7],&c[6],&c[5],&c[4],&c[3],&c[2],&c[1])==9)
{
n=0;
if (c[1]==0 && c[2]==1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("x\n");
goto empieza;
}
else if (c[1]==0 && c[2]==-1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("-x\n");
goto empieza;
}
else if (c[1]==-1 && c[2]==1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("-x + 1\n");
goto empieza;
}
else if (c[1]==1 && c[2]==1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("x + 1\n");
goto empieza;
}
else if (c[1]==-1 && c[2]==-1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("-x - 1\n");
goto empieza;
}
else if (c[1]==1 && c[2]==-1 && c[3]==0 && c[4]==0 && c[5]==0 && c[6]==0 && c[7]==0 && c[8]==0 && c[9]==0){
printf("x - 1\n");
goto empieza;
}
for (i=9; i>=1; i--)
{
if (i==1 && n!=0)
{
if (c>0)
printf("+ %d",c);
else if (c<0)
printf("- %d",abs(c));
printf("\n");
goto empieza;
}
else if (i==1 && n==0)
{
printf("%d",c);
printf("\n");
goto empieza;
}

else if (c==0)
continue;
else if (i==2)
{
if (c>1)
printf("+ %dx ",c);
else if (c<-1)
printf("- %dx",abs(c));
else if (c[i]==-1)
printf("- x ");
else if (c[i]==1)
printf("+ x ");
}
else if (n==0 && abs(c[i])!=1)
{
printf("%dx^%d ",c[i],i-1);
n++;
}
else if (c[i]==-1 && n==0)
{
printf("- x^%d ",i-1);
n++;
}
else if (c[i]==1 && n==0)
{
printf("x^%d ",i-1);
n++;
}
else if (c[i]>1)
printf("+ %dx^%d ",c[i],i-1);
else if (c[i]<-1)
printf("- %dx^%d ",abs(c[i]),i-1);
else if (c[i]==1)
printf("+ x^%d ",i-1);
else if (c[i]==-1)
printf("- x^%d ",i-1);
}
}
return 0;
}
[/c]
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PerHagen
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392

Post by PerHagen » Thu Feb 10, 2005 7:51 pm

hello

i have with W.A.
my cod is


include <stdio.h>
include <iostream.h>
int arreglo[9];
void main(void)
{
while(scanf("%d %d %d %d %d %d %d %d %d",
&arreglo[0],&arreglo[1],&arreglo[2],&arreglo[3],
&arreglo[4],&arreglo[5],&arreglo[6],&arreglo[7],
&arreglo[8])==9)

{ int i=0;
while (arreglo==0)i++;

if (i<9){(arreglo!=1 && arreglo!=-1 &&i!=8)?cout<<arreglo:cout<<"";
(arreglo==-1 && i!=8)?cout<<"-":cout<<"";
(i<8)?cout<<"x":cout<<"";
(i<7)?cout<<"^"<<(8-i):cout<<"";
(i==8 && arreglo>0 )?cout<<arreglo:cout<<"";
(i==8 && arreglo<0 )?cout<<arreglo:cout<<"";
}
i++;

while(i<9)
{
if(arreglo!=0){
(arreglo[i]>0)?cout<<" + ":cout<<" - ";
(arreglo[i]>0 && arreglo[i]!=1 && arreglo[i]!=-1&& i!=7 && i!=8)?cout<<arreglo[i]:cout<<"";
(arreglo[i]<0 && arreglo[i]!=1 && arreglo[i]!=-1&& i!=7 && i!=8)?cout<<(-1*arreglo[i]):cout<<"";
(i==7 && arreglo[i]>0 && arreglo[i]!=1 &&arreglo[i]!=-1)?cout<<arreglo[i]:cout<<"";
(i==7 && arreglo[i]<0 && arreglo[i]!=1 &&arreglo[i]!=-1)?cout<<(-1*arreglo[i]):cout<<"";
(i<8)?cout<<"x":cout<<"";
(i<7)?cout<<"^"<<(8-i):cout<<"";
(i==8 && arreglo[i]>0)?cout<<arreglo[i]:cout<<"";
(i==8 && arreglo[i]<0)?cout<<(-1*arreglo[i]):cout<<"";
}
i++;
}
cout<<endl;
}
}

help[/code][/list][/quote]
hello !
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Sedefcho
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Post by Sedefcho » Mon Feb 14, 2005 8:10 pm

It is mentioned in the Thread Name.

392-Anybody help me?


I would like to have some I/O for this Problem - 392.
Apparently I am missing some very subtle cases which
could cause problems.
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Ghust_omega
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Location: Venezuela

Post by Ghust_omega » Fri Feb 18, 2005 11:30 pm

Hi !! to alll some I/O
in

Code: Select all

9 -2 6 -5 -3 5 -7 6 3
6 0 6 -3 -9 0 -7 2 1
2 0 2 -9 -7 8 -1 6 2
7 -9 8 -2 -2 9 -5 7 3
4 -9 1 -3 -9 2 -1 6 3
0 0 0 -3 0 0 0 0 0
4 -5 5 -1 -6 0 0 0 0
0 -4 0 -3 -9 6 -5 6 7
7 0 3 -4 -4 -7 -4 5 2
9 -4 1 -3 -4 8 -8 6 8
4 -6 6 -2 -9 8 -6 0 2
2 -7 1 -7 -8 4 0 5 -9
5 -1 6 0 -1 6 -2 -2 7
0 7 0 0 -9 0 -9 0 0
0 0 7 6 -7 -7 -9 0 0
0 0 1 8 4 9 -3 6 5
6 9 0 -5 -8 8 0 9 3
8 9 -5 1 -1 6 -5 8 3
4 -4 4 0 -3 0 -1 8 4
6 9 -5 7 -1 3 -6 7 4
out:

Code: Select all

9x^8 - 2x^7 + 6x^6 - 5x^5 - 3x^4 + 5x^3 - 7x^2 + 6x + 3
6x^8 + 6x^6 - 3x^5 - 9x^4 - 7x^2 + 2x + 1
2x^8 + 2x^6 - 9x^5 - 7x^4 + 8x^3 - x^2 + 6x + 2
7x^8 - 9x^7 + 8x^6 - 2x^5 - 2x^4 + 9x^3 - 5x^2 + 7x + 3
4x^8 - 9x^7 + x^6 - 3x^5 - 9x^4 + 2x^3 - x^2 + 6x + 3
-3x^5
4x^8 - 5x^7 + 5x^6 - x^5 - 6x^4
-4x^7 - 3x^5 - 9x^4 + 6x^3 - 5x^2 + 6x + 7
7x^8 + 3x^6 - 4x^5 - 4x^4 - 7x^3 - 4x^2 + 5x + 2
9x^8 - 4x^7 + x^6 - 3x^5 - 4x^4 + 8x^3 - 8x^2 + 6x + 8
4x^8 - 6x^7 + 6x^6 - 2x^5 - 9x^4 + 8x^3 - 6x^2 + 2
2x^8 - 7x^7 + x^6 - 7x^5 - 8x^4 + 4x^3 + 5x - 9
5x^8 - x^7 + 6x^6 - x^4 + 6x^3 - 2x^2 - 2x + 7
7x^7 - 9x^4 - 9x^2
7x^6 + 6x^5 - 7x^4 - 7x^3 - 9x^2
x^6 + 8x^5 + 4x^4 + 9x^3 - 3x^2 + 6x + 5
6x^8 + 9x^7 - 5x^5 - 8x^4 + 8x^3 + 9x + 3
8x^8 + 9x^7 - 5x^6 + x^5 - x^4 + 6x^3 - 5x^2 + 8x + 3
4x^8 - 4x^7 + 4x^6 - 3x^4 - x^2 + 8x + 4
6x^8 + 9x^7 - 5x^6 + 7x^5 - x^4 + 3x^3 - 6x^2 + 7x + 4
Hope it Helps
Keep posting
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Sedefcho
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Post by Sedefcho » Sat Feb 19, 2005 8:48 pm

Thank you, Ghust_omega.

I already have it ACC. Hope your I/O will
help other people working on this one.
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triker
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Joined: Tue Apr 19, 2005 9:56 am

392 Polynomial Showdown Plz Help

Post by triker » Wed May 25, 2005 6:13 am

I got WA. I searched the forum and try inputs. It got the output right but still WA.

Here is my code

Code: Select all

#include <stdio.h>
#include <math.h>

int main()
{
    const int MAX_CO=9;
    int poly[MAX_CO];
    int count=1,power;
    int i;
    
while(scanf("%d%d%d%d%d%d%d%d%d",&poly[0],&poly[1],&poly[2],&poly[3],&poly[4],&poly[5],&poly[6],&poly[7],&poly[8])==9)
{       
    count = 1;
    for(i=0;i<MAX_CO;i++)
    {
        power = MAX_CO - i -1;
        
        /*last number which has no 'x' and no power*/
        if(power == 0)
        {
                /*if it's the first number that appears (all number before are zero*/
                if(count==1)
                {                    
                    printf("%d",poly[i]);
                    continue;
                }
                /*if it's not the first number that appears*/            
                if(poly[i]>0) /*positive*/
                {
                    printf(" + ");
                    printf("%d",poly[i]);
                }
                else if(poly[i]<0) /*negative*/
                {
                    printf(" - ");
                    printf("%d",0-poly[i]);
                }
                continue;
        }
        
        /*first number that appears*/
        if((count == 1)&&(poly[i] != 0))
        {        
                if(poly[i]>1) 
                {
                    printf("%dx",poly[i],power);                    
                }
                else if(poly[i]<-1)
                {
                    printf("%dx",poly[i],power);
                }
                else if(poly[i] == 1)
                {
                    printf("x");                    
                }
                else if(poly[i] == -1)
                {
                    printf("-x");
                }
                
                /*write out its power*/
                if((power != 0)&&(power !=1))
                {
                    printf("^%d",power);
                }                
                count++;                
                continue;
        }
        
        /*second number and so on*/
        if((count>1)&&(poly[i] != 0)&&(power !=0))
        {
                if(poly[i]>0)
                {
                printf(" + ");
                }
                else
                {
                printf(" - ");
                }
                 
                if(poly[i]>1) /*positive*/
                {
                    printf("%dx",poly[i]);
                }
                else if((poly[i] == 1)||(poly[i] == -1))
                {
                    printf("x");
                }
                else if(poly[i]<-1) /*negative*/
                {
                    printf("%dx",0-poly[i]);
                }
                else {}                
        }                         
        
        /*write out the power*/
        if((power != 0)&&(power !=1)&&(poly[i] != 0))
        {
                printf("^%d",power);
        }
                    
    }        
}  
return 0;
}
plz help :(
Thanks in advance :)
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Ali Arman Tamal
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392 more test cases

Post by Ali Arman Tamal » Fri May 27, 2005 2:21 pm

input:
-1 -1 -1 -1 -1 -1 -1 -1 -1
-1 0 0 0 0 0 0 0 0
-1 0 0 0 0 0 0 0 -1
0 0 0 0 0 0 0 0 0
-999 0 -1 999 0 1 999 1 0 -2
4 5 -1 8 0 -2 -2 -3
1 1 1 1 1 1 1 1 1
-0 -0 -0 -0 -0 -0 -0 -0 -0

output:
-x^8 - x^7 - x^6 - x^5 - x^4 - x^3 - x^2 - x - 1
-x^8
-x^8 - 1
0
-999x^8 - x^6 + 999x^5 + x^3 + 999x^2 + x
-2x^8 + 4x^7 + 5x^6 - x^5 + 8x^4 - 2x^2 - 2x - 3
x^8 + x^7 + x^6 + x^5 + x^4 + x^3 + x^2 + x + 1
0
-10x^4
10x^4

hope it helps :P
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Niaz
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Post by Niaz » Sat Oct 22, 2005 10:37 am

I am trying to solve this problem for the last 3 years ! But getting again and again WA !!! I have tried all the test inputs and outputs given in the board. My WA code can produce correct output for all the given inputs. What can I do now ? Is there any one who can help me ? If any interested person wants to watch my code, I can send him mine. But, plz help me. I am suffering from such an easy problem. This is disgusting.

- Niaz
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Niaz
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Post by Niaz » Sat Nov 26, 2005 9:26 am

Here is my code. Plz have a look.

Code: Select all

Got Accepted. Thanks to Roby.
Last edited by Niaz on Tue Dec 06, 2005 7:04 pm, edited 1 time in total.
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Niaz
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Post by Niaz » Sat Nov 26, 2005 9:29 am

Can anyone help me ? Getting WA for the last 3 years !!!

Code: Select all

#include<stdio.h>
int main()
{
	int coeff[10];
	int i,k;
	while(scanf("%d",&i)==1)
	{
		coeff[8]=i;
		for(i=0;i<8;i++)
			scanf("%d",&coeff[7-i]);

		k=0;
		for(i=8;i>1;i--)
		{
			if(coeff[i]>0)
			{
				if(k==1)
					printf(" + ");
				if(coeff[i]!=1)
					printf("%dx^%d",coeff[i],i);
				else
					printf("x^%d",i);
				k=1;
			}
			else if(coeff[i]<0)
			{

				if(k==0)
					printf("-");
				else
					printf(" - ");

				coeff[i]=coeff[i]*(-1);
				if(coeff[i]!=1)
					printf("%dx^%d",coeff[i],i);
				else
					printf("x^%d",i);
				k=1;
			}
		}

		if(coeff[1]!=0)
		{
			i=1;
			if(coeff[i]>0)
			{
				if(k==1)
					printf(" + ");
				if(coeff[i]!=1)
					printf("%dx",coeff[i]);
				else
					printf("x");
				k=1;
			}
			else if(coeff[i]<0)
			{
				if(k==0)
					printf("-");
				else
					printf(" - ");
				coeff[i]=coeff[i]*(-1);
				if(coeff[i]!=1)
					printf("%dx",coeff[i]);
				printf("x");
				k=1;
			}
		}

		if(coeff[0]!=0)
		{
			i=0;
			if(coeff[i]>0)
			{
				if(k==1)
					printf(" + ");
				printf("%d",coeff[i]);
				k=1;
			}
			else if(coeff[i]<0)
			{
				if(k==0)
					printf("-");
				else
					printf(" - ");
				coeff[i]=coeff[i]*(-1);
				printf("%d",coeff[i]);
				k=1;
			}
		}
		if(k==0)
			printf("0");
		printf("\n");
	}
	return 0;
}
Thanks in advance.
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Niaz
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Post by Niaz » Sat Nov 26, 2005 9:30 am

got AC.
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Roby
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Post by Roby » Tue Nov 29, 2005 9:25 am

Your program give wrong result if I test with these:

Code: Select all

0 0 0 1 22 -333 0 1 -1
-1 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 -7 30 66
0 0 0 0 0 0 1 -3 0
0 0 0 0 0 -1 1 3 -1
-5 0 0 0 -243 0 0 0 -9
-0 -1 -1 -1 -1 -1 -1 -1 -1
-1999999999 -978456 0 0 0 0 56 -89 8
0 0 0 0 0 0 0 0 -1
0 0 0 0 0 0 0 0  1
0 0 0 0 0 0 0 1 0
0 0 0 0 0 0 0 -1 0
0 0 0 0 0 0 0 1 1
0 0 0 0 0 0 0 -1 1
0 0 0 0 0 0 0 -1 -1
0 0 0 0 0 0 0 1 -1
0 0 0 0 0 0 0 0 1
1 0 0 0 0 0 0 0 0
0 1 0 0 0 0 0 0 0
0 0 -1 0 0 0 0 0 0
2 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 2
0 0 0 0 0 0 0 0 -10
0 0 0 0 0 0 0 10 0
0 0 0 0 0 0 0 -2 0
0 0 0 0 0 0 0 10 -2
My accepted code give these result:

Code: Select all

x^5 + 22x^4 - 333x^3 + x - 1
-x^8
0
-7x^2 + 30x + 66
x^2 - 3x
-x^3 + x^2 + 3x - 1
-5x^8 - 243x^4 - 9
-x^7 - x^6 - x^5 - x^4 - x^3 - x^2 - x - 1
27649x^8 + 4584x^7 + 56x^2 - 89x + 8
-1
1
x
-x
x + 1
-x + 1
-x - 1
x - 1
1
x^8
x^7
-x^6
2x^8
2
-10
10x
-2x
10x - 2
And these one are yours:

Code: Select all

x^5 + 22x^4 - 333x^3 + x - 1
-x^8
0
-7x^2 + 30x + 66
x^2 - 3xx
-x^3 + x^2 + 3x - 1
-5x^8 - 243x^4 - 9
-x^7 - x^6 - x^5 - x^4 - x^3 - x^2 - x - 1
27649x^8 + 4584x^7 + 56x^2 - 89xx + 8
-1
1
x
-x
x + 1
-x + 1
-x - 1
x - 1
1
x^8
x^7
-x^6
2x^8
2
-10
10x
-2xx
10x - 2
Be careful! This problem is output related! Even if you just add one space after the line, you'll get WA!
Hope it helps :wink:
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