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### 11291 - Smeech

Posted: **Sat Sep 29, 2007 10:23 pm**

by **Piklu_sust**

Can anyone explain what should do in this problem?

I cannot find the meaning of the following statement:

With probability p, (p e1 e2) represents x+y where x is the value of e1 and y is the value of e2; otherwise it represents x-y.

How can be p used for the statement?

Posted: **Sat Sep 29, 2007 10:30 pm**

by **helloneo**

I understood it this way..

the expected value of (p e1 e2) is p*(x+y) + (1-p)*(x-y)..

### wa

Posted: **Sun Sep 30, 2007 10:25 am**

by **tanvir**

can anyone check this code. im getting wa again again

best regard

tanvir

Posted: **Sun Sep 30, 2007 10:34 am**

by **helloneo**

Try this case..

My output is..

Posted: **Mon Oct 01, 2007 12:26 am**

by **sclo**

Hint: My code is only about 30 lines long!

Posted: **Mon Oct 01, 2007 7:17 am**

by **tanvir**

sorry i was not considering the negetive numbers there...

but now im considering the negetive numbers here....

but also wa wa wa

can any one check the code or give sample input output....

regard

tanvir

Posted: **Mon Oct 01, 2007 7:39 am**

by **sclo**

I'm not sure, but how do you know the format of the real numbers that is in the judge input?

Posted: **Mon Oct 01, 2007 8:37 am**

by **helloneo**

Another test case..

Code: Select all

```
(1.0 (1.0 (1.0 -1 -2) (1.0 -1 -2)) (1.0 (1.0 1 2) 2))
()
```

My output is..

Posted: **Mon Oct 01, 2007 10:37 am**

by **tanvir**

thnx helloneo

i was really making dumping things in nested area.

got ac last.

tanvir