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### 957 - Popes

Posted: **Thu Jan 25, 2007 12:54 pm**

by **aha2007**

It's seems to me the problem of maximum sum of continuous sub sequences of length m.

I know a linear algorithm when length m is not specified , but don't know how to extend it for

specified length m. Can any one kind enough to give me a linear time algorithm for this problem , or any link describing that algorithm.

Posted: **Sat Feb 17, 2007 11:09 am**

by **sclo**

It is even easier when m is fixed.

Let a* be the number of popes elected in the year i.*

Let f[0]=a[0], and f* = f[i-1]+a** for i>0, so f** is a cumulative sum.*

Consider the value of f[i+m-1]-f[i-1] for all i.

As for the algorithm for maximum consecutive sum, it is trivial to solve when all the elements of the array is non-negative.

Posted: **Thu Jun 28, 2007 5:36 pm**

by **helloneo**

Hello..~

Can anybody tell me what is wrong with my code..?

I'm getting WAs.. but I have no idea..

check

* is the number of occurences of 'i' and..*

sum* is the cumulative sum up to check*

Thanks..

Posted: **Thu Jun 28, 2007 6:01 pm**

by **Jan**

Try the cases.

**Input:**
Code: Select all

```
11
20
20 numbers given in sample :)
12
20
20 numbers given in sample :)
17
20
20 numbers given in sample :)
```

**Output:**
Hope the weird input set helps.

.

Posted: **Thu Jun 28, 2007 6:26 pm**

by **helloneo**

Thanks a lot..~

I got AC..

PS. very funny input..

It took some time to get the point..

### 957-Popes

Posted: **Sat Sep 18, 2010 9:29 pm**

by **Symon**

I can't realize why I'm getting WA.

Please give me some input output.

Code: Select all

```
#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
long int y,p,i,j,a[100005],cnt[1][3],max,increase;
while(scanf("%ld%ld",&y,&p)!=EOF)
{
max=-1;
increase=-1;
for(i=0;i<p;i++)
{
scanf("%ld",&a[i]);
if(i!=0&&a[i]<a[i-1])
{
increase=0;
}
}
if(increase==0)
{
sort(a,a+p);
}
for(i=0;i<p;i++)
{
cnt[0][2]=0;
for(j=i;j<p&&a[j]<=a[i]+(y-1);j++)
{
cnt[0][2]++;
}
if(max<cnt[0][2])
{
max=cnt[0][2];
cnt[0][0]=a[i];
cnt[0][1]=a[j-1];
}
}
printf("%ld %ld %ld\n\n",max,cnt[0][0],cnt[0][1]);
}
return 0;
}]
```

thanks...

### Re: 957 - Popes

Posted: **Fri Sep 13, 2013 9:00 am**

by **Hammer Engineer**

Why RE ? Please help

Code: Select all

```
#include <iostream>
#include<vector>
#include<cstdio>
using namespace std;
int main()
{
freopen("input.txt", "r", stdin);
int span;
//scanf("%d",&span);
while ( scanf("%d",&span) != EOF ) {
vector<int> a(100001);
vector<int> F(100001);
int Y , year;
a[0] = F[0] = 0;
scanf("%d",&Y);
span -=1;
for(int i=1; i<=Y; i++)
{
scanf("%d",&year);
a[year] +=1;
}
for(int i=1;i<a.size();i++)
{
F[i] = (a[i] + F[i-1]);
}
int max=0,from , sum;
for(int i=1;i<F.size();i++)
{
if(i+span < F.size())
sum = F[i+span] - F[i-1];
else
sum = F[F.size()-1] - F[i-1];
if(sum > max)
{
max=sum;
from = i;
}
}
printf("%d %d %d\n", max , from , from+span);
}
return 0;
}
```

### Re: 957 - Popes

Posted: **Fri Sep 13, 2013 9:23 pm**

by **brianfry713**

Don't read from a file.

### Re: 957 - Popes

Posted: **Mon Sep 16, 2013 1:06 am**

by **Hammer Engineer**

@brainfry713 When i'm submitting code i'm removing **freopen()** [ sorry I did't mension that in code].

Is there any other problem that can end with a RE ?

### Re: 957 - Popes

Posted: **Tue Sep 17, 2013 10:04 pm**

by **brianfry713**

year L <= 1,000,000

### Re: 957 - Popes

Posted: **Sun Oct 05, 2014 11:07 pm**

by **omar.fmc**

Hello all,

I'm getting RE and I can't find out the reason of that.

Here's my code:

Appreciate your help

EDIT:

For those who are getting RE notice that P<=100000 in the judge's input (not 5000 as in the problem statement).

### Re: 957 - Popes

Posted: **Tue Oct 07, 2014 10:50 pm**

by **brianfry713**

There is a case in the judge's input where P > 5000, but not one where P > 100000.

http://online-judge.uva.es/board/viewto ... &hilit=957

### Re: 957 - Popes

Posted: **Tue Oct 07, 2014 10:58 pm**

by **omar.fmc**

Thanks a lot. Got Accepted

### Re:

Posted: **Sat Oct 18, 2014 7:28 pm**

by **morkoh**

Jan wrote:Try the cases.

**Input:**
Code: Select all

```
11
20
20 numbers given in sample :)
12
20
20 numbers given in sample :)
17
20
20 numbers given in sample :)
```

**Output:**
Hope the weird input set helps.

.

Could someone tell me how is this correct?

From years 11-21 we had 12 popes.

There was a pope elected in year 8 and he was alive up until year 12 when a new one was elected.

pope 5 was from 8-11, pope 6 in 12, pope 7 and 8 | 13-14, pope 9 15, pope 10 16, pope 11 in 17, in year 21 pope 16.

So, there were popes from 5 to 16 on a period of 11 years. Pope 5 being in year 11, and pope 16 in year 21.

21 - 11 + 1 = 11 years...

Shouldn't the answer be 12 8 21, instead of 11 12 21?

It is obvious that the text of the task is completely unclear. There's no limit between difference of election years of first and last pope.

And somehow all of the answers automatically assume that last-first+1 <= Y.

### Re: 957 - Popes

Posted: **Tue Oct 21, 2014 8:13 pm**

by **brianfry713**

Input:

Code: Select all

```
11
20
1
2
3
6
8
12
13
13
15
16
17
18
19
20
20
21
25
26
30
31
12
20
1
2
3
6
8
12
13
13
15
16
17
18
19
20
20
21
25
26
30
31
17
20
1
2
3
6
8
12
13
13
15
16
17
18
19
20
20
21
25
26
30
31
```

Correct output:

From years 12 to 21 there were 11 popes elected. There was no pope elected in year 11. We are only interested in the years of election, not the number of popes in office during the time frame. The problem statement is misleading.