10944 - Nuts for nuts..

[ayon]

bfs is unnecessary, the dist between x1,y1 and x2,y2 is
max(x1~x2, y1~y2). use bitmask DP, that wont give tle, i used this with time complexity O(n^2*2^n) and memory O(n*2^n) as described earlier in this forum

[sclo]

The dp for TSP is one of the standard dp for subsets. It is good to learn it.
It is basically 3 nested for loops. At the end, we need to take care of the last segment back to the start vertex.

[mohiul alam prince]

I have solved this problem by this way

but a single if condition has confused me...

Code: Select all

...................................

This problem takes only 1.76 seconds

but when i have changed a if conditions format then it takes 6.52 seconds
why can any body explain me ...

Code: Select all

.................................

Code: Select all

   if (u) {
		if (Graph[x][u] < sum) return ;
		else Graph[x][u] = sum;
	}

it takes 6.52 seconds

Code: Select all

   if (u) {
		if (Graph[x][u] > sum) Graph[x][u] = sum;
		else return ;
	}

it takes 1.76 seconds
Thanks
MAP

After discussion i will cut my code

[emotional blind]

Code: Select all

   if (u) {
		if (Graph[x][u] < sum) return ;
		else Graph[x][u] = sum;
	}

it takes 6.52 seconds

Code: Select all

   if (u) {
		if (Graph[x][u] > sum) Graph[x][u] = sum;
		else return ;
	}

it takes 1.76 seconds
Thanks
MAP

After discussion i will cut my code

Look at this part:

Code: Select all

   if (u) {
		if (Graph[x][u] > sum) Graph[x][u] = sum;
		else return ;
	}

which is equivalent to:

Code: Select all

   if (u) {
		if (Graph[x][u] <= sum) return ;
		else Graph[x][u] = sum;
	}

but your equivalent code was

Code: Select all

   if (u) {
		if (Graph[x][u] < sum) return ;
		else Graph[x][u] = sum;
	}

the function returns when Graph[x]<sum, but in first case function returns when Graph[x]<=sum.. so your code dont return when Graph[x]==sum. thats why it takes more time.

[mohiul alam prince]

Thankx EmotionalBlind
i have got it..

MAP

[nymo]

I 've got ACC with topdown approach (recursion with memoization) ... at last.
Thanks everyone. I 've done pretty much what ayon said.