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### 10882 - Koerner's Pub

Posted: Tue Aug 09, 2005 4:29 pm
Since the range is so small (100), I thought of a bruteforce solution but that gives wrong answer.

My method:
given
A intersection B
B intersectin C
A intersectin C

find A intersectin B intersection C... right?

my code:

Code: Select all

``````  Removed after getting AC..
thanks to mf.
}
``````
Can someone give some input/output... or prove my method wrong.

Posted: Tue Aug 09, 2005 5:37 pm
The lower bound may be 0, for example in "34 33 33".

Posted: Wed Aug 10, 2005 11:32 am
Thanks..
.. got AC.

Sometimes it is hard to think of the obvious !!
Well, for me anyways.

### I/O needed.

Posted: Sat Aug 13, 2005 4:46 am
Greetings!
Any I/O for spare?
No idea why the WA

Posted: Sat Aug 13, 2005 8:40 am
How do you check whether the given data is faulty?

### Ouch!

Posted: Sun Aug 14, 2005 4:55 am
Ouch!, forgot to take some comments away after correction
From

Code: Select all

``low = obligatorios + (a[0] / 2); // + (a[0] % 2);``
to

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``low = obligatorios + (a[0] / 2) + (a[0] % 2);``
Well, had other mistake.
By the way, I considered data faulty if:
- Higher value is > than 100.
- Lower value is < than the intersection of the other 2 values.

Keep posting!

Posted: Fri Jun 23, 2006 2:02 am
i get WA.
can smbody plz tell me what's the output of this input?

71 60 60
72 60 60
70 60 60
72 60 6
10 10 10
34 33 33
33 35 35
0 0 1
1 1 1
34 34 34
100 100 80
80 80 100

Posted: Fri Jun 23, 2006 2:25 am
at last got AC.....

i did a mistake & that was:

i overlooked there would be some friday when Ai != Ci != Mi.

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 7:27 am
Hi everyone ...

It's my first time here.
i hope it's helpful

i had coded this problem and got WA ...
may anyone suggest any tricky input or check my code ?

that is my code:

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``````removed.
``````

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 4:25 pm
Try this case..

Input

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``````12
71 60 60
72 60 60
70 60 60
72 60 6
10 10 10
34 33 33
33 35 35
0 0 1
1 1 1
34 34 34
100 100 80
80 80 100``````
My output is ..

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``````Case #1: Between 46 and 60 times.
Case #2: Between 46 and 60 times.
Case #3: Between 45 and 60 times.
Case #4: The records are faulty.
Case #5: Between 0 and 10 times.
Case #6: Between 0 and 33 times.
Case #7: Between 2 and 33 times.
Case #8: Between 0 and 0 times.
Case #9: Between 0 and 1 times.
Case #10: Between 1 and 34 times.
Case #11: The records are faulty.
Case #12: Between 80 and 80 times.``````

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 7:30 pm
Oops!

seems that i am stupid .. i have done this conditions to be faulty and that is wrong:

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``````if(min(a,b)>c){printf("Case #%d: The records are faulty.\n",i+1);continue;}
if(min(a,c)>b){printf("Case #%d: The records are faulty.\n",i+1);continue;}
if(min(b,c)>a){printf("Case #%d: The records are faulty.\n",i+1);continue;}
``````
i hope that is the only bug .. i will try it now.
Thanks very much.

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 7:42 pm
still WA

i dunno what is still wrong it is passing all the cases u have suggested.

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 8:39 pm
check case 7 again, your program gives a wrong output, it's just a small mistake ...

### Re: 10882 - Koerner's Pub

Posted: Mon Jan 05, 2009 9:07 pm
it is AC thanks