Search found 4 matches

by cooleye
Wed Oct 30, 2002 7:47 pm
Forum: Volume 102 (10200-10299)
Topic: 10289 - A Square and Equilateral Triangles
Replies: 27
Views: 13367

Image

If you check the length of XY,
you will find that it's a little bit larger than the answer.

It implies that there will be some unused space
and you can pack lager triangle.

So I think the offical answer is wrong.
by cooleye
Mon Oct 28, 2002 6:36 pm
Forum: Volume 102 (10200-10299)
Topic: 10289 - A Square and Equilateral Triangles
Replies: 27
Views: 13367

Mahbub wrote:Well..the left top triangle shouldn't be considered
I think that triangle is very important, if you check the coordinate of the points, you will find the problem
by cooleye
Sat Oct 26, 2002 9:16 am
Forum: Volume 102 (10200-10299)
Topic: 10289 - A Square and Equilateral Triangles
Replies: 27
Views: 13367

it's wrong to assume that the top triangle and the bottom one is
on the same axis.

'You can assume that when the images look exactly symmetric along a certain axis they are actually symmetric along that certain axis.'

This does not apply to case 5 as there is no axis of symmetry.
by cooleye
Sun Oct 13, 2002 5:20 pm
Forum: Volume 102 (10200-10299)
Topic: 10289 - A Square and Equilateral Triangles
Replies: 27
Views: 13367

10289 again

it seems that the judge have got wrong with the case of 5 triangle

the offical answer is

0.55437056466848326729919722838716
(2 + sqrt(3)) / (5 + sqrt(3))

but I got

0.554579157314857

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