OJ Board

I finally got AC. :D. It works with my formula for the number of steps, thought I wrote it wrong in the previous post. It is in fact lcm( S/gcd(S,dx), S/gcd(S,dy)). Thanks! Seeing the Waterloo test data really helped. for Eduard: I guess that you are talking about Waterloo's test data. Maybe here th...

My problem is that I created a topic (asking help for a problem in volume CVI) and it has disappeared. In fact following the link in my emails (received when a new post is put) I can view it. But after I log in I can't find it back. And I don't understand why this happened. Sorry if it is not here w...

The number of steps is the period of the sequence of squares, that is the lcm of the periods on x and y, that is per := lcm( gcd(S,dx), gcd(S,dy)). So after per moves the sequence will be the same, so there is no need to check further. In fact if after per moves we are on a white square then the per...

I get WA for this problem and I don't know why. My approach is the follwing: I move the flea step by step, and I check each time whether it is on a black square (including the border) or on a white square. If for a number of steps (depending on S, dx and dy) l don't encounter a white squre then it m...

Yes. They probably meant atgc and tga as input.

Can someone give me some clues or i/o samples, because I guess I'm doing it right but I get wa.

Thanks!

I don't understand the output / the problem: -for 5 there is no answer -for 10 we can find a box of 2*2*3 inches and so the area is 2*(2*2+2*3+2*3)=32<34 - 26 blocks fit in the solid that contains 27 blocks (area[26]<area[27]) but 82>54. It seems I don't understand what a solid rectangular means or ...