UVa OJ Board

Maybe you can replace '/2' and '%2' with shift operator '>>' for higher
efficiency.

the problem insist that answers must be rounded to six digits after the decimal point. If the answer we have is 2.44949 what value we have to output? 2.44949 or 2.449490? And I don't know why W.A occurs at all... #include <iostream.h> #include <math.h> #include <iomanip.h> int GCD(int a,int b){ whil...

anybody......please tell me why it comes with "TimeLimitExceeded" ? #include <stdio.h> #include <iostream.h> #include <string.h> void reverse(char *s){ int i; char t[10000]; memset(t,0,10000); for(i=0;i<strlen(s);i++) t[strlen(s)-1-i]=s[i]; strcpy(s,t); return; } void BIGSUM(char *a,char *b){ int i,...

P256 Quirksome Squares find the number with the following property: 3025=(30+25)^2 The number of digits may be 2,4,6 or 8. The maxint is only 32767 and numbers of eight digits are asked for. Please note that the number of digits in the output is equal to the number in the corresponding input line : ...

your method is too slow .............and "TIMELIMITEXCEEDED" is happened

OH! CRAP~~~~~~

NEVER GIVE UP !

I think my method is fast enough.......... However........It arise "TimeLimitExceeded" Anybody knows why??? My idea is: 5^100 mod 26 =((5^3)^33)*(5^1) mod 26 = ((5^3 mod 26)^33)*(5^1 mod 26) mod 26 =(21^33)*5 mod 26 =X^Y*Z mod 26 ............etc Repeat until X^Y<26 and Z<26 Then directly calculate ...