OJ Board

Thank u very much MF for clearing my doubt ...

#include <stdio.h>
int main()
{
long long n=22214748323LL;
printf("%d\n",sizeof(int));
printf("%d\n",sizeof(long int));
printf("%d\n",sizeof(long long int));
n=n+1;
printf("%lld\n",n);
return 0;
}




I get the output -
4
4
8
-2080218972

while when I use the statement printf("%lu\n",n ...

I am using gcc 4.2.1 compiler(CodeBlocks IDE ) on windows platform . Why I am getting a compile error inspite of the fact that size of long long data type is 8 bytes .




#include <stdio.h>
int main()
{
printf("%d\n",sizeof(int));
printf("%d\n",sizeof(long int));
printf("%d\n",sizeof(long long ...

I cannot understand why I am getting WA ... Plz help me


#include<stdio.h>
long long int a ,b;
void convert(int *num,int *digits,long long int n)
{
int i;
*digits=0;
while(n>0)
{
num[*digits]=(int)(n%10);
n=n/10;
(*digits)++;
}
for(i=*digits;i<11;i++)
num[i]=0;
}
void find()
{
int ...