Ok, I have done everything that I have been told, but I still get WA and I can't make it on my own.
I think that it works correctly to any input but I'm not so sure about the output.
I would really appreciate if any one can help me and run my code just to check if the way I do the output is ...
Search found 7 matches
- Mon Mar 14, 2005 8:22 am
- Forum: Volume 7 (700-799)
- Topic: 765 - References
- Replies: 7
- Views: 4902
- Sat Mar 12, 2005 2:20 pm
- Forum: Volume 7 (700-799)
- Topic: 765 - References
- Replies: 7
- Views: 4902
- Fri Mar 11, 2005 8:53 pm
- Forum: Volume 7 (700-799)
- Topic: 765 - References
- Replies: 7
- Views: 4902
- Fri Mar 11, 2005 8:11 pm
- Forum: Volume 7 (700-799)
- Topic: 765 - References
- Replies: 7
- Views: 4902
765 - References
It's a problem that you have to do what it says to do, but i'm always getting WA and I have tried all the sample inputs that are on ACM North-Eastern European Regional Contest page.
Now here are some questions I have:
Do we have to use files?
If it says up to 40000 lines do we have to implement ...
Now here are some questions I have:
Do we have to use files?
If it says up to 40000 lines do we have to implement ...
- Mon Mar 07, 2005 9:18 pm
- Forum: Algorithms
- Topic: Interesting-Chinese postman problem
- Replies: 5
- Views: 2349
- Mon Mar 07, 2005 5:55 pm
- Forum: Algorithms
- Topic: Interesting-Chinese postman problem
- Replies: 5
- Views: 2349
- Sun Mar 06, 2005 10:12 pm
- Forum: Algorithms
- Topic: Interesting-Chinese postman problem
- Replies: 5
- Views: 2349
Interesting-Chinese postman problem
hi,
i'm new in this "programming world" and i need help on basic graph algorithms, specialy on the basic problem: Chinese postman problem. It consist on calculating the minimum cost for traveling from one vertex going trough all the edges and returning back to the initial vertex.
The solution is ...
i'm new in this "programming world" and i need help on basic graph algorithms, specialy on the basic problem: Chinese postman problem. It consist on calculating the minimum cost for traveling from one vertex going trough all the edges and returning back to the initial vertex.
The solution is ...