I have found the mistake !!!
If the input is :
5
6
7
8
9
12
5
10
22
3
4
12
0
My AC program's output is :
5! = 3 1 1
6! = 4 2 1
7! = 4 2 1 1
8! = 7 2 1 1
9! = 7 4 1 1
12! = 10 5 2 1 1
5! = 3 1 1
10! = 8 4 2 1
22! = 19 9 4 3 2 1 1 1
3! = 1 1
4! = 3 1
12! = 10 5 2 1 1
But ur's ...
Search found 2 matches
- Sat Jan 01, 2005 9:09 am
- Forum: Volume 1 (100-199)
- Topic: 160 - Factors and Factorials
- Replies: 205
- Views: 45151
- Fri Dec 31, 2004 6:19 pm
- Forum: Volume 1 (100-199)
- Topic: 160 - Factors and Factorials
- Replies: 205
- Views: 45151
I run ur program on my PC, I found that ur program can't output the answer, and I also think the solution to the problem is very easy ---- just
creat a prime list ---- prime[num_prime] and define an integer array to record the num ---- sum[num_prime], then do as the following things:
int point = 0 ...
creat a prime list ---- prime[num_prime] and define an integer array to record the num ---- sum[num_prime], then do as the following things:
int point = 0 ...