Got someone's help and got accept.
When indeg(v)==outdeg(v) and degree(v) is even the euler circuit exist, but it can't be solved by choosing arbitrary edges like the classical ways.
I've just figured it out that a small modification in the classical algorithm would work with a graph that meets ...
Search found 2 matches
- Thu Dec 23, 2004 4:59 am
- Forum: Volume 107 (10700-10799)
- Topic: 10735 - Euler Circuit
- Replies: 14
- Views: 6092
- Sat Oct 30, 2004 8:53 am
- Forum: Volume 107 (10700-10799)
- Topic: 10743 - Blocks on Blocks
- Replies: 20
- Views: 14654