After getting a lot of WA finally i solved... :D
Some instructions to new solver:
1. consider graph as bidirectional
2. need not to visit those vertices's which have no edge. u can ignore those. Exception if r != 0 !!
3. must have to visit all edges (Eulerian cycle)
consider these test cases ...
Search found 4 matches
- Tue Oct 20, 2009 9:15 pm
- Forum: Volume 105 (10500-10599)
- Topic: 10596 - Morning Walk
- Replies: 41
- Views: 21069
- Mon Apr 07, 2008 10:26 pm
- Forum: Volume 102 (10200-10299)
- Topic: 10209 - Is This Integration ?
- Replies: 37
- Views: 15985
10209 equations
for prob 10209
3rd eqn: 2x+y+z=(pi/3 - sqrt(3)/4)a^2
2x+y+z
= ((1/2) * s * a) - ((1/2) * c * (a/2))
= yellow shade of circle
= ((1/2) * a * (2/3) * pi * a) - (.5 * sqrt(3)*r * (r/2))
= ((1/3) * pi * a^2) - (sqrt(3)/4 r^2)
= ((1/3) * pi - sqrt(3)/4) * a^2
3rd eqn: 2x+y+z=(pi/3 - sqrt(3)/4)a^2
2x+y+z
= ((1/2) * s * a) - ((1/2) * c * (a/2))
= yellow shade of circle
= ((1/2) * a * (2/3) * pi * a) - (.5 * sqrt(3)*r * (r/2))
= ((1/3) * pi * a^2) - (sqrt(3)/4 r^2)
= ((1/3) * pi - sqrt(3)/4) * a^2
- Fri May 18, 2007 9:17 pm
- Forum: Volume 1 (100-199)
- Topic: 190 - Circle Through Three Points
- Replies: 126
- Views: 37547
please help!!P.E in 190....
will any one please tell me why it is giving P.E?
#include<stdio.h>
int strlen(char str[])
{
int i;
for(i=0;str[i]!=NULL;i++);
return i;
}
void main()
{
int i=0,n,k,j,mxm=0;
char str1[200][200],str2[200][200];
while(gets(str1[i]))
{
k=strlen(str1[i]);
if(k>mxm)
mxm=k;
i++;
}
for ...
#include<stdio.h>
int strlen(char str[])
{
int i;
for(i=0;str[i]!=NULL;i++);
return i;
}
void main()
{
int i=0,n,k,j,mxm=0;
char str1[200][200],str2[200][200];
while(gets(str1[i]))
{
k=strlen(str1[i]);
if(k>mxm)
mxm=k;
i++;
}
for ...
- Fri May 18, 2007 9:07 pm
- Forum: Volume 1 (100-199)
- Topic: 192 - Synchronous Design
- Replies: 11
- Views: 4983
please Help me...output limit exceed in prob 192
can any one tell me what is the problem with my code? why it is showing output limit exceed? :evil:
[/code]
#include<stdio.h>
void main()
{
char ch,str1[2000000];
long int i;
while(scanf(" %[^\n]",str1)==1)
{
for(i=0;str1 !=NULL;i++)
{
if(str1 =='a' || str1 =='A' || str1 =='e'|| str1 =='E ...
[/code]
#include<stdio.h>
void main()
{
char ch,str1[2000000];
long int i;
while(scanf(" %[^\n]",str1)==1)
{
for(i=0;str1 !=NULL;i++)
{
if(str1 =='a' || str1 =='A' || str1 =='e'|| str1 =='E ...