OJ Board

well you only need to generate primes up to sqrt(1000000000).
why ? try to think abt it.you will find it by yourself.
best of luck.

Good to see that you got AC.Hope you will get AC for problem 526.Best of luck

try with this. in: himynameishihaho himynameishohiha associationforcomputingmachinary associationforcomputingmathematics urreallyaniceguy yesiam wowthisisagoodprogram goodprogramthisisindeed # out: Co12Ci14Ca16E Ct26Ce28Cm29It31Ii32Cc33Cs34E Du1Dr1Dr1De1Da1Dl1Dl1Ce2Cs3Dc5De5Dg5Ca5Cm6E Cg1Co3Cd4Cp5Cr...

try to maintain

insert first , then replace and finally delete.

that is the order should be ICD

very complex implementation of BFS indeed. you have used adjacency list. while(v && e) { j=0; while(p[v].paths[j]>=0)j++; p[v].paths[j]=e; scanf("%d %d",&v,&e); } for the colored part you can use another counter array.it will reduce the time. set max=-1; for( j=0 ;j<=N;j++) { if(p[j].dis>max) { max=...

3 3 2 1 3 1 2 for ur input the graph matrix would be 1 2 3 4 5 6 1 0 - - - - - 2 - 0 - - - - 3 2 1 0 - - - 4 - - - 0 - - 5 - - - - 0 - 6 - - - - - 0 here '-' stands for infinity. the matrix need to be 6*6 atleast.as u want to find a rally point from which the fr five positions are in unidistance. as...

output:

-1

i hope you have change ur datatype to unsigned long or long long or __int64. consider the case 2147483647 2147483647 then you can get overflow. coz 2147483647*3+1 is out of range of int(long) indeed. input can be 12 10 so swap them and thus you can avoid tle. remember the word "between" all the time...

consider the fact that the farthest point from the desired point can be the shortest distance from the first 5 five points. example. 1 6 10 2 6 10 3 6 10 4 6 10 5 6 10 since the distance from the fr five(1,2,3,4,5) points to 6 are same that is 10, so 6 is a candidate.Again the farthest point(among t...

here is the greedy one. 1.sort the team based on number of members in decreasing order 2.then assign team members of a team to each table considering the capacity limit of each table. and do same for the next team.... 3.if a member of one team can't be assigned to any table due to table capacity try...

Wow you got the 1st place.Good job done.Congrates....

I agree with you.Its annoying but sometimes we need to make a solution for some wrong cases.

I have check the above input using Vcc and they were the same as little joy. Thanks little joy for pointing out the fact. Hope the following are correct. 52 6 349 2 818 12 63 13 983 8 356 9 419 12 167 6 291 10 165 1 181 3 808 6 142 10 878 12 750 13 373 13 175 8 981 2 70 10 8 4 392 11 835 3 198 3 74 ...

sorry i haven't judge the outputs carefully.But this has been genrated from my A.C. solution.Long time ago Adrian also pointed out the fact.May
be it is becoz of the borland compiler i used.Strange but true.I should try with my Vcc compiler.
Silverfox03 your output is correct.

I forgot the critical cases.I generated some inputs.Try with this. Input 346 10 972 10 645 7 578 10 926 1 996 8 568 4 474 10 407 6 441 12 92 1 183 5 183 14 222 6 765 1 660 1 978 13 731 5 976 5 546 12 471 8 438 9 887 3 744 9 622 1 407 10 770 7 93 6 335 7 755 4 584 13 657 6 377 3 552 9 174 13 53 4 283...