OJ Board

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
char s[100000], t[100000];
long int m, n, i, j, D=0;
while( scanf("%s %s",&s,&t) == 2 )
{
m = strlen(s);
n = strlen(t);

D = 0;


i = 0;
for(j=0;j<m;j++)
{
while(i < n)
{
if(s[j] == t[i])
{
s[j ...

Oh~I got it.
Thank you!!!

[quote="sohel"][quote="Waddle"]why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?[/quote]

What makes you think [10 1 2 3 4 5 6 7 8 9 10] is Jolly?[/quote]
10-9=1
9-8=1
8-7=1
7-6=1
6-5=1
5-4=1
4-3=1
3-2=1
2-1=1
1 <= All of them <= n-1 = 9

why the third case " 10 1 2 3 4 5 6 7 8 9 10" Not jolly ?[/quote]

[quote="chunyi81"]My AC program has a slightly different output than the one above.

My AC program outputs:
[code]
Jolly
Not jolly
Not jolly
Jolly
Jolly
Not jolly
Jolly
Jolly
Jolly
Not jolly
Not jolly
Jolly
Jolly
Not jolly
Jolly
Not jolly
Jolly
[/code]

As for which one is correct, it all comes down ...

[code]#include <string.h>
#include <stdio.h>
#include <stdlib.h>

int lcs( int[], int[]);
int len[101][101];
int lenth ,n_1, n_2, i, j;

int main()
{
int str1[101] ;
int str2[101] ;
int p = 0;
while(1)
{
p++;

scanf("%d %d",&n_1,&n_2);

if(n_1 == 0 && n_2 == 0)
break;

for(i=0;i<n_1 ...

Give me more cases.
I need more cases. \=皿=/

does the output always be positive

I GOT AC~~~
thanks everybody~

I still got PE
I almost gave up.
I think i have a blank line at the end of the last triangle.
Did you see my output ?

The Last:
1\n
22\n
333\n
22\n
1\n
\n --->you mean this,right?

Thank you.

Like this?

\n
1\n
22\n
333\n
22\n
1\n
\n

MY INPUT:
2

3
2

4
3


MY OUTPUT:
1\n
22\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
4444\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
4444\n
333\n
22\n
1\n
\n
1\n
22\n
333\n
4444\n
333\n
22\n
1\n
\n

I'm sorry that I can only understand C.
But I thought getting a PE has no concern with thread.

The code has been removed.

#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main()
{
int i,n,m;
char sl[40];


while(gets(sl))
{
n=0;
i=0;
if(isalpha(sl[0]) != 0)
i++;
while(sl[n] != '\0')
{


if(isalpha(sl[n+1]) != 0 && sl[n] == ' ')
i++ ;

if(n != 0 && isalpha(sl[n]) != 0 && isalpha(sl ...