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m2lajoo

this is my AC code try to understand before sending it.

m2lajoo

You didn't understand the problem well
it is not EOF It has test cases
for example:
input:
1
3
2
output:

1
22
333
22
1

1
22
333
22
1
yor code doesn't go out of program but it should.
sorry for my bad english.
#include<smile.h>
regards

m2lajoo

It doesn't matter to me.
but however the right code is

Code: Select all

#include<stdio.h>
#define m2lajoo 0 
int main()
{
while (1) 
{
printf("m2lajoo is the winner");
}
return m2lajoo;
}

m2lajoo

Ok, you are right:

Code: Select all

while (1) 
{
printf("m2lajoo is the winner\n newton is simply a loser");
}
 :D  :D  :wink:

m2lajoo

I'm 14 and 1 solved 115 problems

m2lajoo

{
while (1) do
{
cout<<"m2lajoo is winner";
}
return m2lajoo

}

m2lajoo

No one want to deal with me

m2lajoo

I AM THE WINNER

m2lajoo

help me! why my program say presentation error :cry: var m,n:byte; test:integer; house:array[1..100,1..100]of char; st:string; khane:array[1..100,1..100]of (mine,clear); h:array[1..100,1..100]of byte; i,j:integer; function shownumber(num1,num2:integer):integer; var x,y,tedad:integer; begin tedad:=0;...

m2lajoo

can you help me with this code?i don't know why it' WA var a,b:longint; function tedad(a,b:integer):integer; begin if (a=1)and(b=1) then begin tedad:=0; exit; end; if (a=1) then tedad:=b-1; if (b=1) then tedad:=a-1; if (a<>1)and(b<>1) then tedad:=(a-1)+tedad(1,b)*b; end; begin while not eof(input) d...

m2lajoo

hi please help me my problem is good in my computer but it got TLE here is mycode: type st100=array[1..100]of string; arr100=array[1..100]of integer; var test:integer; counter:integer; j,i,tedad,len:integer; strings,strings2:st100; number:arr100; function translate_number(st:string):string; var i:in...

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