UVa OJ Board

m2lajoo

this is my AC code try to understand before sending it.

m2lajoo

You didn't understand the problem well
it is not EOF It has test cases
for example:
input:
1
3
2
output:

1
22
333
22
1

1
22
333
22
1
yor code doesn't go out of program but it should.
sorry for my bad english.
#include<smile.h>
regards

m2lajoo

It doesn't matter to me.
but however the right code is

Code: Select all

#include<stdio.h>
#define m2lajoo 0 
int main()
{
while (1) 
{
printf("m2lajoo is the winner");
}
return m2lajoo;
}

m2lajoo

Ok, you are right:

Code: Select all

while (1) 
{
printf("m2lajoo is the winner\n newton is simply a loser");
}
 :D  :D  :wink:

m2lajoo

I'm 14 and 1 solved 115 problems

m2lajoo

{
while (1) do
{
cout<<"m2lajoo is winner";
}
return m2lajoo

}

m2lajoo

No one want to deal with me

m2lajoo

I AM THE WINNER

m2lajoo

help me! why my program say presentation error :cry: var m,n:byte; test:integer; house:array[1..100,1..100]of char; st:string; khane:array[1..100,1..100]of (mine,clear); h:array[1..100,1..100]of byte; i,j:integer; function shownumber(num1,num2:integer):integer; var x,y,tedad:integer; begin tedad:=0;...

m2lajoo

can you help me with this code?i don't know why it' WA var a,b:longint; function tedad(a,b:integer):integer; begin if (a=1)and(b=1) then begin tedad:=0; exit; end; if (a=1) then tedad:=b-1; if (b=1) then tedad:=a-1; if (a<>1)and(b<>1) then tedad:=(a-1)+tedad(1,b)*b; end; begin while not eof(input) d...

m2lajoo

hi please help me my problem is good in my computer but it got TLE here is mycode: type st100=array[1..100]of string; arr100=array[1..100]of integer; var test:integer; counter:integer; j,i,tedad,len:integer; strings,strings2:st100; number:arr100; function translate_number(st:string):string; var i:in...

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