OJ Board

m2lajoo

this is my AC code try to understand before sending it.

m2lajoo

You didn't understand the problem well
it is not EOF It has test cases
for example:
input:
1
3
2
output:

1
22
333
22
1

1
22
333
22
1
yor code doesn't go out of program but it should.
sorry for my bad english.
#include<smile.h>
regards

m2lajoo

It doesn't matter to me.
but however the right code is

Code: Select all

#include<stdio.h>
#define m2lajoo 0 
int main()
{
while (1) 
{
printf("m2lajoo is the winner");
}
return m2lajoo;
}

m2lajoo

Ok, you are right:

Code: Select all

while (1) 
{
printf("m2lajoo is the winner\n newton is simply a loser");
}
 :D  :D  :wink:

m2lajoo

I'm 14 and 1 solved 115 problems

m2lajoo

{
while (1) do
{
cout<<"m2lajoo is winner";
}
return m2lajoo

}

m2lajoo

No one want to deal with me

m2lajoo

I AM THE WINNER

m2lajoo

help me! why my program say presentation error :cry:

var
m,n:byte;
test:integer;
house:array[1..100,1..100]of char;
st:string;
khane:array[1..100,1..100]of (mine,clear);
h:array[1..100,1..100]of byte;
i,j:integer;
function shownumber(num1,num2:integer):integer;
var
x,y,tedad:integer;
begin
tedad ...

m2lajoo

can you help me with this code?i don't know why it' WA

var
a,b:longint;
function tedad(a,b:integer):integer;
begin
if (a=1)and(b=1) then
begin
tedad:=0;
exit;
end;
if (a=1) then
tedad:=b-1;
if (b=1) then
tedad:=a-1;
if (a<>1)and(b<>1) then
tedad:=(a-1)+tedad(1,b)*b;
end;
begin
while not eof(input ...

m2lajoo

hi please help me my problem is good in my computer but it got TLE
here is mycode:

type
st100=array[1..100]of string;
arr100=array[1..100]of integer;
var
test:integer;
counter:integer;
j,i,tedad,len:integer;
strings,strings2:st100;
number:arr100;
function translate_number(st:string):string;
var ...

OJ Board

Search found 11 matches

10189:how to present

10970 - Big Chocolate

612 TLE