UVa OJ Board

I got the following output: I was talking to crip121 and maybe my calculated number of iterations is wrong. I had a bad time trying to get AC on this, and i tried many ways to find the number of months.

crip121 wrote:what is the output for following input

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1
460 2 1
20
A B
B C
C D
D E
E F
F G
G H
H I
I J
J K
K L
L M
M N
N O
O P
P Q
Q R
R S
S T
T U
A U

i WA code gives

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0.03419

My AC code gives 0.03127.

This gives runtime error, so this problem has no test data.

fR0D wrote:here's my code
can sum1 help

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REMOVED

I don't know if your expressions are right, but you'd better use double instead of float for real type.

In this situation, you just count the number of nested loops.

If you want to learn more, read this:

http://www.topcoder.com/tc?module=Stati ... omplexity1

Since there are codes for this problem on the board, I guess I'm not giving too much with this post, so these are the areas I used to find the formulas.

http://www.ee.furg.br/~thiago/10209.jpg

adelar wrote:Hi,
this input is possible?

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......
.***..
......
....*.
....*.
....*. 

thanks in advance.

No gaps allowed.

I know how it works. My question is if the new system requires the "return 0", since the current one doesn't.

But thank you anyway.

At Waterloo's contest, I submitted 3 problems and all of them got RE. I had no idea why that was happening, so I just waited the problems to be available on the OJ and submitted again, and 2 got AC and the other WA, so here is my question... Did this happen because I didn't put a *return 0;* on the ...

Try these:

Using your notation: 456 - 1st instruction 789 - 2nd instruction 234 - 3rd instruction 453 - 4th instruction 125 - 5th instruction (halt) 175(skip) 183(skip) 256(skip) 012(skip) 100(skip) That's why i'm telling you, this input is wrong. You don't need to verify if the instruction is valid. In my pro...

It doesn't even get passed the 125, it stops right there and just skips the following lines.

If you want to make sure the other two digits are zeroes I guess you won't have any problems, since 125 isn't supposed to appear anyway... Keep in mind that this input is wrong according to the description.

Actually, my program stops when 125 is reached. It is the halt instruction, so the program finishes there, and the subsequent lines should be ignored. This way we have 5 instructions executed, including the 125. Why does your program stop when 125 is reached tgoulart? Isn't 100 mean to be the halt ...

Actually, it is possible to get AC with a brute force method, but you must use a simpler way to see if the point is in the triangle. This one above is too slow.

Besides the TLE, your code gives wrong answer for the data in this thread:

http://online-judge.uva.es/board/viewtopic.php?t=7805