OJ Board

I am getting wrong answer but I think I handled all the test cases correctly. Here is my code:

//
// soundex.cpp
//
//
// Created by iOS Development on 7/10/15.
//
//

#include <iostream>
#include <map>
#define c cin
#define o cout
#define el endl
using namespace std;

map<char,char> l;
void sets ...

#include <bits/stdc++.h>
#define ll long long int
using namespace std;

inline void fastRead_int(ll &x) {
register ll c = getchar();
x = 0;
ll neg = 0;
for(; ((c<48 || c>57) && c != '-'); c = getchar());
if(c=='-') {
neg = 1;
c = getchar();
}
for(; c>47 && c<58 ; c = getchar()) {
x = (x ...

still getting WA. What could be the problem?
Try running your code at least once and consider looking at it objectively. This thread has some test cases. Check your code output against what's available on the forums.

So, you're no longer printing two lines at the end of the output but what do you ...

95.123 12
548815620517731830194541.899025343415715973535967221869852721
0.4321 20
0.00000005148554641076956121994511276767154838481760200726351203835429763013462401
5.1234 15
43992025569.928573701266488041146654993318703707511666295476720493953024
6.7592 9
29448126 ...

You'll need to program a bigint mod function - search the web for examples. Or you could use Java's bigInteger.


import java.math.*;
import java.util.*;

class Main{
public static void main(String[] args){
Scanner cin = new Scanner(System.in);
BigInteger n;
while(cin.hasNext()){
n = cin ...

You're printing two blank lines at the end of the output.


#include <iostream>
#include <cstring>
using namespace std;

int main(){
long long n,m,c;
int x=1;
while(cin >> n >> m >> c){
if(n==0 && m==0 && c==0){ break; }
long long amp[n], op[m];
bool swtch[n];
memset(swtch, false, sizeof ...

#include <iostream>
#include <algorithm>
using namespace std;

int main(){
int s;
while(cin >> s){
if(s == 0) break;
int station[s];
bool conse = true;
for(int i = 0; i < s; i++) cin >> station[i];
sort(station, station+s);
for(int i = 0; i < s-1; i++){
if(abs(station[i]-station[i+1 ...

So I will create a char, say char num[1000000], but here's the question:

How will I be able to convert every character to an integer so that i could check it if it is leap year or huluculu or bulukulu. Sorry. I'm still a newbie programmer.

#include <iostream>
using namespace std;

int main(){
long long year;
while(cin >> year){
bool leap = false, huluculu = false, bulukulu = false;
if(year%4 == 0 && year%400 == 0) leap = true;
else if(year%100 == 0) leap = false;
if(year%15 == 0) huluculu = true;
if(year%55 == 0 && leap ...

#include <iostream>
#include <cstring>
using namespace std;

int main(){
long long n,m,c;
int x=1;
while(cin >> n >> m >> c){
if(n==0 && m==0 && c==0){ cout << endl; break; }
long long amp[n], op[m];
bool swtch[n];
memset(swtch, false, sizeof(swtch));
for(int i = 1; i <= n; i++) cin >> amp ...