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Hi Red Scorpion thanks for ur replay .. I got Ac atlast ... But the problem was not there....My program give same out put for your given sample input.
Thanks to all and thank you again my frined.

#include<stdio.h> #include<stdlib.h> #include<string.h> void main() { char in[12],in1[12]; long i,k,n,num1,num2,c; while(scanf("%ld",&n)!=EOF) { for(k=0;k<n;k++) { scanf("%s",in); strcpy(in1,in); int len=strlen(in),j=0; for (i=len-1;i>=0;i--) { in1[j]=in ; j++; } c=0; { do{ c++; num1=atol(in); num2=...

At the time of regug its giving WA ....Whats wrong with my program..do u know? #include<stdio.h> #include<stdlib.h> #include<string.h> void main() { char in[12],in1[12]; long i,k,n,num1,num2,c; while(scanf("%ld",&n)!=EOF) { for(k=0;k<n;k++) { scanf("%s",in); strcpy(in1,in); int len=strlen(in),j=0; f...

See preveas post about this problem u will get AC like me
Test for given input ...... in preveas post about this problem

Good luck

Thanks for replay.......for case 2 my program print also...there was not the problem...I got AC but still Presentation Error.... i am not geting whats the wrong in my out put....Thanks all....

Whats the wrong with my code? Why WA? Do u know? #include<stdio.h> #include<string.h> void process(char string[]) { int len,i; len=strlen(string); if(len==7) { if(string[0]=='0') { if(string[1]!='0') printf("%c lakh ",string[1]); } else printf("%c%c lakh ",string[0],string[1]); if(string[2]=='0') { ...

HI Astrakan Thanks for riplay.. i got accept....but :-? PA i use int main() { const long int x=1000000; int *a,*b,n,m,l,temp; a=new int[x]; b=new int[x]; Code...... ........... delete a,b; return 0; } So at the end of output file my program write a extra line "Null pointer assignment" Do u can help!...

Output for all given data its ok...

and also...

For input:-
1
5
5 0
8 1
8 0
1 1
1 1

1
4
0 9
0 9
0 9
1 9


Oput put is :--
59822

99100


And i am geting WA Do u know whats the problem ?Help me

----------INPUT----------
1.0
2.00
3.000
4.01
5.001
6.1000000000
7.100000000000000
----------OUTPUT--------
1. 0
2.
3.
4. 1
5. 1
6. 1 shata kuti
7. 1 kuti kuti

So whats the warng with my program [/b]